有人能向一个完全的初学者解释这个java练习的输出吗？

我是Java新手，我试图理解以下代码的逻辑。谁能给我解释一下怎么做

y = x - y;

给出输出

0 0 1 2 1 3 2 4 2

class MyFirstApp {

    public static void main(String [] args) {
        int x = 0;
        int y = 0;
        while ( x < 5 ) {
            y = x - y;
            System.out.print(x + " " + y + " ");
            x = x + 1;
        }
    }
}    

类MyFirstApp{
公共静态void main（字符串[]args）{
int x=0；
int y=0；
而（x<5）{
y=x-y；
系统输出打印（x+“”+y+“”）；
x=x+1；
}
}
}    
while（x<5）{
y=x-y；
系统输出打印（x+“”+y+“”）；
x=x+1；
}

当
x=0
时，将执行此循环直到
x>=5
，并且在每次迭代中，将打印
x
和
y
的值。您注意到，在每次迭代结束时，变量
x
将递增。因此，循环将执行5次

屈服：
第一次迭代：x=0，y=x-y=0-0=0，因此显示
0 0
。
在第二次迭代中，x=1，y=x-y=1-0=1，因此打印
11
等等
你必须拿出纸和笔/铅笔来学习编码杜德的逻辑工作原理。不过这次我会帮你，让你开始

第一次通过

x = 0   y = 0
y = x - y = 0 - 0 = 0
x = x + 1 = 0 + 1 = 1

x = 1   y = 0
y = x - y = 1 - 0 = 1
x = x + 1 = 1 + 1 = 2

x = 2   y = 1
y = x - y = 2 - 1 = 1
x = x + 1 = 2 + 1 = 3

x = 3   y = 1
y = x - y = 3 - 1 = 2
x = x + 1 = 3 + 1 = 4

x = 4   y = 2
y = x - y = 4 - 2 = 2
x = x + 1 = 4 + 1 = 5

第二次通过

x = 0   y = 0
y = x - y = 0 - 0 = 0
x = x + 1 = 0 + 1 = 1

x = 1   y = 0
y = x - y = 1 - 0 = 1
x = x + 1 = 1 + 1 = 2

x = 2   y = 1
y = x - y = 2 - 1 = 1
x = x + 1 = 2 + 1 = 3

x = 3   y = 1
y = x - y = 3 - 1 = 2
x = x + 1 = 3 + 1 = 4

x = 4   y = 2
y = x - y = 4 - 2 = 2
x = x + 1 = 4 + 1 = 5

第三次通过

x = 0   y = 0
y = x - y = 0 - 0 = 0
x = x + 1 = 0 + 1 = 1

x = 1   y = 0
y = x - y = 1 - 0 = 1
x = x + 1 = 1 + 1 = 2

x = 2   y = 1
y = x - y = 2 - 1 = 1
x = x + 1 = 2 + 1 = 3

x = 3   y = 1
y = x - y = 3 - 1 = 2
x = x + 1 = 3 + 1 = 4

x = 4   y = 2
y = x - y = 4 - 2 = 2
x = x + 1 = 4 + 1 = 5

第四次通过

x = 0   y = 0
y = x - y = 0 - 0 = 0
x = x + 1 = 0 + 1 = 1

x = 1   y = 0
y = x - y = 1 - 0 = 1
x = x + 1 = 1 + 1 = 2

x = 2   y = 1
y = x - y = 2 - 1 = 1
x = x + 1 = 2 + 1 = 3

x = 3   y = 1
y = x - y = 3 - 1 = 2
x = x + 1 = 3 + 1 = 4

x = 4   y = 2
y = x - y = 4 - 2 = 2
x = x + 1 = 4 + 1 = 5

最后一次通过

x = 0   y = 0
y = x - y = 0 - 0 = 0
x = x + 1 = 0 + 1 = 1

x = 1   y = 0
y = x - y = 1 - 0 = 1
x = x + 1 = 1 + 1 = 2

x = 2   y = 1
y = x - y = 2 - 1 = 1
x = x + 1 = 2 + 1 = 3

x = 3   y = 1
y = x - y = 3 - 1 = 2
x = x + 1 = 3 + 1 = 4

x = 4   y = 2
y = x - y = 4 - 2 = 2
x = x + 1 = 4 + 1 = 5

在我看来，通过这样的逻辑是了解它在代码中如何工作的最好方法
调试它怎么样？@SURESH ATTA-我不确定这篇文章是否特别合适（因为它看起来像是家庭作业，并且没有显示他自己做了什么来尝试解决它）。不过，我怀疑“完全初学者”是否能够调试。感谢ShadowManes的反馈，因为它向我展示了输出是如何工作的。谢谢，没问题。任何时候你对输出有疑问，只要拿出纸和笔，然后像写在代码中一样完成每一步。这样你会学到很多，作为一个初学者，这是一件很棒的事情。祝你好运