Java JPanel不显示组件?(六边形网格)
对不起,我是java的初学者。我以前做过一个正方形格子,用于跳棋游戏,但是我在六边形格子上遇到了麻烦。我遵循同样的想法,使用正方形网格,但是,我的JPanel上有小点,虽然我不确定这是什么原因,但我环顾四周,试图找出可能的错误 GameBoard.java;负责绘制六边形Java JPanel不显示组件?(六边形网格),java,hexagonal-tiles,Java,Hexagonal Tiles,对不起,我是java的初学者。我以前做过一个正方形格子,用于跳棋游戏,但是我在六边形格子上遇到了麻烦。我遵循同样的想法,使用正方形网格,但是,我的JPanel上有小点,虽然我不确定这是什么原因,但我环顾四周,试图找出可能的错误 GameBoard.java;负责绘制六边形 import java.awt.Color; import java.awt.GridLayout; import java.awt.Point; import java.awt.event.ActionEvent; impo
import java.awt.Color;
import java.awt.GridLayout;
import java.awt.Point;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.event.MouseAdapter;
import java.awt.event.MouseEvent;
import java.util.Collections;
import javax.swing.JButton;
import javax.swing.JOptionPane;
import javax.swing.JPanel;
//import CheckerBoard.GameSquareMouseListener;
public class GameBoard extends JPanel {
protected final static int size = 8;
protected final static int radius = 50;
protected final static int padding = 5;
private Position oldPosition = null;
public GameBoard(){
super ();
int numPieceSpots = 0;
int x = 0; int y = 0;
int xOff = (int) Math.cos(Math.toRadians(30)) * (radius + padding);
int yOff = (int) Math.sin(Math.toRadians(30)) * (radius + padding);
int half = size / 2;
GameHexagon hex = null;
for (int r = 0; r < size; r++){
for (int c = 0; c < size; c++)
{
if (((r + c) % 2 == 0) && (r % 2 == 1)){
hex = new GameHexagon(r, c, x, y);
}
else if (((r + c) % 2 == 0) && (r % 2 == 0))
{
hex = new GameHexagon(r, c, x, y);
}
else {
hex = new GameHexagon(r, c, x, y);
}
if (c == (size - 1)){
x = 0;
y += yOff;
}
add (hex);
x += xOff*c;
}
}
repaint();
}
}
Hexagon.java;负责绘制六边形
这段代码是我从stackoverflow上的一个程序员那里得到的,我做了一些小的编辑,我自己也试过了,它成功了,但是,我浏览了一遍,不确定是什么错了,或者为什么它与我正在做的不兼容
import java.awt.*;
import java.awt.image.BufferedImage;
import java.io.File;
import java.io.IOException;
import javax.imageio.ImageIO;
public class Hexagon extends Polygon {
private static final long serialVersionUID = 1L;
public static final int SIDES = 6;
private Point[] points = new Point[SIDES];
private Point center = new Point(0, 0);
private int radius;
private int rotation = 90;
public Hexagon(Point center, int xlabel, int ylabel, int radius) {
npoints = SIDES;
xpoints = new int[SIDES];
ypoints = new int[SIDES];
this.center = center;
this.radius = radius;
updatePoints();
}
public Hexagon(int x, int y, int xlabel, int ylabel, int radius) {
this(new Point(x, y), xlabel, ylabel, radius);
}
public int getRadius() {
return radius;
}
public void setRadius(int radius) {
this.radius = radius;
updatePoints();
}
public int getRotation() {
return rotation;
}
public void setRotation(int rotation) {
this.rotation = rotation;
updatePoints();
}
public void setCenter(Point center) {
this.center = center;
updatePoints();
}
public void setCenter(int x, int y) {
setCenter(new Point(x, y));
}
private double findAngle(double fraction) {
return fraction * Math.PI * 2 + Math.toRadians((rotation + 180) % 360);
}
private Point findPoint(double angle) {
int x = (int) (center.x + Math.cos(angle) * radius);
int y = (int) (center.y + Math.sin(angle) * radius);
return new Point(x, y);
}
protected void updatePoints() {
for (int p = 0; p < SIDES; p++) {
double angle = findAngle((double) p / SIDES);
Point point = findPoint(angle);
xpoints[p] = point.x;
ypoints[p] = point.y;
points[p] = point;
}
}
public void draw(Graphics2D g, int x, int y, int lineThickness, boolean border) {
// Store before changing.
Stroke tmpS = g.getStroke();
Color tmpC = g.getColor();
g.setStroke(new BasicStroke(lineThickness, BasicStroke.CAP_SQUARE, BasicStroke.JOIN_MITER));
if (border)
g.fillPolygon(xpoints, ypoints, npoints);
else
g.drawPolygon(xpoints, ypoints, npoints);
// Set values to previous when done.
g.setColor(tmpC);
g.setStroke(tmpS);
}
}
我可以使用一个正方形网格来布置十六进制图标,但这并没有达到目的,因为我希望网格彼此对齐
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或者类似的东西
在本例中使用了2号
]因此,我注意到您没有使用多边形和
java.awt.*
类中的.fill()
方法。我建议用它来代替。这里有几个网站链接,可以帮助使用多边形方法
希望这是有用的 添加了
g2.fill(bkgnd)
但是相同的点,Hexagon.java是多边形的子对象,它不应该继承吗?是的,我没有想到,我会更仔细地阅读你的代码。这个问题已经被问过了。下面是答案的链接:我已经看过了。这就是我获得hexagon.java文件的地方,然而,我正在尝试使用JComponent,以便在游戏中使用六边形网格。考虑到我必须设置边框,引入带有形状的MouseEvent要困难得多,而且我还是新手,所以我仍在尝试获取基础知识。这是完整的代码吗?这就是我使用的所有代码。你有很多严重的缺陷:bkgnd.draw(g2,x,y,2,true);xy在这个方法中没有相关性。。。如果你是一个彻头彻尾的新手,你要对一个复杂的怪物做什么?我自己也不确定,我想我会把它作为一个项目来尝试。我假设一旦我构造了一个GameHexagon(行,列,x,y,true),x和y将被设置。在组件中,它将使用bkgnd.draw(g2,x,y,2,true)绘制。我想我假设基于x和y轴的绘制将更容易绘制组件,因为我不想使用网格
import java.awt.*;
import java.awt.geom.*;
import java.awt.event.*;
import javax.swing.*;
/**
A program that allows users to edit a scene composed
of items.
*/
public class GameTest
{
public static void main(String[] args) {
JFrame f = new JFrame();
GameBoard p = new GameBoard();
f.add (p, BorderLayout.CENTER);
f.setDefaultCloseOperation (JFrame.EXIT_ON_CLOSE);
f.setSize (600, 600);
f.setVisible (true);
}
}
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