是否可以使用Java 8流结构更简洁地表达以下逻辑:
是否可以使用Java 8流结构更简洁地表达以下逻辑:是否可以使用Java 8流结构更简洁地表达以下逻辑:,java,java-8,java-stream,Java,Java 8,Java Stream,是否可以使用Java 8流结构更简洁地表达以下逻辑: int[] gameState = {2, 2, 2, 2, 2, 2, 2, 2, 2}; int[][] winningPositions = {{0, 1, 2}, {3, 4, 5}, {6, 7, 8}, {0, 3, 6},
int[] gameState = {2, 2, 2, 2, 2, 2, 2, 2, 2};
int[][] winningPositions = {{0, 1, 2}, {3, 4, 5}, {6, 7, 8}, {0, 3, 6},
{1, 4, 7}, {2, 5, 8}, {0, 4, 8}, {2, 4, 6}};
for (int[] winningPosition : winningPositions) {
System.out.println("RST " + gameState[winningPosition[0]] );
if (gameState[winningPosition[0]] == gameState[winningPosition[1]]
&& gameState[winningPosition[1]] == gameState[winningPosition[2]]
&& gameState[winningPosition[0]] != 2) {
// Somone has won!
gameActive = false;
String winner = "";
if (activePlayer == 1) {
winner = "Yellow";
} else {
winner = "Red";
}
}
我想将此代码更改为流 像这样的东西怎么样
Arrays.stream(winningPositions) // Stream<int[][]>
.anyMatch(win -> // win is an int[] array
gameState[win[0]] == gameState[win[1]] &&
gameState[win[1]] == gameState[win[2]] &&
gameState[win[0]] != 2
); // anyMatch will stop as soon as match has been found.
Arrays.stream(winningPositions)//stream
.anyMatch(win->//win是一个int[]数组
游戏状态[win[0]]==游戏状态[win[1]]&&
游戏状态[win[1]]==游戏状态[win[2]]&&
游戏状态[赢[0]!=2
); // 一旦找到匹配项,任何匹配项都将停止。
尽管与您最初的方法相比,它可能没有任何真正的优势 数组.stream(winningPositions).filter(e->e[0]==e[1]&&e[0]==e[2]&&e[0]!=2).forEach(e->System.out.println(e[0]+“”+e[1]+“”+e[2]);我需要另一只鹦鹉///有人赢了!gameActive=false;字符串赢家=”;如果(activePlayer==1){winner=“Yellow”}其他{winner=“Red”}我使用了filter,filter和anymatch有什么不同