Java MySQLSyntaxErrorException尽管一切看起来都很好（Hibernate）

我有一个项目实体和一个集团实体。我可以使用以下getter方法从DAO按名称获取项目：

public Project getProject(String name){
    Project project = null;

    DetachedCriteria criteria = DetachedCriteria.forClass(Project.class);
    criteria.add(Restrictions.eq("name", name));
    List<Project> projects = getHibernateTemplate().findByCriteria(criteria);
    if ((projects != null) && (projects.size() > 0)) {
        project = (Project)projects.get(0);
    }
    return project;
}

不起作用的是：

@Entity
@Table(name = "project")
public class Project implements Serializable {

private static final long serialVersionUID = 1L;

@Transient
public static final String REF = "Project";

@ManyToMany(targetEntity = pl.edu.agh.adam.core.projects.hibernate.Tag.class)
@JoinTable(name = "project_tag", joinColumns = @JoinColumn(name = "project_id"), inverseJoinColumns = @JoinColumn(name = "tag_id"))
private List<Tag> tags;

@ManyToMany(targetEntity = pl.edu.agh.adam.core.projects.hibernate.Group.class)
@JoinTable(name = "project_group_role",
        joinColumns = @JoinColumn(name = "project_id"),
        inverseJoinColumns = @JoinColumn(name = "group_id"))
private Set<Group> groups;

@ManyToMany(targetEntity = pl.edu.agh.adam.core.projects.hibernate.Role.class)
@JoinTable(name = "project_group_role",
        joinColumns = @JoinColumn(name = "project_id"),
        inverseJoinColumns = @JoinColumn(name = "role_id"))
private Set<Role> roles;


@Transient
public static final String PROP_ID = "id";

@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(name = "project_id")
private Long id;

@Transient
public static final String PROP_NAME = "name";
@Column(name = "name", length = 60, unique = true, nullable = false)
private String name;

@Transient
public static final String PROP_SHORTNAME = "shortname";

@Column(name = "shortname", length = 25, unique = true)
private String shortname;

@Transient
public static final String PROP_HOMEPAGE = "homepage";
@Column(name = "homepage", length = 60)
private String homepage;

@Transient
public static final String PROP_DESCRIPTION = "description";
@Column(name = "description", columnDefinition = "LONGTEXT")
private String description;

  }

select
    this_.group_id as group1_4_0_,
    this_.name as name4_0_,
    this_.password as password4_0_,
    this_.subscribable as subscrib4_4_0_ 
from

group this_ where
    this_.name=?

---

发生了什么事？？：（

我没有立即发现这一点，但

group

是一个保留关键字，因此生成的查询确实不正确。请为

group

实体使用另一个表名。例如：

@Entity
@Table(name = "groups")
public class Group implements Serializable {

    //...
}

---

第二个查询在粘贴到SQL客户端时是否运行？不，它不会运行，这并不令人惊讶，尽管我不能一眼看出它有什么问题。此外，我如何使hibernate生成一个不同的查询？我不希望它工作，但在SQL客户端中“调试”某些内容（删除别名、删除列等）更容易.无论如何，我想我找到了问题所在。如果这不对的话，该死的。除了GROUP BY之外，GROUP还有其他用法吗？如果没有，这个词应该是可用的。当涉及到修改数据库时，我很不情愿，所以我这样做了：

@Table（name=“`GROUP`”）

现在每件事都很有魅力。非常感谢你帮我发现了这一点：）@sammy:的确，这会起作用（如果你不想更改数据库，实际上效果会更好）。我个人尽量避免保留关键字，但你的解决方案很好。啊，你也帮了我。我的保留字是“索引”。-）

select
    this_.project_id as project1_3_0_,
    this_.description as descript2_3_0_,
    this_.homepage as homepage3_0_,
    this_.name as name3_0_,
    this_.shortname as shortname3_0_ 
from
    project this_ 
where
    this_.name=?

select
    this_.group_id as group1_4_0_,
    this_.name as name4_0_,
    this_.password as password4_0_,
    this_.subscribable as subscrib4_4_0_ 
from

group this_ where
    this_.name=?

@Entity
@Table(name = "groups")
public class Group implements Serializable {

    //...
}