Java 在接收数组的方法中分配两个数组

在一个方法中分配两个数组，该方法接收一个数组，但其内容未更改，为什么

public class Sol {

    public static void main(String[] args) {
        int[] list = {1, 2, 3, 4, 5}; 
        reverse(list); 

        for (int i = 0; i < list.length; i++) 
            System.out.print(list[i] + " ");// here it prints after reversing 1 2 3 4 5 why?
}

public static void reverse(int[] list) {
     int[] array = new int[list.length];

     for (int i = 0; i < list.length; i++) 
         array[i] = list[list.length - 1 - i];
         list = array;  here is the problem // is it call by value  //here assignment why does not change the contents after exit from the method
i do not ask about call by reference and i do not need answers for the code
i need to understand this statement (list = array; why is it call by value when exiting from the method reversing disappeared)
     }
}

公共类Sol{
公共静态void main（字符串[]args）{
int[]list={1,2,3,4,5}；
反向（列表）；
for（int i=0；i

Java是原语类型的按值传递和对象的按引用传递。 有关更多详细信息，请参阅以下链接

publicstaticvoidmain（字符串[]args）{
int[]list={1,2,3,4,5}；
列表=反向（列表）；
for（int i=0；i

int[]list={1,2,3,4,5}；
**反向（列表）**
for（int i=0；i

在这种情况下，在反转数组之后，您没有将反转的数组分配给任何变量。这就是这个问题的原因。换成这样，检查一下 列表=反向（列表）

在反转1 2 3 4 5后打印，为什么？你认为逆向（列表）是什么是否（如果转录正确）？是否使用？

public static void main(String[] args) {
        int[] list = { 1, 2, 3, 4, 5 };

        list = reverse(list);

        for (int i = 0; i < list.length; i++)
            System.out.print(list[i] + " "); // here it prints after reversing 1 2 3 4 5 why? }
    }

    public static int[] reverse(int[] list) {

        int[] tempList = new int[list.length];

        for (int i = 0; i < list.length; i++)
            tempList[i] = list[list.length - 1 - i];

        return tempList;
    }

int[] list = {1, 2, 3, 4, 5};

**reverse(list);**

for (int i = 0; i < list.length; i++)

System.out.print(list[i] + " ");// here it prints after reversing 1 2 3 4 5 why? }

public static void reverse(int[] list) {

int[] new List = new int[list.length];

for (int i = 0; i < list.length; i++)

new List[i] = list[list.length - 1 - i];

list = new List;}

}