Java 如何在android中使用intent传递数组列表
如何使用intent将数组列表从一个活动传递到另一个活动 来自活动Java 如何在android中使用intent传递数组列表,java,android,list,android-intent,Java,Android,List,Android Intent,如何使用intent将数组列表从一个活动传递到另一个活动 来自活动 ArrayList<ServicesInfo> bookedService = new ArrayList<ServicesInfo>();` Intent intent = new Intent(getActivity() , Proceedtocart.class); intent.putExtra("Listview",bookedServi
ArrayList<ServicesInfo> bookedService = new ArrayList<ServicesInfo>();`
Intent intent = new Intent(getActivity() , Proceedtocart.class);
intent.putExtra("Listview",bookedService);
startActivity(intent);
bookedService = (ArrayList<BookedInfo>) getIntent().getSerializableExtra("Listview");
ArrayList bookedService=new ArrayList()`
Intent Intent=新的Intent(getActivity(),Proceedtocart.class);
intent.putExtra(“Listview”,bookedService);
星触觉(意向);
到活动
ArrayList<ServicesInfo> bookedService = new ArrayList<ServicesInfo>();`
Intent intent = new Intent(getActivity() , Proceedtocart.class);
intent.putExtra("Listview",bookedService);
startActivity(intent);
bookedService = (ArrayList<BookedInfo>) getIntent().getSerializableExtra("Listview");
bookedService=(ArrayList)getIntent().getSerializableExtra(“Listview”);
运行时,我收到错误“java.lang.runtimeexception包无法封送值”
帮助解决此问题
试试这个:
Intent intent = new Intent(this, NextActivity.class);
intent.putStringArrayListExtra("Listview", bookedService);
startActivity(intent);
关于触觉:
yourArrayList = getIntent().getStringArrayListExtra("Listview");
你可以用
public class ContactInfo {
private String name;
private String surname;
private int idx;
// get and set methods
}
public class ContactInfo implements Parcelable {
private String name;
private String surname;
private int idx;
// get and set method
@Override
public int describeContents() {
return 0;
}
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeString(name);
dest.writeString(surname);
dest.writeInt(idx);
}
// Creator
public static final Parcelable.Creator CREATOR
= new Parcelable.Creator() {
public ContactInfo createFromParcel(Parcel in) {
return new ContactInfo(in);
}
public ContactInfo[] newArray(int size) {
return new ContactInfo[size];
}
};
// "De-parcel object
public ContactInfo(Parcel in) {
name = in.readString();
surname = in.readString();
idx = in.readInt();
}
}
放
得到
我在我的ServiceInfo数组中实现了parcelable,但仍然出现相同的错误显示您的
ServiceInfo
Try intent.putParcelableArrayListExtra(“key”,my_list);。它会解决你的问题。为此,您需要使您的ServiceInfo可打包。