Java 如何在android中解析json数组中没有键的json对象值？

如何解析下面的json数组，我的目标是传递没有值的对象

我已经尝试使用json对象的键返回json对象，但我的问题是如何在textview中显示没有键的json

[
[
    "Why are teachers being paid poorly?",
    {
        "answer": "minimum wage is 30,000",
        "candidate": "Nnamdi kalu"
    },
    "what is the minimum wage for teachers?",
    {
        "answer": "net worth is $200,000",
        "candidate": "Nnamdi kalu"
    },
    {
        "answer": "Teachers minimum wage is $200,000",
        "candidate": "Nnamdi kalu"
    },
    "What can you do to improve the Agriculture section?",
    "why do you delay in salary payment and how do you intend to solve late payment of salary?",
    "Checking if i can ask you more questions, can i ?",
    "What can you do to improve the football game?",
    "what is your name",
    "what are your agenda",
    "What can you do to help young entrepreneurs?"
 ]
]

---

我希望以测验应用程序的形式显示数据？

在这种情况下，您有一个带有多种可能值类型的

JSONArray

。数组中的每个元素可以是

字符串

或

JSONObject

您可以使用

JSONArray.get（）

方法获取每个元素，然后使用

instanceof

操作符检查元素是

字符串还是
JSONObject

假设您发布的示例存储在名为
数组的
JSONArray
中。您可以编写以下代码：

for (int i = 0; i < array.length(); i++) {
    Object o = array.get(i);
    if (o instanceof JSONObject) {
        System.out.println("object");
    } else if (o instanceof String) {
        System.out.println("string");
    }
}

现在，您可以用真实代码替换我的
System.out.println（）
调用，您应该已经上路了

string
object
string
object
object
string
...