Java 驼峰HTTP端点：如何将URL字符串设置为POST参数

先决条件

• ApacheTomcat7
• 弹簧3.2.11.释放
• ApacheCamel 2.14.1
• 驼峰HTTP端点（

  ..
  .com？urlparam1=value1&urlparam2=value2）作为后参数2的值
  
  提前谢谢
  
  问候,
  
  Max
  正如上面提到的isim，以下内容对我很有用。
  其思想是先解析给定的url，然后再对其进行编码。
  这避免了双重编码
  
  import java.io.UnsupportedEncodingException;
  import java.net.*;
  
  public static String getEncodedURL(String urlString) {
      final String encodedURL;
      try {
          String decodedURL = URLDecoder.decode(urlString, "UTF-8");
          URL url = new URL(decodedURL);
          URI uri = new URI(url.getProtocol(), url.getUserInfo(), url.getHost(), url.getPort(), url.getPath(), url.getQuery(), url.getRef());
          final URL urlFromDecoding = uri.toURL();
          encodedURL = URLEncoder.encode(urlFromDecoding.toString(), "UTF-8");
      } catch (UnsupportedEncodingException e) {
          ...
      } catch (MalformedURLException e) {
          ...
      } catch (URISyntaxException e) {
          ...
      }
      return encodedURL;
  }
  
  我在这里提到了如何通过驼峰HTTP post发送字符串消息，我希望这将对您有所帮助。另一个是我们需要添加基本的rest身份验证。用户名和密码是您的应用程序rest身份验证凭据
  
  from("seda:httpSender")  
      .log("Inside Http sender")
      .process(new Processor(){
          @Override
          public void process(Exchange exchange) throws Exception {
              // Camel will populate all request.parameter and request.headers, 
              // no need for placeholders in the "from" endpoint
              String content = exchange.getIn().getBody(String.class);      
  
              System.out.println("Outbound message string : "+content);
  
              // This URI will override http://dummyhost
              exchange.getIn().setHeader(Exchange.HTTP_URI, "http://localhost:9090/httpTest");
  
              // Add input path. This will override the original input path.
              // If you need to keep the original input path, then add the id to the 
              // URI above instead
           //   exchange.getIn().setHeader(Exchange.HTTP_PATH, id);
  
              // Add query parameter such as "?name=xxx"
              exchange.getIn().setHeader(Exchange.HTTP_QUERY, "outboundMessage="+content);  
              exchange.getIn().setHeader(Exchange.HTTP_METHOD, "POST");
          }
      })
      .doTry()
      .log("Message added as a parameter")
      .to("http4://localhost:9090/httpTest?authMethod=Basic&authPassword=admin&authUsername=admin")
      .log("HTTP message transfer success")
      .doCatch(Exception.class)
      .log("HTTP message transfer failed")
      .end();
  
  你试过使用吗？
  import java.io.UnsupportedEncodingException;
  import java.net.*;
  
  public static String getEncodedURL(String urlString) {
      final String encodedURL;
      try {
          String decodedURL = URLDecoder.decode(urlString, "UTF-8");
          URL url = new URL(decodedURL);
          URI uri = new URI(url.getProtocol(), url.getUserInfo(), url.getHost(), url.getPort(), url.getPath(), url.getQuery(), url.getRef());
          final URL urlFromDecoding = uri.toURL();
          encodedURL = URLEncoder.encode(urlFromDecoding.toString(), "UTF-8");
      } catch (UnsupportedEncodingException e) {
          ...
      } catch (MalformedURLException e) {
          ...
      } catch (URISyntaxException e) {
          ...
      }
      return encodedURL;
  }
  
  from("seda:httpSender")  
      .log("Inside Http sender")
      .process(new Processor(){
          @Override
          public void process(Exchange exchange) throws Exception {
              // Camel will populate all request.parameter and request.headers, 
              // no need for placeholders in the "from" endpoint
              String content = exchange.getIn().getBody(String.class);      
  
              System.out.println("Outbound message string : "+content);
  
              // This URI will override http://dummyhost
              exchange.getIn().setHeader(Exchange.HTTP_URI, "http://localhost:9090/httpTest");
  
              // Add input path. This will override the original input path.
              // If you need to keep the original input path, then add the id to the 
              // URI above instead
           //   exchange.getIn().setHeader(Exchange.HTTP_PATH, id);
  
              // Add query parameter such as "?name=xxx"
              exchange.getIn().setHeader(Exchange.HTTP_QUERY, "outboundMessage="+content);  
              exchange.getIn().setHeader(Exchange.HTTP_METHOD, "POST");
          }
      })
      .doTry()
      .log("Message added as a parameter")
      .to("http4://localhost:9090/httpTest?authMethod=Basic&authPassword=admin&authUsername=admin")
      .log("HTTP message transfer success")
      .doCatch(Exception.class)
      .log("HTTP message transfer failed")
      .end();