Java中的数字三角形

我想写一个程序，打印出一个由数字组成的三角形。应该是这样的：

           1
         2 3 4
       3 4 5 6 7
     4 5 6 7 8 9 0
   5 6 7 8 9 0 1 2 3
 6 7 8 9 0 1 2 3 4 5 6    

在我的例子中，它返回负数876543210-1-2-3。。。但它应该只使用0-9。我可以用模n%10，但我不知道怎么写。有什么帮助吗？多谢各位

import java.util.Scanner ;

public class Triangle {
public static void main (String [] args) {
    Scanner sc = new Scanner(System.in);

    System.out.print("Number: ");
    int n = sc.nextInt();
    int j;
    int i;
    int k = n-1;

    System.out.printf("n=%d\n\n", n);

    for (i=1; i<=(n*2); i=i+2) {
        for (j=0; j<=2*n-1; j++) {
            if (j < k){
                System.out.print(" ");
            }
            else if (j < (k+i)){ 
                    System.out.printf("%d", (n-j));
            }
            else {
                System.out.print(" ");              
            }       
        }
        k = k-1;
    System.out.println();
    }
}
}

---

这是一个可能的实现，我修改了您的索引名，因为它有点混乱：

public class Triangle {
    public static void main (String [] args) {
        Scanner sc = new Scanner(System.in);

        System.out.print("Number: ");
        int n = sc.nextInt();

        int startNumber = 1; /* First number in the line */
        int spaces = n - 1;  /* Spaces in the current line */
        int numbers = 1; /* Numbers in the current line */

        System.out.printf("n=%d\n\n", n);


        for (int lineCounter = 0; lineCounter < n; lineCounter++) {
            /* Spaces before the numbers */
            for (int spaceCounter = 0; spaceCounter < spaces; spaceCounter++) {
                System.out.print(" ");
            }
            for (int numberCounter = 0, number = startNumber; numberCounter < numbers; numberCounter++) {
                System.out.printf("%d", (number));
                number = (number + 1) % 10;
            }
            /* Spaces after the numbers */
            for (int spaceCounter = 0; spaceCounter < spaces; spaceCounter++) {
                System.out.print(" ");
            }
            System.out.println();
            startNumber = (startNumber + 1) % 10;
            spaces--;
            numbers += 2;
        }
    }
}

您可以创建一个printTriangle方法，如下注释所示：

static void printTriangle(int numLines) {
    for (int lineNumber = 1; lineNumber <= numLines; lineNumber++) {
        // Print 2 * (numLines - lineNumber) spaces before the first number in the current line
        for (int spacesPerLine = 0; spacesPerLine < 2 * (numLines - lineNumber); spacesPerLine++) {
            System.out.print(" ");
        }
        // First line has 1 number, second has 3, third has 5, etc.
        int numbersPerLine = (2 * lineNumber) - 1;
        // Print the numbers in the current line
        // from lineNumber (inclusive) to lineNumber + numbersPerLine (exclusive)
        for (int number = lineNumber; number < lineNumber + numbersPerLine; number++) {
            System.out.print((number % 10) + " ");
        }
        System.out.println();
    }
}

---

使用n%10仅仅意味着，如果n在0到9之间，它将给出n，但是当它大于10时，它将是：10到0，11到1，12到2，13到3。。。基本上，就我所能告诉你的，你想要的正是一个关于负数的快速修复方法，可以是System.out.printf%d，Math.absn-j；而不是System.out.printf%d，n-j；，但这表明，问题比负数还要多。