Java eclipse-android应用程序在EditText为空时崩溃

Java eclipse-android应用程序在EditText为空时崩溃,java,android,android-edittext,Java,Android,Android Edittext,你好。我在eclipse中为android编写应用程序,当EditText为空时,应用程序崩溃。我尝试了很多方法,但都不管用。每次我输入它和EditText时,它都会崩溃。对不起我的英语。 这是我代码的一部分: public class MainActivity extends Activity implements OnClickListener { TextView mnozstvo; TextView percento; TextView hmotnost; TextView vysle

你好。我在eclipse中为android编写应用程序,当EditText为空时,应用程序崩溃。我尝试了很多方法,但都不管用。每次我输入它和EditText时,它都会崩溃。对不起我的英语。 这是我代码的一部分:

public class MainActivity extends Activity implements OnClickListener {

TextView mnozstvo;
TextView percento;
TextView hmotnost;
TextView vysledok1;
TextView vysledok2;
TextView text;
RadioButton muz1;
RadioButton zena1;
Button vysledok;
EditText coo;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

text = (TextView)this.findViewById(R.id.text);

mnozstvo = (TextView)this.findViewById(R.id.dl);


percento = (TextView)this.findViewById(R.id.per);

hmotnost = (TextView)this.findViewById(R.id.kg);

vysledok1 = (TextView)this.findViewById(R.id.krv);

vysledok2 = (TextView)this.findViewById(R.id.dych);

muz1 = (RadioButton)this.findViewById(R.id.muz);

zena1 = (RadioButton)this.findViewById(R.id.zena);

vysledok = (Button)this.findViewById(R.id.vysledok);

vysledok.setOnClickListener(this);


}
.................
public void convertDollarsToEuros() {
double val = Double.parseDouble(mnozstvo.getText().toString());
double val1 = Double.parseDouble(percento.getText().toString());
double val2 = Double.parseDouble(hmotnost.getText().toString());

vysledok1.setText(Double.toString((val*val1*0.8)/(val2*0.68)));
vysledok2.setText(Double.toString(((val*val1*0.8)/(val2*0.68))/(2.1)));

text.setText(Double.toString(((val*val1*0.8)/(val2*0.68))*6.6164));



}

public void convertEurosToDollars() {

double val = Double.parseDouble(mnozstvo.getText().toString());
double val1 = Double.parseDouble(percento.getText().toString());
double val2 = Double.parseDouble(hmotnost.getText().toString());

vysledok1.setText(Double.toString((val*val1*0.8)/(val2*0.55)));
vysledok2.setText(Double.toString(((val*val1*0.8)/(val2*0.55))/(2.1)));
text.setText(Double.toString(((val*val1*0.8)/(val2*0.55))*6.6164));
有人能帮我吗?

如果给定null或“

Double,则parseDouble将不满意。parseDouble()
将引发NumberFormatException

但是,您可以在尝试解析字符串之前检查字符串的长度,而不是等待异常发生然后再处理它

您的代码应该如下所示:

public void convertEurosToDollars() {
    double val = 0;
    double val1= 0;
    double val2= 0;
    if (mnozstvo.getText().length() > 0 ) {
        val = Double.parseDouble(mnozstvo.getText().toString());
    }
    if (percento.getText().length() > 0 ) {
        val2 = Double.parseDouble(percento.getText().toString());
    }
    if (hmotnost.getText().length() > 0 ) {
        val3 = Double.parseDouble(hmotnost.getText().toString());
    }       


    vysledok1.setText(Double.toString((val*val1*0.8)/(val2*0.55)));
    vysledok2.setText(Double.toString(((val*val1*0.8)/(val2*0.55))/(2.1)));
    text.setText(Double.toString(((val*val1*0.8)/(val2*0.55))*6.6164));
   }

请发布所有崩溃的完整堆栈跟踪以寻求帮助。