如何确定输入最后一个整数的时间?JAVA
我现在必须输入一个字母来停止while循环并打印出数字列表。 是否有更好的方法来确定何时输入最后一个整数如何确定输入最后一个整数的时间?JAVA,java,loops,arraylist,integer,Java,Loops,Arraylist,Integer,我现在必须输入一个字母来停止while循环并打印出数字列表。 是否有更好的方法来确定何时输入最后一个整数 ` Scanner scanner = new Scanner(System.in); System.out.println("Enter a sequence of integer values" + " to be sent to the server"); List<Integer> n
` Scanner scanner = new Scanner(System.in);
System.out.println("Enter a sequence of integer values" +
" to be sent to the server");
List<Integer> numberList = new ArrayList<Integer>();
while(scanner.hasNextInt()) {
numberList.add(scanner.nextInt());
}
System.out.println(numberList);
os.write(String.valueOf(numberList));
scanner.close();`
`Scanner Scanner=新的扫描仪(System.in);
System.out.println(“输入整数值序列”+
“发送到服务器”);
List numberList=new ArrayList();
while(scanner.hasNextInt()){
numberList.add(scanner.nextInt());
}
System.out.println(numberList);
write(String.valueOf(numberList));
scanner.close()`
试试这个
final Scanner scanner = new Scanner(System.in);
System.out.println("Enter a sequence of integer values to be sent to the server");
final List<Integer> numberList = new ArrayList<Integer>();
int scanned;
do {
final int scanned = scanner.nextInt();
numberList.add(scanned);
} while (scanner.hasNextInt() && scanned != yourChar);
os.write(String.valueOf(numberList));
scanner.close();`
final Scanner=新扫描仪(System.in);
System.out.println(“输入要发送到服务器的整数值序列”);
最终列表编号列表=新的ArrayList();
int扫描;
做{
final int scanned=scanner.nextInt();
数字列表添加(扫描);
}while(scanner.hasnetint()&&scanned!=yourChar);
write(String.valueOf(numberList));
scanner.close()`
我希望我正确理解了你的问题。试试这个
final Scanner scanner = new Scanner(System.in);
System.out.println("Enter a sequence of integer values to be sent to the server");
final List<Integer> numberList = new ArrayList<Integer>();
int scanned;
do {
final int scanned = scanner.nextInt();
numberList.add(scanned);
} while (scanner.hasNextInt() && scanned != yourChar);
os.write(String.valueOf(numberList));
scanner.close();`
final Scanner=新扫描仪(System.in);
System.out.println(“输入要发送到服务器的整数值序列”);
最终列表编号列表=新的ArrayList();
int扫描;
做{
final int scanned=scanner.nextInt();
数字列表添加(扫描);
}while(scanner.hasnetint()&&scanned!=yourChar);
write(String.valueOf(numberList));
scanner.close()`
我希望我正确地理解了您的问题。按以下步骤操作:
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class Program {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("Enter a sequence of integer values to be sent to the server (x to terminate)");
List<Integer> numberList = new ArrayList<Integer>();
String[] data = scanner.nextLine().split(" ");
int i = 0;
while (i < data.length && data[i].matches("\\d+")) {// The regex \d+ matches only integers
numberList.add(Integer.parseInt(data[i]));
i++;
}
System.out.println(numberList);
}
}
另外,不要关闭系统中的扫描仪
,因为它也会关闭系统中的
如有疑问/问题,请随时发表评论。按以下步骤进行:
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class Program {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("Enter a sequence of integer values to be sent to the server (x to terminate)");
List<Integer> numberList = new ArrayList<Integer>();
String[] data = scanner.nextLine().split(" ");
int i = 0;
while (i < data.length && data[i].matches("\\d+")) {// The regex \d+ matches only integers
numberList.add(Integer.parseInt(data[i]));
i++;
}
System.out.println(numberList);
}
}
另外,不要关闭系统中的扫描仪
,因为它也会关闭系统中的
如果有疑问/问题,请随时发表评论。我试图避免输入字符,而是尝试实现知道的功能-我希望这能澄清问题。好吧,我的错,Arvind的答案是完美的,没有任何补充!我试图避免输入字符,而是尝试实现知道的功能-我希望这能澄清问题。好吧,我的错,Arvind的答案是完美的,没有什么可添加的!