Java 使用Gson解析单个json条目到多个对象
我有一个json响应,如下所示:Java 使用Gson解析单个json条目到多个对象,java,json,parsing,gson,Java,Json,Parsing,Gson,我有一个json响应,如下所示: { "id":"001", "name":"Name", "param_distance":"10", "param_sampling":"2" } { "id":"001", "name":"Name", "param_distance":"10", "param_sampling":"2", "events":[ { "id":"01",
{
"id":"001",
"name":"Name",
"param_distance":"10",
"param_sampling":"2"
}
{
"id":"001",
"name":"Name",
"param_distance":"10",
"param_sampling":"2",
"events":[
{
"id":"01",
"value":"22.5"
},
{
"id":"02",
"value":"31.0"
}
]
}
public class TestDeserializer implements JsonDeserializer<Test> {
@Override
public Test deserialize(JsonElement json, Type type,
JsonDeserializationContext context) throws JsonParseException {
JsonObject obj = json.getAsJsonObject();
Test test = new Test();
test.setId(obj.get("id").getAsInt());
test.setName(obj.get("name").getAsString());
Parameters params = new Parameters();
params.setDistance(obj.get("param_distance").getAsDouble());
params.setSampling(obj.get("param_sampling").getAsInt());
test.setParameters(params);
Gson eventGson = new Gson();
Type eventsType = new TypeToken<List<Event>>(){}.getType();
List<Event> eventList = eventGson.fromJson(obj.get("events"), eventsType);
test.setEvents(eventList);
return test;
}
}
private class TestDeserializer implements JsonDeserializer<Test> {
public Test deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context)
throws JsonParseException {
JsonObject obj = json.getAsJsonObject();
int id = obj.get("id").getAsInt();
String name = obj.get("name").getAsString();
double distance = obj.get("param_distance").getAsDouble();
int sampling = obj.get("param_sampling").getAsInt();
//assuming you have suitable constructors...
Test test = new Test(id, name, new Parameters(distance, sampling));
return test;
}
}
我有两个类:Teste和Parameters
public class Test {
private int id;
private String name;
private Parameters params;
}
public class Parameters {
private double distance;
private int sampling;
}
我的问题是:有没有一种方法可以让Gson理解一些json属性应该转到Parameters类,或者唯一的方法是“手动”解析它
编辑
好吧,让我在@MikO的回答中的评论更具可读性:
我将向json输出中添加一个对象列表,因此json响应应该如下所示:
{
"id":"001",
"name":"Name",
"param_distance":"10",
"param_sampling":"2"
}
{
"id":"001",
"name":"Name",
"param_distance":"10",
"param_sampling":"2",
"events":[
{
"id":"01",
"value":"22.5"
},
{
"id":"02",
"value":"31.0"
}
]
}
public class TestDeserializer implements JsonDeserializer<Test> {
@Override
public Test deserialize(JsonElement json, Type type,
JsonDeserializationContext context) throws JsonParseException {
JsonObject obj = json.getAsJsonObject();
Test test = new Test();
test.setId(obj.get("id").getAsInt());
test.setName(obj.get("name").getAsString());
Parameters params = new Parameters();
params.setDistance(obj.get("param_distance").getAsDouble());
params.setSampling(obj.get("param_sampling").getAsInt());
test.setParameters(params);
Gson eventGson = new Gson();
Type eventsType = new TypeToken<List<Event>>(){}.getType();
List<Event> eventList = eventGson.fromJson(obj.get("events"), eventsType);
test.setEvents(eventList);
return test;
}
}
private class TestDeserializer implements JsonDeserializer<Test> {
public Test deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context)
throws JsonParseException {
JsonObject obj = json.getAsJsonObject();
int id = obj.get("id").getAsInt();
String name = obj.get("name").getAsString();
double distance = obj.get("param_distance").getAsDouble();
int sampling = obj.get("param_sampling").getAsInt();
//assuming you have suitable constructors...
Test test = new Test(id, name, new Parameters(distance, sampling));
return test;
}
}
反序列化器类如下所示:
{
"id":"001",
"name":"Name",
"param_distance":"10",
"param_sampling":"2"
}
{
"id":"001",
"name":"Name",
"param_distance":"10",
"param_sampling":"2",
"events":[
{
"id":"01",
"value":"22.5"
},
{
"id":"02",
"value":"31.0"
}
]
}
public class TestDeserializer implements JsonDeserializer<Test> {
@Override
public Test deserialize(JsonElement json, Type type,
JsonDeserializationContext context) throws JsonParseException {
JsonObject obj = json.getAsJsonObject();
Test test = new Test();
test.setId(obj.get("id").getAsInt());
test.setName(obj.get("name").getAsString());
Parameters params = new Parameters();
params.setDistance(obj.get("param_distance").getAsDouble());
params.setSampling(obj.get("param_sampling").getAsInt());
test.setParameters(params);
Gson eventGson = new Gson();
Type eventsType = new TypeToken<List<Event>>(){}.getType();
List<Event> eventList = eventGson.fromJson(obj.get("events"), eventsType);
test.setEvents(eventList);
return test;
}
}
private class TestDeserializer implements JsonDeserializer<Test> {
public Test deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context)
throws JsonParseException {
JsonObject obj = json.getAsJsonObject();
int id = obj.get("id").getAsInt();
String name = obj.get("name").getAsString();
double distance = obj.get("param_distance").getAsDouble();
int sampling = obj.get("param_sampling").getAsInt();
//assuming you have suitable constructors...
Test test = new Test(id, name, new Parameters(distance, sampling));
return test;
}
}
按我想要的方式给我测试对象 让Gson理解它的方法是通过为
测试
类创建类型适配器
来编写自定义反序列化程序。您可以在中找到信息。这并不完全是一个手动解析,但也没有什么不同,因为您必须告诉Gson如何处理每个JSON值
应该是这样的:
{
"id":"001",
"name":"Name",
"param_distance":"10",
"param_sampling":"2"
}
{
"id":"001",
"name":"Name",
"param_distance":"10",
"param_sampling":"2",
"events":[
{
"id":"01",
"value":"22.5"
},
{
"id":"02",
"value":"31.0"
}
]
}
public class TestDeserializer implements JsonDeserializer<Test> {
@Override
public Test deserialize(JsonElement json, Type type,
JsonDeserializationContext context) throws JsonParseException {
JsonObject obj = json.getAsJsonObject();
Test test = new Test();
test.setId(obj.get("id").getAsInt());
test.setName(obj.get("name").getAsString());
Parameters params = new Parameters();
params.setDistance(obj.get("param_distance").getAsDouble());
params.setSampling(obj.get("param_sampling").getAsInt());
test.setParameters(params);
Gson eventGson = new Gson();
Type eventsType = new TypeToken<List<Event>>(){}.getType();
List<Event> eventList = eventGson.fromJson(obj.get("events"), eventsType);
test.setEvents(eventList);
return test;
}
}
private class TestDeserializer implements JsonDeserializer<Test> {
public Test deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context)
throws JsonParseException {
JsonObject obj = json.getAsJsonObject();
int id = obj.get("id").getAsInt();
String name = obj.get("name").getAsString();
double distance = obj.get("param_distance").getAsDouble();
int sampling = obj.get("param_sampling").getAsInt();
//assuming you have suitable constructors...
Test test = new Test(id, name, new Parameters(distance, sampling));
return test;
}
}
最后,您只需像往常一样解析JSON,使用:
gson.fromJson(yourJsonString, Test.class);
Gson将自动使用您的自定义反序列化程序将JSON解析到您的
Test
类中。Yep。我曾经在一些代码中使用过很多“示例”。这里有一个类,但该目录中的大多数内容都有一个自定义适配器:Ok。成功了。但让我们把问题复杂化一点。我在这个测试课上也有一个列表。列表如何在此方法中包含此列表解析。根据我所读的,我必须使用JsonArray类,对吗?好的。我的活动列表也在运行。您可以获取元素并使用regular Gson对象对其进行解析Gson eventGson=new Gson();类型eventsType=newTypeToken(){}.getType();List eventList=eventGson.fromJson(obj.get(“事件”),eventsType);test.setEvents(事件列表)代码>Json输入应该是这样的:{“id”:“001”,“name”:“name”,“param_distance”:“10”,“param_sampling”:“2”,“events”:[{“id”:“01”},{“id”:“02”}]}
我已经用这些信息更新了我的问题。谢谢你的帮助……=)