Java 删除和返回索引链接列表中的项 package linkedList.list; 导入linkedList.node.ListNode; 公共接口链接列表 { 公共布尔值为空(); 公共整数大小(); 公共字符串toString(); public T[]toArray(Class
当从I位置的链接列表中删除节点时,您需要做的就是Java 删除和返回索引链接列表中的项 package linkedList.list; 导入linkedList.node.ListNode; 公共接口链接列表 { 公共布尔值为空(); 公共整数大小(); 公共字符串toString(); public T[]toArray(Class,java,methods,linked-list,nodes,singly-linked-list,Java,Methods,Linked List,Nodes,Singly Linked List,当从I位置的链接列表中删除节点时,您需要做的就是 到达i-1的节点,我们将其命名为“n1” 获取节点n2=n1.next.next 使n1.next=n2 您只需删除i处请求节点的“链接”,它就不再是链接列表的一部分。首先,您必须检查这是否是您必须删除的第0个索引,因此您必须移动根。然后,要删除i根处的节点,您只需执行以下操作: package linkedList.list; import linkedList.node.ListNode; public interface LinkedL
您只需删除i处请求节点的“链接”,它就不再是链接列表的一部分。首先,您必须检查这是否是您必须删除的第0个索引,因此您必须移动根。然后,要删除i根处的节点,您只需执行以下操作:
package linkedList.list;
import linkedList.node.ListNode;
public interface LinkedList<N extends ListNode<T>,T>
{
public boolean isEmpty();
public int size();
public String toString();
public T[] toArray(Class<? extends T> cl);
public LinkedList<N,T> fromArray(T[] array) throws ListAccessError;
}
package linkedList.list;
import linkedList.node.ListNode;
import java.lang.reflect.Array;
import java.util.ArrayList;
import java.util.Arrays;
public abstract class BasicList<N extends ListNode<T>,T> implements LinkedList<N,T> {
N root;
int size;
public boolean isEmpty() {
return size == 0;
}
public int size() {
return size;
}
public N getRoot() {
return root;
}
public void setRoot(N newRoot) {
root = newRoot;
}
public T[] toArray(Class<? extends T> cl) {
T[] array = (T[]) Array.newInstance(cl,size());
ListNode<T> node = getRoot();
for (int index = 0; index < size(); index++) {
array[index] = node.getValue();
node = node.getNext();
}
return array;
}
public String toString() {
if (isEmpty()) {
return "[]";
} else {
ListNode<T> currentNode = getRoot();
StringBuilder string = new StringBuilder("[" + currentNode.getValue());
while ((currentNode = currentNode.getNext()) != null) {
string.append("," + currentNode.getValue());
}
string.append("]");
return string.toString();
}
}
public String toString(int n) {
if (isEmpty()) {
return "[]";
} else {
ListNode<T> currentNode = getRoot();
StringBuilder string = new StringBuilder("[" + currentNode.getValue());
int added = 0;
while (added < n && (currentNode = currentNode.getNext()) != null) {
string.append("," + currentNode.getValue());
added++;
}
if (currentNode != null) {
string.append(",...");
}
string.append("]");
return string.toString();
}
}
}
package linkedList.list;
import com.sun.xml.internal.bind.v2.runtime.unmarshaller.XsiNilLoader;
import jdk.nashorn.internal.ir.IfNode;
import linkedList.node.ListNode;
import linkedList.node.SingleLinkNode;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
public class SingleLinkList<T> extends BasicList<SingleLinkNode<T>,T> implements List<T> {
public SingleLinkList<T> fromArray(T[] array) throws ListAccessError {
for (int index = array.length-1; index >= 0; index--) {
add(0,array[index]);
}
return this;
}
ListNode<T> getNode(int index) throws ListAccessError {
// Is the list empty? If so, cannot access the node.
if (isEmpty()) {
throw new ListAccessError("Cannot get node. List is empty.");
}
// Is the given index negative? If so, this is an error.
if (index < 0) {
throw new ListAccessError("Cannot get node. Negative index.");
}
ListNode<T> currentNode = getRoot(); // start at the root
while (index != 0 && currentNode != null) { // walk along the list (if haven't reached the end by hitting null node)
currentNode = currentNode.getNext(); // by gettting next node in the list
index--; // and reducing index by one
}
// Reached the end of the list (by hitting null node)? If so, cannot access the required node.
if (currentNode == null) {
throw new ListAccessError("Cannot get node. Not enough nodes in the list.");
}
// Successfully found node by walking through until index was zero.
return currentNode;
}
public T get(int index) throws ListAccessError {
return getNode(index).getValue();
}
@Override
public void add(int index, T value) throws ListAccessError {
if (index > size() || index < 0) {
throw new ListAccessError("Index bigger than size.");
}
SingleLinkNode<T> newNode = new SingleLinkNode<T>(value);
SingleLinkNode<T> current = getRoot();
if(index==0) {
setRoot(newNode);
newNode.setNext(current);
size++;
} else {
while(--index > 0) {
current = current.getNext();
}
newNode.setNext(current.getNext());
current.setNext(newNode);
size++;
}
}
@Override
public T remove(int index) throws ListAccessError {
if (index >= size() || index < 0) {
throw new ListAccessError("Index out of bounds");
}
if (isEmpty()) {
throw new ListAccessError("List is empty cannot remove from list");
}
SingleLinkNode<T> current = getRoot();
SingleLinkNode<T> nextItem = getRoot().getNext();
return null;
}
}
package linkedList.node;
public class SingleLinkNode<T> implements ListNode<T>
{
private T value;
private SingleLinkNode<T> next;
public SingleLinkNode(T value) {
this.value = value;
next = null;
}
public SingleLinkNode(T value, SingleLinkNode<T> next) {
this.value = value;
this.next = next;
}
public T getValue() {
return value;
}
@Override
public void setValue(T value) {
this.value = value;
}
public SingleLinkNode<T> getNext() {
return next;
}
@Override
public void setNext(ListNode<T> node) {
next = (SingleLinkNode<T>) node;
}
public String toString() {
return value + (getNext() != null ? "=>" + getNext() : "");
}
}
完整代码:
public T remove(int index)抛出ListAccessError{
如果(索引>=size()||索引<0){
抛出新的ListAccessError(“索引超出范围”);
}
if(isEmpty()){
抛出新ListAccessError(“列表为空,无法从列表中删除”);
}
SingleLinkNode current=getRoot();
删除SingleLinkNode;
如果(索引==0){
移除=电流;
setRoot(current.getNext());//将root设置为root.next
}否则{
对于(int i=0;i
尝试实现此代码,但在测试时,它从列表中删除了错误的项。我添加的代码是相同的,但不是在末尾返回null,而是返回current.getValue();此方法应返回null,这不取决于您在方法中执行的操作。您的代码的其他位置一定有问题。您的getNext()
和setNext()
方法在哪里?我已将它们添加到代码包的顶部,它们位于SingleLinkNodeIt下。必须工作。您能详细说明为什么它不工作吗
nodeBeforeI.setNext(nodeBeforeI.getNext().getNext());