Java Selenium检查下载链接是否处于活动状态

Java Selenium检查下载链接是否处于活动状态,java,selenium,selenium-webdriver,webdriver,Java,Selenium,Selenium Webdriver,Webdriver,使用Java和selenium,我想检查我的下载链接是否处于活动状态。我只想显示http状态代码 HttpClient client = HttpClientBuilder.create().build(); HttpGet request = new HttpGet(baseUrl); HttpResponse response = client.execute(request); System.out.println(response.getS

使用Java和selenium,我想检查我的下载链接是否处于活动状态。我只想显示http状态代码

      HttpClient client = HttpClientBuilder.create().build();
      HttpGet request = new HttpGet(baseUrl);
      HttpResponse response = client.execute(request);
      System.out.println(response.getStatusLine().getStatusCode());

我试过了,但没有成功。

我已经设法让它按我想要的方式工作。我使用TestNG使用了.isEnabled()选项,如下所示

@Test
public void testProductNavBar(){
assertTrue(driver.findElement(By.xpath("/html/body/nav[2]/div/div/ul/li[1]/a")).isEnabled());
}

希望它能对您有所帮助。

我已经尝试过了,它可以很好地验证链接的状态。我的密码在这里

public static void verifyURLStatus(String URL) {

    HttpClient client = HttpClientBuilder.create().build();
    HttpGet request = new HttpGet(URL);
    try {
        HttpResponse response = client.execute(request);
        // verifying response code and The HttpStatus should be 200 if not,
        // increment invalid link count
        // We can also check for 404 status code like response.getStatusLine().getStatusCode() == 404
        int invalidLinksCount=0;
        if (response.getStatusLine().getStatusCode() != 200)
            invalidLinksCount++;
        System.out.println(response.getStatusLine().getStatusCode());
    } catch (Exception e) {
        e.printStackTrace();
    }
}

String URL="http://cdn.rentbyowner.com/sitemap/gz/site-map-0.xml.gz";
verifyURLStatus(URL);

对。我们可以使用httpurl连接来验证下载链接。下面是可重用代码

public static void verifyLinkActive(String linkUrl)
{
    try 
    {
       URL url = new URL(linkUrl);
       HttpURLConnection httpURLConnect=(HttpURLConnection)url.openConnection();
       httpURLConnect.setConnectTimeout(3000);
       httpURLConnect.connect();
       if(httpURLConnect.getResponseCode()==200)
       {
           System.out.println(linkUrl+" - "+httpURLConnect.getResponseMessage());
       }
       else 
       {
           System.out.println(linkUrl+" - is Dowm");
       }
    } catch (Exception e) 
    {

    }
} 

谢谢。

谢谢您的评论。假设我要检查此处的链接,没有选项让IDI运行此代码及其带有URL的打开浏览器,但不幸的是,它没有显示任何输出。在程序上显示没有错误,但没有获得输出。