Java 在do while循环中获取要从队列中删除的项目

您的问题在于代码的这一部分：

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a new customer has been added to line
The Queue size is now: 1

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a new customer has been added to line
The Queue size is now: 2

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a new customer has been added to line
The Queue size is now: 3

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a new customer has been added to line
The Queue size is now: 4

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a new customer has been added to line
The Queue size is now: 5

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a new customer has been added to line
The Queue size is now: 6

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a new customer has been added to line
The Queue size is now: 7

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a new customer has been added to line
The Queue size is now: 8

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a new customer has been added to line
The Queue size is now: 9

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a new customer has been added to line
The Queue size is now: 10

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a new customer has been added to line
The Queue size is now: 11

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a new customer has been added to line
The Queue size is now: 12

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a new customer has been added to line
The Queue size is now: 13

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a new customer has been added to line
The Queue size is now: 14

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如果没有人添加到队列，而当前队列尚未完成，则将

currentPatronTimeLeft

更新为当前客户端的开始值。在那之后，你减少它。如果在下一次迭代中，没有新的客户机添加到队列中，那么当前客户机将不会完成，因为他剩余的时间是他从开始到现在的时间-1。然后将

currentCustomerTimeLeft

再次更新为其开始值，然后再将其递减。这样它就永远不会变成0

解决方案：

else if (lineSize != 0)
{
    currentPatronTimeLeft =myQueue.peek();
}
currentPatronTimeLeft--;

else if（CurrentCustomerTimeLeft==0&&lineSize！=0）
{
myQueue.poll（）；
线条尺寸--；
//插入以下行：
如果（线宽>0）{
CurrentCustomerTimeLeft=myQueue.peek（）+1；/+1递减后
}
//我的插入结束
System.out.println（“客户已从队列中删除”）；
totalCheckedOut++；
System.out.println（“队列大小现在为：“+lineSize”）；
}

---

如果（lineSize！=0）块，则必须去除整个

。
从代码中删除以下条件：

else if(currentPatronTimeLeft == 0 && lineSize != 0)
{
    myQueue.poll();
    lineSize--;
    // insert following lines:
    if (lineSize > 0) {
        currentPatronTimeLeft =myQueue.peek() + 1; // +1 <--> following decrement
    }
    // end of my insert
    System.out.println("A customer has been removed from the queue");
    totalCheckedOut++;
    System.out.println("The Queue size is now: "+ lineSize);
}

它应该可以正常工作
如果您遇到了问题，那么currentCustomerTimeLeft将始终是第一个元素，因此永远不会达到零。快速修复方法是使用另一个变量来实现这些目的。
你有调试器吗？@RADAI我没有调试器，我们必须经常滚动，因为你的代码有很多空行。在此之前，请考虑把它格式化好。尝试将代码减少到显示问题的绝对最小值-请参见“好的，我已更改：else if”（CurrentPatientTimeLeft==0 | | lineSize！=0），现在我已删除项prematurely@user2094629：使用
| |线宽！=一旦0进入，它将始终被删除。我在上面发布了一个解决方案。好吧，它似乎运行得更好，并且似乎处于正确的模式。输出为新客户已添加到生产线。他们的服务时间是：1队列大小现在是：1---------------------------------------------一个新客户已添加到队列中。他们的服务时间是：3队列大小现在是：2 1-------------------------------------------客户已从队列中删除队列大小现在是：1-------------------------------------------破折号表示1次迭代，但我觉得输出是一次迭代是的，因为现在它是正确的。请不要忘记接受最好的答案，看看它是如何工作的：并向上投票选出有用的答案。您建议如何使用另一个变量来替换currentTimeLeft？或者你是在建议我另外添加一个变量吗？因为我还不能对其他答案发表评论，@user2094270如果currentCustomerTimeLeft=myQueue.poll（），你最好添加第一个变量；
else if(currentPatronTimeLeft == 0 && lineSize != 0)
{
    myQueue.poll();
    lineSize--;
    // insert following lines:
    if (lineSize > 0) {
        currentPatronTimeLeft =myQueue.peek() + 1; // +1 <--> following decrement
    }
    // end of my insert
    System.out.println("A customer has been removed from the queue");
    totalCheckedOut++;
    System.out.println("The Queue size is now: "+ lineSize);
}

else if(lineSize != 0)
 {
           currentPatronTimeLeft =myQueue.peek();
 }