Java 如何从JSON中获取密钥名并形成新的JSON

我有一个JSON示例：-

{
   "d-ps":{
   "d-es":{
   "d-e": 
       [
       {
        "dr": "A",
        "dn": "ad",
        "dt": "am",
        "db": "ami",
        "tn": "at",
        "dqr": "A",
        "dc": "GPC-01",
        "bdo": "Ain",
        "tdo": "Adn",
        "de": "St"
        },
        {
        "dr": "A1",
        "dn": "ads",
        "dt": "amd",
        "db": "am",
        "tn": "ats",
        "dqr": "B",
        "dc": "GP-01",
        "bdo": "Ann",
        "tdo": "And",
        "de": "Sat"
        }
        ]
        }
        }
        }

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我想从d-e数组中的这个JSON中获取所有密钥名称，然后生成一个新的JSON，并在数组中的d-e之后将这些密钥包含在JSON数组中，作为eh:[包含d-e数组中用逗号分隔的所有密钥]

您可以将JSON字符串作为字典加载，然后抓住其中的第一个d-e数组，通过其键进行迭代，并将其添加到数组中：

jsonDict = {"d-ps":{"d-es":{"d-e":[{"dr":"A","dn":"ad","dt":"am","db":"ami","tn":"at","dqr":"A","dc":"GPC-01","bdo":"Ain","tdo":"Adn","de":"St"},{"dr":"A1","dn":"ads","dt":"amd","db":"am","tn":"ats","dqr":"B","dc":"GP-01","bdo":"Ann","tdo":"And","de":"Sat"}]}}}
deDict = jsonDict['d-ps']['d-es']['d-e'][0]
keysArray = []
for k in de[0].keys():
    keysArray.append(k)

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我将JSOn转换为XML类型，然后使用xpath从d-e节点内的XML中提取所有节点名称，然后生成一个新的XML，并在d-es节点后在XML中包含数组中的键，然后将其转换为JSOn，为什么不先尝试一下呢？