Java 从以逗号分隔的文件中读取int

Java 从以逗号分隔的文件中读取int,java,bufferedreader,Java,Bufferedreader,我这里有一段代码,它从文件中读取数字并将其存储在字符串数组中 public static void main(String [] args) throws Exception{ BufferedReader br = new BufferedReader(new FileReader("/Users/Tda/desktop/ReadFiles/scores.txt")); String line = null;

我这里有一段代码,它从文件中读取数字并将其存储在字符串数组中

        public static void main(String [] args) throws Exception{


             BufferedReader br = new BufferedReader(new FileReader("/Users/Tda/desktop/ReadFiles/scores.txt"));

             String line = null;

             while((line = br.readLine()) != null){

               String[] values = line.split(",");

               for(String str : values){
               System.out.println(str);
               }

              }

             System.out.println("");

             br.close();            

         }
但是如果我想将字符串数组中的值存储在int数组中,我应该怎么做呢

我正在读的文件看起来像这样

      23,64,73,26
      75,34,21,43
使用parseInt(String)将每个字符串转换为int

int[]intvalues=newint[values.length];
对于(int i=0;i
String[]值=line.split(“,”)之后

// new int[] with "values"'s length
int[] intValues = new int[values.length];
// looping over String values
for (int i = 0; i < values.length; i++) {
    // trying to parse String value as int
    try {
        // worked, assigning to respective int[] array position
        intValues[i] = Integer.parseInt(values[i]);
    }
    // didn't work, moving over next String value
    // at that position int will have default value 0
    catch (NumberFormatException nfe) {
        continue;
    }
}

您需要将
字符串
解析为
int

 while((line = br.readLine()) != null){

               String[] values = line.split(",");
               int[] values2=new int[values.length];

               for(int i=0; i<values.length; i++){
               try {
               values2[i]= Integer.parseInt(values[i]);
               //in case it's not an int, you need to try catching a potential exception
               }catch (NumberFormatException e) {
                 continue;
               }
               }


 }
while((line=br.readLine())!=null){
字符串[]值=行。拆分(“,”);
int[]values2=新的int[values.length];

for(int i=0;我想把所有的值放在一个int数组中,还是想为文件中的每一行单独设置一个int数组?实际上,每一行一个数组,但所有行一个数组也可以。for循环中的值应该是values.length,而不是values.length()很好!完全忽略了这一点。
System.out.println(Arrays.toString(intValues));
 while((line = br.readLine()) != null){

               String[] values = line.split(",");
               int[] values2=new int[values.length];

               for(int i=0; i<values.length; i++){
               try {
               values2[i]= Integer.parseInt(values[i]);
               //in case it's not an int, you need to try catching a potential exception
               }catch (NumberFormatException e) {
                 continue;
               }
               }


 }