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Java 如何在gremlin中编写for循环?_Java_Neo4j_Gremlin - Fatal编程技术网

Java 如何在gremlin中编写for循环?

Java 如何在gremlin中编写for循环?,java,neo4j,gremlin,Java,Neo4j,Gremlin,如何在gremlin中为循环编写?比如: for i=0;i<10:i++: println hello number i gremlin> g = TinkerGraphFactory.createTinkerGraph() ==>tinkergraph[vertices:6 edges:6] gremlin> g.V.filter{!it.inE.hasNext()}.count() ==>2 我的主要目标是执行for循环并打印没有inE的节点的值。这意

如何在gremlin中为循环编写
?比如:

for i=0;i<10:i++:
  println hello number i
gremlin> g = TinkerGraphFactory.createTinkerGraph()
==>tinkergraph[vertices:6 edges:6]
gremlin> g.V.filter{!it.inE.hasNext()}.count()
==>2

我的主要目标是执行for循环并打印没有
inE
的节点的值。这意味着它们的阶数为零。

如果要在图中的所有节点上进行迭代,以获得边中没有的节点数,可以执行以下操作:

for i=0;i<10:i++:
  println hello number i
gremlin> g = TinkerGraphFactory.createTinkerGraph()
==>tinkergraph[vertices:6 edges:6]
gremlin> g.V.filter{!it.inE.hasNext()}.count()
==>2
如果要执行一些副作用,如“打印”,则使用副作用步骤:

gremlin> g.V.filter{!it.inE.hasNext()}.sideEffect{println it.name}
marko
==>v[1]
peter
==>v[6]
请注意,它打印了两次,因为Gremlin终端已经在为您打印,因此如果您在终端中,您最好执行以下操作:

gremlin> g.V.filter{!it.inE.hasNext()}.name                       
==>marko
==>peter

过滤器{!it.inE.hasNext()}
效率更高,因为不需要完整计数/迭代