Java Jackson xml在序列化时忽略空对象
我想在SpringMVCModelAttribute(Person)和Jackson的帮助下从html表单创建xml 表格: 在控制器中创建XML:Java Jackson xml在序列化时忽略空对象,java,spring-mvc,jackson,Java,Spring Mvc,Jackson,我想在SpringMVCModelAttribute(Person)和Jackson的帮助下从html表单创建xml 表格: 在控制器中创建XML: @RequestMapping("saveperson") public String savePerson(@ModelAttribute final Person person, final ModelMap model) { final ObjectMapper xmlMapper = new XmlMapper(); fin
@RequestMapping("saveperson")
public String savePerson(@ModelAttribute final Person person, final ModelMap model) {
final ObjectMapper xmlMapper = new XmlMapper();
final String xml = xmlMapper.writeValueAsString(person);
return "redirect:/listpersons";
}
输出xml:
<person>
<name>John</name>
<email>john@test.com</email>
<address/>
</person>
但它不起作用。
我也试过了
@JsonInclude(Include.NON_EMPTY)和@JsonInclude(Include.NON_NULL)
但它总是在XML中包含空对象
我的第二个问题是:当我想将地址列表绑定到html表单时。最好的方法是什么
....
<input name="name"/>
<input name="birthday"/>
<input name="address1.street/>
<input name="address1.city/>
<input name="address2.street/>
<input name="address2.city/>
....
@JacksonXmlRootElement(localName = "person")
@JsonInclude(Include.NON_DEFAULT)
public class Person implements Serializable {
@JsonIgnore
private Long id;
@JacksonXmlProperty(localName = "name")
private String name;
@JacksonXmlProperty(localName = "email")
private String email;
@JsonIgnore
private Address address1;
@JsonIgnore
private Address address2;
//add address1 and address2 in the getter or dto for the ModelAttribute?
@JacksonXmlElementWrapper(localName = "addresses")
@JacksonXmlProperty(localName = "address")
private List<Address> address;
private String birthday;
//getter and setter
}
。。。。
....
@JacksonXmlRootElement(localName=“person”)
@JsonInclude(Include.NON_默认值)
公共类Person实现可序列化{
@杰索尼奥雷
私人长id;
@JacksonXmlProperty(localName=“name”)
私有字符串名称;
@JacksonXmlProperty(localName=“电子邮件”)
私人字符串电子邮件;
@杰索尼奥雷
私人地址1;
@杰索尼奥雷
私人地址2;
//在ModelAttribute的getter或dto中添加address1和address2?
@JacksonXmlElementWrapper(localName=“地址”)
@JacksonXmlProperty(localName=“地址”)
私人名单地址;
私人串生日;
//接二连三
}
谢谢 圣诞老人
我刚刚遇到这个问题,很高兴看到有人问了同样的问题,但很遗憾没有人回答
在修改之后,我为您的第一个问题找到了两种可能的解决方案,即在XML输出中不包含空值
首先是将@JsonInclude(JsonInclude.Include.NON_EMPTY)
包含在我的模型之上。所以对你来说,在这种情况下,我怀疑这会起作用:
@JacksonXmlRootElement(localName = "person")
@JsonInclude(JsonInclude.Include.NON_EMPTY)
public class Person implements Serializable {
@JsonIgnore
private Long id;
@JacksonXmlProperty(localName = "name")
private String name;
@JacksonXmlProperty(localName = "email")
private String email;
@JacksonXmlProperty(localName = "address")
private Address address;
private String birthday;
//getter and setter
}
这将删除您以前的Include.NON_DEFAULT
,如果您选择这条路线,我希望您可以不使用它
其次,似乎还有一种我没有采用的替代解决方案,这将使我们直接像这样修改XmlMapper:
XmlMapper xmlMapper = new XmlMapper();
xmlMapper.setSerializationInclusion(JsonInclude.Include.NON_EMPTY);
我希望其中一个能有所帮助,十个月后。我遇到了完全相反的问题,在模型中,我有空字符串,它被序列化为null:(
....
<input name="name"/>
<input name="birthday"/>
<input name="address1.street/>
<input name="address1.city/>
<input name="address2.street/>
<input name="address2.city/>
....
@JacksonXmlRootElement(localName = "person")
@JsonInclude(Include.NON_DEFAULT)
public class Person implements Serializable {
@JsonIgnore
private Long id;
@JacksonXmlProperty(localName = "name")
private String name;
@JacksonXmlProperty(localName = "email")
private String email;
@JsonIgnore
private Address address1;
@JsonIgnore
private Address address2;
//add address1 and address2 in the getter or dto for the ModelAttribute?
@JacksonXmlElementWrapper(localName = "addresses")
@JacksonXmlProperty(localName = "address")
private List<Address> address;
private String birthday;
//getter and setter
}
@JacksonXmlRootElement(localName = "person")
@JsonInclude(JsonInclude.Include.NON_EMPTY)
public class Person implements Serializable {
@JsonIgnore
private Long id;
@JacksonXmlProperty(localName = "name")
private String name;
@JacksonXmlProperty(localName = "email")
private String email;
@JacksonXmlProperty(localName = "address")
private Address address;
private String birthday;
//getter and setter
}
XmlMapper xmlMapper = new XmlMapper();
xmlMapper.setSerializationInclusion(JsonInclude.Include.NON_EMPTY);