如何在java中显示上一条记录和下一条记录

可能重复：

我试图用JAVA将数据库中的记录显示到gui应用程序中。我试着运行下面的代码，但是我得到了一个异常，这个操作不受支持，我不知道它出了什么问题

 private void bt_previousActionPerformed(java.awt.event.ActionEvent evt) {
        if(evt.getSource()==bt_previous){

            DBUtil util = new DBUtil();
               try {
                    Connection con = util.getConnection();
                   PreparedStatement stmt = con.prepareStatement("SELECT [box_no],[weight],[note_state],[dm_state],[1],[2],[5],[10],[20],[50],[100],[500],[1000] FROM [CNV].[dbo].[soil_det] where rm_id=?");
                    ResultSet rs;
                    String rm = tf_rm_id.getText().trim();

                    stmt.setLong(1, Long.parseLong(rm));

                    rs = stmt.executeQuery();

                    rs.getArray(WIDTH);
                    char n = WIDTH;
                    int i;
                    for (i=0; i<n; i++) {
                        String a = rs.getString("weight");
                        txtboxwgt.setText(a);
                        String b = rs.getString("note_state");
                        cbnotstat.setSelectedItem(b);
                        String c = rs.getString("dm_state");
                        cbdmnstat.setSelectedItem(c);
                        txtboxno.setText(rs.getString("box_no"));
                        txtRe1.setText(rs.getString("1"));
                        txtRs2.setText(rs.getString("2"));
                        txtRs5.setText(rs.getString("5"));
                        txtRs10.setText(rs.getString("10"));
                        txtRs20.setText(rs.getString("20"));
                        txtRs50.setText(rs.getString("50"));
                        txtRs100.setText(rs.getString("100"));
                        txtRs500.setText(rs.getString("500"));
                        txtRs1000.setText(rs.getString("1000"));
                    }

               } catch (Exception e) {
                         JOptionPane.showMessageDialog(null, e.getMessage());
                     }
        }


    }

您需要在调用executeQuery后调用ResultSet.next：

while (rs.next()) {
...