Java 如何在扫描仪中设置无限循环？

我是Java的初学者，所以我有一个问题 我正在尝试创建一个简单的代码，我已经完成了，我只是想知道如何设置一个用户可以输入的无限提问问题？我现在有一个无限循环，这是没有帮助的

    import java.util.Scanner;
    public class Logical_Operators {
    
        public static void main(String[] args) {
            // TODO Auto-generated method stub
    
            Scanner input = new Scanner(System.in);
            
            //this is a conditional scenario, where only boys above the age of 18 can enter
            //and only girls equal to or over the age of 20 
            
            String gender, boy, girl, response;
            int age;
            
            System.out.println("Welcome to the party! Would you like to enter?");
            response = input.nextLine();
        
        while(!response.equals("yes") && !response.equals("no"))    {
            System.out.println("Please say Yes or No");
        }
        {
            
            if(response.equals("yes"))  {       
                
                System.out.println("What gender are you? Type boy or girl.");
                gender = input.nextLine();
                
                System.out.println("What about your age?");
                age = input.nextInt();
                
                    if(gender.equals("boy") && age >= 18)   {
                    System.out.println("You can enter, Welcome!"); 
                    
                }
                    else if(gender.equals("girl") && age >= 20) {
                    System.out.println("You can enter, Welcome!");  }
                 
                    else { System.out.println("Sorry, you may not enter because you don't meet the age requirements");  }
                
            }
            
            else if(!(response.equals("yes")||response.equals("no")))   {
                System.out.println("Please say Yes or No");
                
            }
            
            else { 
                System.out.println("Bye, hope to see you again!");
            }
            
        System.exit(1);
        }
            
        }
    
    }

---

为了跳出循环，您需要获得一个新的值进行测试

response = input.nextLine();

while(!response.equals("yes") && !response.equals("no"))    {
    System.out.println("Please say Yes or No");
    response = input.nextLine();
}

您需要将逻辑放在代码中当前没有的循环中。在您的代码中，只有

System.out.println（“请说是或否”）在循环中

您可以使用无限循环（即

while（true）{}

），当输入与退出条件匹配时，您可以

中断该循环

另外，我建议您使用

equalsIgnoreCase

而不是

equals

以不区分大小写的方式测试相等性

我还建议您使用

age=Integer.parseInt（input.nextLine（））

而不是

age=input.nextInt（）

，以避免讨论的问题

演示：

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);

        // this is a conditional scenario, where only boys above the age of 18 can enter
        // and only girls equal to or over the age of 20

        String gender, response;
        int age;

        while (true) {
            System.out.println("Welcome to the party! Would you like to enter?");
            System.out.print("Please say Yes or No: ");
            response = input.nextLine();
            if (response.equalsIgnoreCase("no")) {
                System.out.println("Bye, hope to see you again!");
                break;
            }

            if (response.equalsIgnoreCase("yes")) {
                System.out.print("What gender are you? Type boy or girl: ");
                gender = input.nextLine();

                System.out.print("What about your age?: ");
                age = Integer.parseInt(input.nextLine());

                if (gender.equalsIgnoreCase("boy") && age >= 18) {
                    System.out.println("You can enter, Welcome!");
                } else if (gender.equalsIgnoreCase("girl") && age >= 20) {
                    System.out.println("You can enter, Welcome!");
                } else {
                    System.out.println("Sorry, you may not enter because you don't meet the age requirements");
                }
            }
        }
    }
}

Welcome to the party! Would you like to enter?
Please say Yes or No: yes
What gender are you? Type boy or girl: boy
What about your age?: 24
You can enter, Welcome!
Welcome to the party! Would you like to enter?
Please say Yes or No: yes
What gender are you? Type boy or girl: girl
What about your age?: 19
Sorry, you may not enter because you don't meet the age requirements
Welcome to the party! Would you like to enter?
Please say Yes or No: yes
What gender are you? Type boy or girl: girl
What about your age?: 21
You can enter, Welcome!
Welcome to the party! Would you like to enter?
Please say Yes or No: no
Bye, hope to see you again!

运行示例：

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);

        // this is a conditional scenario, where only boys above the age of 18 can enter
        // and only girls equal to or over the age of 20

        String gender, response;
        int age;

        while (true) {
            System.out.println("Welcome to the party! Would you like to enter?");
            System.out.print("Please say Yes or No: ");
            response = input.nextLine();
            if (response.equalsIgnoreCase("no")) {
                System.out.println("Bye, hope to see you again!");
                break;
            }

            if (response.equalsIgnoreCase("yes")) {
                System.out.print("What gender are you? Type boy or girl: ");
                gender = input.nextLine();

                System.out.print("What about your age?: ");
                age = Integer.parseInt(input.nextLine());

                if (gender.equalsIgnoreCase("boy") && age >= 18) {
                    System.out.println("You can enter, Welcome!");
                } else if (gender.equalsIgnoreCase("girl") && age >= 20) {
                    System.out.println("You can enter, Welcome!");
                } else {
                    System.out.println("Sorry, you may not enter because you don't meet the age requirements");
                }
            }
        }
    }
}

Welcome to the party! Would you like to enter?
Please say Yes or No: yes
What gender are you? Type boy or girl: boy
What about your age?: 24
You can enter, Welcome!
Welcome to the party! Would you like to enter?
Please say Yes or No: yes
What gender are you? Type boy or girl: girl
What about your age?: 19
Sorry, you may not enter because you don't meet the age requirements
Welcome to the party! Would you like to enter?
Please say Yes or No: yes
What gender are you? Type boy or girl: girl
What about your age?: 21
You can enter, Welcome!
Welcome to the party! Would you like to enter?
Please say Yes or No: no
Bye, hope to see you again!

---

请修正你源代码的缩进，这使它更容易阅读（特别是对你来说）。嗨，谢谢你的回复，它成功了。但是有没有一种方法可以让我对性别和年龄做同样的事情呢？就像无限循环一样。我尝试过使用相同的方法，但即使我输入男孩或女孩，它也会继续问这个问题。你应该能够使用完全相同的逻辑。记住用你要求的新术语替换“是”和“否”