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Java中的多线程排序动画_Java_Multithreading_Sorting_Animation - Fatal编程技术网

Java中的多线程排序动画

Java中的多线程排序动画,java,multithreading,sorting,animation,Java,Multithreading,Sorting,Animation,因此,我正在编写一个程序,它使用一种线图类型的东西来设置插入排序算法的动画。 按照现在编写的方式,当单击“填充”按钮时,它将生成一个随机整数数组,并根据代表线绘制一个DrawingPanel,当单击“暂停”按钮时,它将冻结5秒钟,然后显示排序的图形。我想显示每个迭代,每次显示一行。任何建议。我真的不知道如何在Java中使用多线程,我是个新手。如果有任何建议,我将不胜感激 import java.awt.*; import java.awt.event.*; import java.util.Ar

因此,我正在编写一个程序,它使用一种线图类型的东西来设置插入排序算法的动画。 按照现在编写的方式,当单击“填充”按钮时,它将生成一个随机整数数组,并根据代表线绘制一个DrawingPanel,当单击“暂停”按钮时,它将冻结5秒钟,然后显示排序的图形。我想显示每个迭代,每次显示一行。任何建议。我真的不知道如何在Java中使用多线程,我是个新手。如果有任何建议,我将不胜感激

import java.awt.*;
import java.awt.event.*;
import java.util.ArrayList;
import javax.swing.*;
import java.util.Random;
import java.util.Arrays;

public class AnimationApplication extends JFrame {

private static final long serialVersionUID = 1L;

AnimationPanel panel1 = new AnimationPanel();
AnimationPanel panel2 = new AnimationPanel();

public static void main(String[] args) {
    AnimationApplication prog = new 
     AnimationApplication("Animation Application");

    prog.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    prog.setSize(450, 300);
    prog.setVisible(true);
}

AnimationApplication(String title) {
    super(title);

    setLayout(new BorderLayout());

    add(panel1, BorderLayout.WEST);
    add(panel2, BorderLayout.EAST);
}
}

class AnimationPanel extends JPanel implements ActionListener, Runnable {

private static final long serialVersionUID = 1L;

private int currentSize;

private JButton populate = new JButton("Populate Array");
private JButton pauseB = new JButton("Pause");
private JButton stopB = new JButton("Stop");
private DrawingPanel drawingCanvas = new DrawingPanel();

private volatile Thread animator = null;
private volatile boolean animationSuspended = false;

ArrayList<Integer> pointList = new ArrayList<Integer>();

private Integer [] rndInts;

AnimationPanel() {
    setLayout(new BorderLayout());

    JPanel buttonP = new JPanel(new GridLayout(1, 3, 5, 5));
    buttonP.add(populate);
    buttonP.add(pauseB);
    buttonP.add(stopB);

    populate.addActionListener(this);
    pauseB.addActionListener(this);
    stopB.addActionListener(this);

    add(drawingCanvas, BorderLayout.CENTER);
    add(buttonP, BorderLayout.SOUTH);
}

public void actionPerformed(ActionEvent e) {

    if (e.getSource() == populate) {

                        rndInts = new Integer[ getSize().width-1];


                        for(int i = 0; i < rndInts.length; i++)
  {
    Random rand = new Random();
    rndInts[i]=rand.nextInt((getSize().height)-1);
  //  System.out.println(rndInts[i]);
  }

  currentSize = rndInts.length;               

       pointList = new ArrayList<Integer>(Arrays.asList(rndInts));                



        //System.out.println("Start button pressed");

        // Check if no animation thread exists
        if (animator == null) {

            // If not, start the animation
            start();


        } else {
            // If animation is paused, resume it
            if (animationSuspended) {
                resume();
            }
        }

    } else if (e.getSource() == pauseB) {
        insertionSort(rndInts , currentSize);
        // Check if animation thread exists
        if (animator != null) {

            // If so, suspend the animation thread
            animationSuspended = true;
        }

    } else if (e.getSource() == stopB) {
        stop();
        clear();
    }

}

public void run() {

    Thread thisThread = Thread.currentThread();

    drawingCanvas.repaint();
    while (animator == thisThread) {
        //System.out.println("Animation thread running");
      drawingCanvas.repaint();
        try {
          //  Thread.sleep(1);
 drawingCanvas.repaint();
            if (animationSuspended) {
                synchronized (this) {
                    while (animationSuspended && animator == thisThread) {
                        drawingCanvas.repaint();
                        wait();
                        drawingCanvas.repaint();
                    }
                }
            }
        } catch (InterruptedException e) {
            break;
        }

        // Repaint the panel
        drawingCanvas.repaint();
    }

}

public void start() {
drawingCanvas.repaint();
    // Create a new animation thread and start it
    animator = new Thread(this);
    animationSuspended = false;
    animator.start();
    animationSuspended = true;
 }




public synchronized void stop() {
    drawingCanvas.repaint();
    animator = null;
    notify();
}

public synchronized void resume() {
    animationSuspended = false;
    notify();
}

public void clear() {
    pointList.clear();
    repaint();
}


void insertionSort(Integer [] arr, int length) 
{
  int i, j, tmp;
  for (i = 1; i < length; i++) 
{
        j = i;
        while (j > 0 && arr[j - 1] > arr[j]) 
{
              tmp = arr[j];
              arr[j] = arr[j - 1];
              arr[j - 1] = tmp;
              j--;
              stop();
              drawingCanvas.repaint();
              start();
              //resume();
        }

  }
}



class DrawingPanel extends JPanel implements Runnable {

    private static final long serialVersionUID = 1L;

    protected void paintComponent(Graphics g) {





        // Call superclass version of method
        super.paintComponent(g);

        this.setBackground(Color.WHITE);

        //clear the background
        g.clearRect(0, 0, getSize().width-1, getSize().height-1);

        g.setColor(Color.RED);



        // Draw points
        for (int i = 0; i < currentSize ; i++) //pointList.size(); i++) 
        {
          g.drawLine(i, getSize().height, i, rndInts[i]);
          repaint();
            //resume(); 
        }
      }
    }

}
我认为这个代码就是问题所在,在一个循环中启动;他被打了好几次电话。请调试并了解如何进行重构。

一些建议:

一,。您不需要,更具体地说,不希望为此使用多线程

二,。除了重新绘制之外,对Swing方法的所有访问都必须在事件队列上。事实上,从个人经验来看,Swing在99.999%的时间里都能正常工作,但这0.001%就是谋杀!即使没有线程,您的主方法也不在事件队列上,因此请启动如下操作:

EventQueue.InvokeLater( new Runnable()  {
    AnimationApplication prog = new AnimationApplication( "Animation Application" );
    prog.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    prog.setSize(450, 300);
    prog.setVisible(true);
} );
三,。使用摆动计时器让您完成每一步。从“填充”按钮开始,如果可以,暂停它;如果不能,停止它,重新创建它;我已经有一段时间没有使用它了,暂停按钮让我的记忆力变差。Swing计时器与您可以使用的其他任何东西(如AWT计时器)不同,它在EventQueue上运行其事件

四,。编写一个执行排序的一个步骤的方法。然后在每个计时器事件中调用它一次,以便在每个事件中执行排序的一个步骤,然后更新显示

更一般地说,您必须使您的显示工作在UI事件、按钮按下和计时器事件上,而不是当前排序代码的进度上。你的排序需要从里到外,就像它一样,随着用户界面的节奏起舞,而不是快速排序。现在的代码执行速度太快,一个线程无法看到另一个线程在做什么。

另请参见此。class DrawingPanel extends JPanel实现可运行此类未实现运行方法,请使用IDE,这将告诉您此问题。请参阅此网页:
EventQueue.InvokeLater( new Runnable()  {
    AnimationApplication prog = new AnimationApplication( "Animation Application" );
    prog.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    prog.setSize(450, 300);
    prog.setVisible(true);
} );