Java 如何根据在listview中单击的项目启动新活动?
我已经被困在这2天了,我不明白为什么下面的代码不工作,问题似乎是“如果”块上的onItemClick,请我真的很感激如果有人能帮我解决这个问题。谢谢Java 如何根据在listview中单击的项目启动新活动?,java,android,listviewitem,start-activity,Java,Android,Listviewitem,Start Activity,我已经被困在这2天了,我不明白为什么下面的代码不工作,问题似乎是“如果”块上的onItemClick,请我真的很感激如果有人能帮我解决这个问题。谢谢 listView.setOnItemClickListener(new AdapterView.OnItemClickListener() { @Override public void onItemClick(AdapterView<?> parent, View view, int
listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
String name = parent.getItemAtPosition(position).toString();
Toast.makeText(SearchActivity.this, name,Toast.LENGTH_LONG).show();
if (name=="Sweet Tooth"){
Intent intent = new Intent(SearchActivity.this,SwitActivity.class);
startActivity(intent);
}
}
});
listView.setOnItemClickListener(新的AdapterView.OnItemClickListener(){
@凌驾
public void onItemClick(AdapterView父对象、视图、整型位置、长id){
字符串名称=parent.getItemAtPosition(position).toString();
Toast.makeText(SearchActivity.this,name,Toast.LENGTH_LONG.show();
如果(姓名==“甜食”){
意向意向=新意向(SearchActivity.this、SwitActivity.class);
星触觉(意向);
}
}
});
在java字符串中==String将始终返回false
用这个代替
String s = "Sweet Tooth";
if (s.equals("Sweet Tooth"){
//code
}
试试这个:
String name = listview.getItemAtPosition(position).toString();
及
在Java中,使用
equals
函数比较两个字符串
String name = parent.getItemAtPosition(position).toString();
if (name.equals("Sweet Tooth")){
startActivity(new Intent(SearchActivity.this,SwitActivity.class));
}
String name = parent.getItemAtPosition(position).toString();
if (name.equals("Sweet Tooth")){
startActivity(new Intent(SearchActivity.this,SwitActivity.class));
}