如何在java函数中返回预期的异常:java.util.InputMismatchException
这是我的职责如何在java函数中返回预期的异常:java.util.InputMismatchException,java,exception,Java,Exception,这是我的职责 public Object check(long number) { long root = 0; while (number > 0 || root > 9) { if (number == 0) { number = root; root = 0; }
public Object check(long number) {
long root = 0;
while (number > 0 || root > 9) {
if (number == 0) {
number = root;
root = 0;
}
root += number % 10;
number /= 10;
}
return root;
}
**我想通过这个测试用例我如何解决它**
@Test(expected = InputMismatchException.class)
public void testInvalidInput() {
digitalRoot.check(-87625L);
}
您可以更改错误消息以提供更多上下文。这将不会进入while循环。抛出异常的条件是什么?在方法的开头,如果(number<0)抛出新的inputmaschException(),则需要
if代码>
if (number < 0) throw new InputMismatchException(number + "");
Exception in thread "main" java.util.InputMismatchException: -87625