Java 休眠：选择OneToMany关系中的位置

以下是我的缩写实体：

@Entity
public class User {

    @OneToMany(fetch=FetchType.LAZY)
    @JoinTable(name="user_items",joinColumns=@JoinColumn(name="user_id"),inverseJoinColumns=@JoinColumn(name="useritem_id"))
    private Set<UserItem> items = Sets.newHashSet();

}


@Entity
@Inheritance(strategy=InheritanceType.JOINED)
public class UserItem {

    @Id
    @Type(type=EntityConstants.TYPE_UUID)
    @Column(columnDefinition=EntityConstants.COL_UUID)
    private UUID id;

}

@Entity
public class UserItemFurniture extends UserItem {

}

但它产生了这种荒谬的SQL：

select useritemfu0_.id as id17_, useritemfu0_1_.item as item17_, useritemfu0_.roomNumber as roomNumber18_, useritemfu0_.x as x18_, useritemfu0_.y as y18_
from UserItemFurniture useritemfu0_ inner join UserItem useritemfu0_1_ on useritemfu0_.id=useritemfu0_1_.id
where useritemfu0_.id=? and (useritemfu0_.id in (
    select .
    from _User user1_, user_items items2_, UserItem useritem3_
    where user1_.id=items2_.user_id and items2_.useritem_id=useritem3_.id and user1_.id=?
))
limit ?

注意子查询：SELECT

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我可以在不使用本机或多个查询的情况下执行此操作吗？请注意，UserItem没有对用户的引用，这是出于设计考虑。

可以使用以下查询：

SELECT f
FROM UserItemFurniture f
WHERE f.id = :uid AND EXISTS 
  (SELECT u FROM User u
   WHERE u.id = :iid and f MEMBER OF u.items)

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你试过在条款中用id限制吗？类似于从用户选择u.items.id中的…和f.id…不可能使用u.items.id，因为作为集合值路径的项引用整个集合，因此它没有属性id，即使集合元素也没有属性id。

SELECT f
FROM UserItemFurniture f
WHERE f.id = :uid AND EXISTS 
  (SELECT u FROM User u
   WHERE u.id = :iid and f MEMBER OF u.items)