Java 如何读取txt文件，并使用其中的双值？
我有这样一个.txt文件：它实际上更长Java 如何读取txt文件，并使用其中的双值？,java,android,text-files,Java,Android,Text Files,我有这样一个.txt文件：它实际上更长 5.4167707e-02 7.4330113e-02 1.3307861e-01 1.1399230e-01 9.7865982e-02 -4.5091141e-02 5.4978066e-02 1.9342541e-01 1.3783929e-01 这是一行字符串。我需要读取文件并在计算中使用这些值。这些值应该类似于输入[i] 以下是我目前的代码： public class MainActivity extends
5.4167707e-02 7.4330113e-02 1.3307861e-01 1.1399230e-01 9.7865982e-02 -4.5091141e-02 5.4978066e-02 1.9342541e-01 1.3783929e-01
public class MainActivity extends AppCompatActivity {
AudioAnalyzer aa = new AudioAnalyzer();
BufferedReader brinput = null , brbandpass = null;
InputStream isinput = null, isbandpass = null;
InputStreamReader isrinput = null, isrbandpass = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
public void analyzer (View view) throws FileNotFoundException{
try {
isinput = new FileInputStream("/storage/sdcard/input.txt");
isbandpass = new FileInputStream("/storage/sdcard/bandpass.txt");
isrinput = new InputStreamReader(isinput);
isrbandpass = new InputStreamReader(isbandpass);
brinput = new BufferedReader(isrinput);
brbandpass = new BufferedReader(isrbandpass);
//reads to the end of the stream
int i;
int f;
while ((i = brinput.read()) != -1) {
f = brbandpass.read();
double input = (double)i; // int to double
double filtered = (double)f;
String working = "The filter works!";
String notworking = "Try again. The filter does not work!";
TextView t = (TextView) findViewById(R.id.textView);
if (aa.analyze(in, fil) = true) // Analyze is the methode I want to use the values for
t.setText(working);
else
t.setText(notworking);
} catch (IOException e) {
e.printStackTrace();
}
}
double filtered = (double)f;
if (aa.analyze(input, filtered) = true)
public class AudioAnalyzer {
private IIRFilter bandpass, lowpass;
final double[] b1 = {0.0286, 0, -0.0859, 0, 0.0859, 0, -0.0286};
final double[] a1 = {-3.9320, 6.8170, -6.7455, 4.0453, -1.3889, 0.2120};
public AudioAnalyzer() {
bandpass = new IIRFilter(b1, a1);
}
public boolean analyze(double[] inputFilter, double[] outputFilter) {
int i;
boolean work;
double[] w;
double g1[] = new double[inputFilter.length];
for (i = 0; i < inputFilter.length; i++) {
double f1 = inputFilter[i];
g1[i] = outputFilter[i]-(bandpass.filter(f1));
for ( i = 0;i < g1.length; i++)
w[i] = g1[i]-outputFilter[i];
if (w[i] == 0)
work = true;
return work;
}
public class IIRFilter {
private final double[] b;
private final double[] a;
private double[] g; //g(n) = output
private double[] f; //f(n) = input
public IIRFilter(double[] b, double[] a) {
this.a = a;
this.b = b;
g = new double[a.length];
f = new double[b.length];
Arrays.fill(g, 0.0);
Arrays.fill(f, 0.0);
}
public double filter(double f0) {
// change the values' positions in the buffer f
int s;
for (s=f.length-1;s>0; s--){
f[s] = f[s-1];
}
f[0] = f0;
//filter equation
int n;
double gt;
double ht;
ht = 0.0;
gt = 0.0;
for (n = 0; n < b.length; n++) {
ht += b[n] * f[n];
}
for (n = 0; n < a.length; n++) {
gt -= a[n] * g[n];
}
// change the values' positions in the buffer g
for ( s=g.length; s>0; s--){
g[s] = g[s-1];
}
g[0] = ht+gt;
return g[0];
}
}
public class AudioAnalyzer {
private IIRFilter bandpass, lowpass;
final double[] b1 = {0.0286, 0, -0.0859, 0, 0.0859, 0, -0.0286};
final double[] a1 = {-3.9320, 6.8170, -6.7455, 4.0453, -1.3889, 0.2120};
public AudioAnalyzer() {
bandpass = new IIRFilter(b1, a1);
}
public boolean analyze(double[] inputFilter, double[] outputFilter) {
int i;
double g1[] = new double[inputFilter.length];
for (i = 0; i < inputFilter.length; i++) {
double f1 = inputFilter[i];
g1[i] = outputFilter[i]-(bandpass.filter(f1));
for (i = 0; i < g1.length; i++){
if (( g1[i]-outputFilter[i] != 0))
return false;
}
return true;
}
}
首先，=true不会做你想做的事。在if语句中，即使与true进行比较也是多余和不必要的。错误消息非常清晰且不言自明。你能提供更多关于你不理解的细节吗？关于错误，是的；从未初始化。你希望双f做什么？为什么不把f作为一个双精度数组开始呢？既然你还没有展示过AudioAnalyzer，我们就不能告诉你，但是这种分析方法显然接受两个双精度数组，而不仅仅是两个双精度值。实际上你的问题是你没有读取分析过的数据来检查analyzer功能是否正常工作。对于更清晰的代码，您可以使用3个while方法来读取数字列表，第一个是list to list of input.txt，第二个是bandpass.txt，第三个是进行分析，如果我得到了未解析的“readFile”，则使用==on。我猜你指的是“阅读”方法？2无法解析“添加”、“toArray”和“大小”。我应该为此导入哪个util？3对于'List'，我得到的类型参数不能是基元typePerfect！无错误。非常感谢。在运行应用程序之前，我仍然需要使用我的分析方法。我的“w”和“work”变量据说尚未初始化。应用程序已启动，但textView未给出任何信息。请检查logcat以查看e上是否有错误。printStackTraceThere对此没有错误。我在错误中只找到了这个：找不到从方法android.support.v7.widget.AppCompatImageHelper.hasOverlappingRendering引用的类“android.graphics.drawable.RippleDrawable”
public class AudioAnalyzer {
private IIRFilter bandpass, lowpass;
final double[] b1 = {0.0286, 0, -0.0859, 0, 0.0859, 0, -0.0286};
final double[] a1 = {-3.9320, 6.8170, -6.7455, 4.0453, -1.3889, 0.2120};
public AudioAnalyzer() {
bandpass = new IIRFilter(b1, a1);
}
public boolean analyze(double[] inputFilter, double[] outputFilter) {
int i;
double g1[] = new double[inputFilter.length];
for (i = 0; i < inputFilter.length; i++) {
double f1 = inputFilter[i];
g1[i] = outputFilter[i]-(bandpass.filter(f1));
for (i = 0; i < g1.length; i++){
if (( g1[i]-outputFilter[i] != 0))
return false;
}
return true;
}
}