Java 猜数字

我想创建一个程序，让你三次尝试找到任何给定的数字。这本质上是一场猜谜游戏。问题是，我必须在没有任何循环的情况下完成这项工作。到目前为止，我只能从用户那里获得输入，阅读输入并告诉他们是否赢了或“输了”游戏。程序只运行一次，并按预期停止

有人告诉我，它可以在没有循环的情况下完成，尽管需要更多的代码。你们能让我知道我做错了什么，并给我一些我应该改变的建议吗？如果你需要澄清，请告诉我。 谢谢

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您可以使用递归来实现这一点。看这个节目。在评论中找到解释

import java.util.Scanner;

public class HelloWorld {

    private static Scanner ran = new Scanner(System.in);

    //this is number of tries you want to give to user
    private static int counter = 5;

    //The actual number
    private static final int NUM = 3;

    public static boolean guessingMachine() {
        //counter indicates that number of attempts remaining
        if(counter == 0) {
            return false;
        }
        counter--;

        System.out.println("Enter a number: ");
        int x = ran.nextInt();

        if (x < NUM) {
            System.out.println("Too low. Try again.");
            //try again... call this method again
            return guessingMachine();
        } else if (x > NUM) {
            System.out.println("Too high. Try again");
            //try again... call this method again
            return guessingMachine();
        } else {
            //x == NUM success
            return true;
        }
    }


    public static void main(String[] args) {
        boolean result = guessingMachine();

        if(result) 
            System.out.println("You win. Nice job.");
        else 
            System.out.println("You lose");

        System.out.println("Number Guessing Game (c) 2017 Anna Gibson");
    }
}

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您可以在下列条件下：

get user input
if input is correct, congratulation user and exit
    else
        get user input //second attempt
        if input is correct, congratulation user and exit
...

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你可以从那里继续。您提供的代码（告诉用户它们是否过高或过低）必须包含在上述伪代码的每个分支中。

我认为本练习的主要目的是加强嵌套的if-else概念

import java.util.Scanner;

公共类HelloWorld{

 public static void main(String []args){
    int num=3;
    int count=1;
    Scanner ran = new Scanner(System.in);
    System.out.println("Enter a number: ");
    int x = ran.nextInt();

    if(x>num || x<num)
    {
        System.out.println("incorrect guess");
        count++;
        System.out.println("Enter a number: ");
         x = ran.nextInt();
         if(x>num || x<num)
         {
              System.out.println("incorrect guess");
              count++;
                          System.out.println("Enter a number: ");
                           x = ran.nextInt();
                           if(x>num || x<num)
                           {
                               System.out.println("incorrect guess YOU LOSE");
                           }
                           else
                           {
                                               System.out.println("YOU WIN");
                           }
         }
         else
         {
               System.out.println("YOU WIN");
         }

    }

    if(x==num && count==1)
    {
        System.out.println("YOU WIN");
    }

    System.out.println("Number Guessing Game (c) 2017 Anna Gibson");
 }
}

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您可以使用递归，也可以将猜测代码放在自己的代码中​ 静态方法，并连续调用三次。虽然我真的怀疑不使用循环在任何方面都是有益的……用户猜测的数字是如何选择的？我本来打算自己设置数字，因此x==3，但我感觉我做得不对。

 public static void main(String []args){
    int num=3;
    int count=1;
    Scanner ran = new Scanner(System.in);
    System.out.println("Enter a number: ");
    int x = ran.nextInt();

    if(x>num || x<num)
    {
        System.out.println("incorrect guess");
        count++;
        System.out.println("Enter a number: ");
         x = ran.nextInt();
         if(x>num || x<num)
         {
              System.out.println("incorrect guess");
              count++;
                          System.out.println("Enter a number: ");
                           x = ran.nextInt();
                           if(x>num || x<num)
                           {
                               System.out.println("incorrect guess YOU LOSE");
                           }
                           else
                           {
                                               System.out.println("YOU WIN");
                           }
         }
         else
         {
               System.out.println("YOU WIN");
         }

    }

    if(x==num && count==1)
    {
        System.out.println("YOU WIN");
    }

    System.out.println("Number Guessing Game (c) 2017 Anna Gibson");
 }
}