Java 使用Parse获取其他查询列

我正试图使用Parse SDK在我的Android应用程序中实现一个注册/登录系统

到目前为止，我已经使注册和登录成为可能

我要查找的是在另一个活动上显示其他用户凭据（例如，first_name或last_name）

这是我的代码：

LoginActivity.java

//Read user information as String.
String email = etEmail.getText().toString();
String password = etPassword.getText().toString();

//Find user by Email and Password.
ParseQuery<ParseObject> query = ParseQuery.getQuery("Users");

query.whereEqualTo("email", email);
query.whereEqualTo("password", password);
query.findInBackground(new FindCallback<ParseObject>() {
  public void done(List<ParseObject> users, ParseException e) {

    if (e == null) {
       //User logged in successful.
       Toast.makeText(LoginActivity.this, "Welcome back!", Toast.LENGTH_SHORT).show();
       //Take user to FeedActivity.
       startActivity(new Intent(LoginActivity.this, FeedActivity.class));
    } else {
       //User login failed.
       Toast.makeText(LoginActivity.this, "Login failed.", Toast.LENGTH_SHORT).show();
       e.printStackTrace();
    }
  }
});

            //Store user information in String.
            String firstname = etFirstname.getText().toString();
            String lastname = etLastname.getText().toString();
            String email = etEmail.getText().toString();
            String password = etPassword.getText().toString();
            int userID = count.getAndIncrement();

            ParseObject Users = new ParseObject("Users");
            Users.put("userID", userID);
            Users.put("first_name", firstname);
            Users.put("last_name", lastname);
            Users.put("email", email);
            Users.put("password", password);
            Users.saveInBackground(new SaveCallback() {
                @Override
                public void done(ParseException e) {
                    if (e == null) {
                        //User registered successfully.
                        Toast.makeText(RegisterActivity.this, "Registration successful."
                                , Toast.LENGTH_SHORT).show();
                        //Take user to LoginActivity.
                        startActivity(new Intent(RegisterActivity.this, LoginActivity.class));
                    } else {
                        Toast.makeText(RegisterActivity.this, "Registration failed."
                                , Toast.LENGTH_SHORT).show();
                        e.printStackTrace();
                    }
                }
            });

---

您可能需要检查通过

Intent

发送数据

因此，在第一个活动中，您可以这样做：

Intent i = new Intent(FirstActivity.this, SecondActivity.class);
i.putExtra("label", "My name, yo!");
startActivity(i);

在第二项活动中：

Intent d = getIntent();
String s = d.getStringExtra("label");

---

或者你也可以这样说：

如果我没弄错，你想要的是：

if (ParseUser.getCurrentUser() != null) {
        String user = ParseUser.getCurrentUser().getObjectId();
        ParseQuery<ParseObject> query = ParseQuery.getQuery("User");
        query.whereEqualTo("objectId",user);
        query.findInBackground(new FindCallback<ParseObject>() {
            public void done(List<ParseObject> objects, ParseException e) {
                if (e == null) {
                    for (final ParseObject post : objects) {
                        // Put Data in TextBoxes
                        // String first_name = post.getString("first_name"); - Will return first Name
                    }
                }
            }
        });

    } else {
        //Log in the User
    }

if（ParseUser.getCurrentUser（）！=null）{
字符串user=ParseUser.getCurrentUser（）.getObjectId（）；
ParseQuery=ParseQuery.getQuery（“用户”）；
查询。whereEqualTo（“objectId”，用户）；
findInBackground（新的FindCallback（）{
公共void done（列出对象，parsee异常）{
如果（e==null）{
for（最终解析对象post:objects）{
//将数据放入文本框中
//String first_name=post.getString（“first_name”）；-将返回first name
}
}
}
});
}否则{
//登录用户
}