Java hibernate更新JPA外键
我的jpa如下所示Java hibernate更新JPA外键,java,hibernate,jpa,Java,Hibernate,Jpa,我的jpa如下所示 public class TESTClass implements Serializable { ... private String name; @EmbeddedId protected IssTESTPK issTESTPK; @ManyToOne(optional=false) @JoinColumns({ @JoinColumn(name="DIVISION_CODE", referencedC
public class TESTClass implements Serializable {
...
private String name;
@EmbeddedId
protected IssTESTPK issTESTPK;
@ManyToOne(optional=false)
@JoinColumns({
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE", nullable=false, insertable=false, updatable=false),
@JoinColumn(name="SURVEY_NUM", referencedColumnName="SURVEY_NUM", nullable=false, insertable=false, updatable=false)})
private IssDivision issDivision;
}
若我更改“name”并调用merge,它可以更新到数据库中,但当我更改issDivision并调用merge时,它不会更新数据库。如何解决这个问题
因为我使用的是EmbeddedId(复合主键),所以它是否与相关 更新 如果我设置upadted=true,我会得到以下错误
ERROR - ContextLoader.initWebApplicationContext(215) | Context initialization fa
iled
org.springframework.beans.factory.BeanCreationException: Error creating bean wit
h name 'sessionFactory' defined in ServletContext resource [/WEB-INF/application
Context.xml]: Invocation of init method failed; nested exception is org.hibernat
e.MappingException: Repeated column in mapping for entity: com.compay.test.model
.TESTClass column: SURVEY_NUM (should be mapped with insert="false" update="fa
lse")
at org.springframework.beans.factory.support.AbstractAutowireCapableBean
Factory.initializeBean(AbstractAutowireCapableBeanFactory.java:1338)
at org.springframework.beans.factory.support.AbstractAutowireCapableBean
Factory.doCreateBean(AbstractAutowireCapableBeanFactory.java:473)
at org.springframework.beans.factory.support.AbstractAutowireCapableBean
Factory$1.run(AbstractAutowireCapableBeanFactory.java:409)
at java.security.AccessController.doPrivileged(Native Method)
at org.springframework.beans.factory.support.AbstractAutowireCapableBean
Factory.createBean(AbstractAutowireCapableBeanFactory.java:380)
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getOb
ject(AbstractBeanFactory.java:264)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistr
y.getSingleton(DefaultSingletonBeanRegistry.java:222)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBe
an(AbstractBeanFactory.java:261)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean
(AbstractBeanFactory.java:185)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean
(AbstractBeanFactory.java:164)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.
preInstantiateSingletons(DefaultListableBeanFactory.java:423)
at org.springframework.context.support.AbstractApplicationContext.finish
BeanFactoryInitialization(AbstractApplicationContext.java:728)
at org.springframework.context.support.AbstractApplicationContext.refres
h(AbstractApplicationContext.java:380)
at org.springframework.web.context.ContextLoader.createWebApplicationCon
text(ContextLoader.java:255)
at org.springframework.web.context.ContextLoader.initWebApplicationConte
xt(ContextLoader.java:199)
at org.springframework.web.context.ContextLoaderListener.contextInitiali
zed(ContextLoaderListener.java:45)
at org.apache.catalina.core.StandardContext.listenerStart(StandardContex
t.java:3843)
at org.apache.catalina.core.StandardContext.start(StandardContext.java:4
342)
at org.apache.catalina.core.ContainerBase.addChildInternal(ContainerBase
.java:791)
at org.apache.catalina.core.ContainerBase.addChild(ContainerBase.java:77
1)
at org.apache.catalina.core.StandardHost.addChild(StandardHost.java:525)
at org.apache.catalina.startup.HostConfig.deployDescriptor(HostConfig.ja
va:627)
at org.apache.catalina.startup.HostConfig.deployDescriptors(HostConfig.j
ava:553)
at org.apache.catalina.startup.HostConfig.deployApps(HostConfig.java:488
)
at org.apache.catalina.startup.HostConfig.start(HostConfig.java:1149)
at org.apache.catalina.startup.HostConfig.lifecycleEvent(HostConfig.java
:311)
at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(Lifecycl
eSupport.java:117)
at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1053)
at org.apache.catalina.core.StandardHost.start(StandardHost.java:719)
at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:443
)
at org.apache.catalina.core.StandardService.start(StandardService.java:5
16)
at org.apache.catalina.core.StandardServer.start(StandardServer.java:710
)
at org.apache.catalina.startup.Catalina.start(Catalina.java:578)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.
这是因为您使用的是
updateable=false
。删除它可能会导致其他问题,我不能假设不知道完整的映射
在
embedded
类中将updateable
和insertable
设置为false
,并将它们从联接列中删除我找到了一个解决方法,但我想听听大家是否可以使用此技术。我将实体类修改为
public class TESTClass implements Serializable {
...
private String name;
@EmbeddedId
protected IssTESTPK issTESTPK;
@JoinColumns({@JoinColumn(name = "DIVISION_CODE", referencedColumnName = "DIVISION_CODE", nullable = false , insertable = false, updatable = false), @JoinColumn(name = "SURVEY_NUM", referencedColumnName = "SURVEY_NUM", nullable = false, insertable = false, updatable = false)})
@ManyToOne(optional = false)
private IssDivision issDivision; //since this is not merge
@Basic(optional = false)
@Column(name = "DIVISION_CODE")
private String divisionCode; //i add this
}
我添加了'divisionCode'属性,即使它在issDivision对象中重复。但这是我在合并过程中能够更新“DIVISION_CODDE”的变通方法
您的例外(和著名)消息是
repeated column in mapping for entity:
column: SURVEY_NUM (should be mapped with insert="false" update="false")
“调查数量”栏目在哪里
1分区字段存储一个外键列,称为SURVEY_NUM
@ManyToOne
@JoinColumns({
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE", insertable=false, updatable=false),
@JoinColumn(name="SURVEY_NUM", referencedColumnName="SURVEY_NUM", insertable=false, updatable=false)})
private IssDivision issDivision;
现在,查看以下映射(查看id和accountNumber共享同一列)
现在让我们做如下事情
Account account = new Account();
account.setId(127359);
account.setAccountNumber(null);
entityManager.persist(account);
// Employee.java
@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE", insertable=false, updatable=false),
@JoinColumn(name="SURVEY_NUMBER", referencedColumnName="SURVEY_NUMBER", insertable=false, updatable=false)})
private Division division;
// Wow, now i expect i can change the value of DIVISION_CODE column
@Column(name="DIVISION_CODE")
private BigInteger divisionCode;
Hibernate会问你
无论两个属性是否共享同一列,我应该保留哪个属性???正如我所看到的,id属性存储一个非空值,accountNumber存储一个空值
我应该执行这样的查询吗
INSERT INTO ACCOUNT (ACCOUNT_NUMBER, ACCOUNT_NUMBER) VALUES (127359, NULL);
这没有道理。因此,这是一个错误的SQL查询
正因为如此,你看到了这个好消息
重复列。。。废话,废话,废话。。。(应使用insert=“false”update=“false”进行映射)
因此,我假设名为IssTESTPK的复合主键也存储名为SURVEY_NUM的列。这不是一个好主意您将复合主键属性定义为insert=“false”update=“false”。避免头痛
请记住:当多个属性共享同一列时,请将其中一个定义为insertable=false、Updateable=false没有其他内容
我认为你的复合主键类应该是这样的
@Embeddable
public class IssTESTPK implements Serializable {
// Ops... Our missing field which causes our Exception (repeated column... blah, blah, blah...)
@Column(name="SURVEY_NUM", nullable=false)
private Integer property;
private Integer otherProperty;
private Integer anotherProperty;
// required no-arg constructor
public IssTESTPK() {}
// You must implement equals and hashcode
public boolean equals(Object o) {
if(o == null)
return false;
if(!(o instanceof IssTESTPK))
return false;
IssTESTPK other = (IssTESTPK) o;
if(!(getProperty().equals(other.getProperty())))
return false;
if(!(getOtherProperty().equals(other.getOtherProperty())))
return false;
if(!(getAnotherProperty().equals(other.getAnotherProperty())))
return false;
return true;
}
// NetBeans or Eclipse will worry about it
public int hashcode() {
// hashcode code goes here
}
}
更新
在继续之前 Hibernate不支持自动生成复合主键
@Embeddable
public class EmployeeId implements Serializable {
@Column(name="EMPLOYEE_NUMBER")
private String employeeNumber;
@Column(name="SURVEY_NUMBER")
private BigInteger surveyNumber;
// getter's and setter's
// equals and hashcode
}
必须在保存前提供其值。记住这一点
让我们看看Employee复合主键
@Embeddable
public class EmployeeId implements Serializable {
@Column(name="EMPLOYEE_NUMBER")
private String employeeNumber;
@Column(name="SURVEY_NUMBER")
private BigInteger surveyNumber;
// getter's and setter's
// equals and hashcode
}
1º在保存员工之前,必须提供其值。如上所述,Hibernate不支持自动生成复合主键
@Embeddable
public class EmployeeId implements Serializable {
@Column(name="EMPLOYEE_NUMBER")
private String employeeNumber;
@Column(name="SURVEY_NUMBER")
private BigInteger surveyNumber;
// getter's and setter's
// equals and hashcode
}
2ºHibernate不允许您更新(复合)主键—它没有意义
3º其值不能为空
因此,根据上面的描述,我们的EmployeeId可以写为
@Embeddable
public class EmployeeId implements Serializable {
@Column(name="EMPLOYEE_NUMBER", nullable=false, updatable=false)
private String employeeNumber;
@Column(name="SURVEY_NUMBER", nullable=false, updatable=false)
private BigInteger surveyNumber;
// getter's and setter's
// equals and hashcode
}
如前所述
当多个属性共享同一列时,将其中一个定义为insertable=false、Updateable=false没有其他内容
但是我们不能将复合主键属性标记为insertable=false,updateable=false,因为Hibernate使用它来保存我们的实体
由于Hibernate将使用名为surveyNumber的复合主键属性(及其SURVEY_NUMBER列)对数据库执行SQL操作,我们需要将@ManyTone division属性(及其名为SURVEY_NUMBER的外键列)重写为insertable=false、Updateable=false
// Employee.java
@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE"),
@JoinColumn(name="SURVEY_NUMBER", referencedColumnName="SURVEY_NUMBER", insertable=false, updatable=false)})
private Division division;
4º当您使用复合外键时,我们不能混合使用可插入不可插入或可更新不可更新
差不多
@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
// I can be updatable
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE", insertable=false),
// And i can be insertable
@JoinColumn(name="SURVEY_NUMBER", referencedColumnName="SURVEY_NUMBER", updatable=false)})
private Division division;
否则,Hibernate会抱怨
不允许在属性中混合可插入列和不可插入列
因此,其名为DIVISION_CODE的复合外键列也应标记为可插入=false,可更新=false,以避免上述异常
// Employee.java
@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE", insertable=false, updatable=false),
@JoinColumn(name="SURVEY_NUMBER", referencedColumnName="SURVEY_NUMBER", insertable=false, updatable=false)})
private Division division;
由于我们不能再更新DIVISION\u CODE列,我们的DIVISION属性的行为就像一个常量。然后,您可以考虑创建一个名为divisionCode的新属性,以某种方式更改DIVISION_CODE列,如下所示
Account account = new Account();
account.setId(127359);
account.setAccountNumber(null);
entityManager.persist(account);
// Employee.java
@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE", insertable=false, updatable=false),
@JoinColumn(name="SURVEY_NUMBER", referencedColumnName="SURVEY_NUMBER", insertable=false, updatable=false)})
private Division division;
// Wow, now i expect i can change the value of DIVISION_CODE column
@Column(name="DIVISION_CODE")
private BigInteger divisionCode;
好吧,让我想想。假设我们有下面的除法表
DIVISION TABLE
DIVISION_CODE SURVEY_NUMBER
1 10
2 11
3 12
4 13
5 14
请记住:部门和员工之间存在外键约束
你想到
由于insertable=false、Updateable=false,我无法更改division属性但我可以更改divisionCode属性(及其DIVISION\u CODE列),作为更改名为DIVISION\u CODE的外键列的方法
您可以执行以下代码
员工代码(7)
哇,见上面的分区表。除法代码列中是否有等于7的值
答案很清楚:否(您将看到约束冲突)
因此,这是一个不一致的映射。Hibernate不允许这样做
关于,@Bozho,当设置updateable=true时,我遇到了另一个错误,我更新了我的问题。这就是为什么我必须设置Updateable=falseTESTClass复合键@Bozho,我看到了你的更新,你能给我一个示例吗。。我不太明白你说的什么是可嵌入类?哪个类是issDivision?@cometta-@issDivision
不是可嵌入的吗?我假设有些东西可能不是真的,但是-给出IssDivision
的代码!我发布了我的原始实体(IssEmployee.java)(IssEmployeePK.java)请给出整个类(实体和嵌入的密钥)@Bozho,你能发布一个使用pk的实体的示例吗?我在上看到帖子,你理解最后2篇关于私有get/set的帖子吗?嗨,我做了如你所说的更改,但它不起作用。我发布了我的原始实体(IssEmployee.java)(IssEmployeePK.java)