Java 显示产品属于使用xml解析的android listview中的类别
我必须在android listview应用程序中通过xml解析传递类别、子类别和产品详细信息Java 显示产品属于使用xml解析的android listview中的类别,java,android,listview,xml-parsing,Java,Android,Listview,Xml Parsing,我必须在android listview应用程序中通过xml解析传递类别、子类别和产品详细信息 This is my xml feed: <Feed> <category> <Category> <Categoryname>Books</Categoryname> <SubCategory> <subcategor
This is my xml feed:
<Feed>
<category>
<Category>
<Categoryname>Books</Categoryname>
<SubCategory>
<subcategoryname>Internet</subcategoryname>
<Product>
<Name>New Masters of Flash</Name>
<Price>79.99</Price>
</Product>
<Product>
<Name>Professional Java Server Programming</Name>
<Price>63.99</Price>
</Product>
</SubCategory>
<SubCategory>
<subcategoryname>Software</subcategoryname>
<Product>
<Name>Krishnaveni</Name>
<Price>79.99</Price></Product>
<Product>
<Name>Veeman</Name>
<Price>63.99</Price>
</Product>
</SubCategory>
</Category>
</category>
</Feed>
---->在我必须点击互联网之后,意味着我将获得该特定(互联网)类别的产品。
它们是:
Internet
Software
New Masters of Flash
Professional Java Server Programming
如果我必须单击第二个子类别(软件),意味着我必须获得以下结果:
Krishnaveni
Veeman
在这里,我只面临一些问题
在这里,我必须单击internet子类别表示我得到4个产品。同样的方法也适用于软件。我必须单击软件子类别表示我得到4个产品
我如何开发这个。请帮助我。我如何才能获得该特定子类别的产品
这是我的编码部分:
public class AndroidXMLParsingActivity extends Activity {
static final String URL = "http://192.168.1.168/xcart432pro/feed.xml";
private static final int Tech = 0;
static String KEY_CATEGORY = "Category";
static final String KEY_TITLE = "Categoryname";
ListView lview3;
LazyAdapter adapter;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
final ArrayList<HashMap<String, String>> songsList = new ArrayList<HashMap<String, String>>();
XMLParser parser = new XMLParser();
String xml = parser.getXmlFromUrl(URL); // getting XML from URL
Document doc = parser.getDomElement(xml); // getting DOM element
NodeList nl = doc.getElementsByTagName(KEY_CATEGORY);
// looping through all song nodes <song>
for (int i = 0; i < nl.getLength(); i++) {
// creating new HashMap
HashMap<String, String> map = new HashMap<String, String>();
Element e = (Element) nl.item(i);
map.put(KEY_TITLE, parser.getValue(e, KEY_TITLE));
songsList.add(map);
}
lview3 = (ListView) findViewById(R.id.listView1);
adapter = new LazyAdapter(this, songsList);
lview3.setAdapter(adapter);
lview3.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
HashMap<String, String> map = songsList.get(position);
switch (position)
{
case Tech:
Intent tech = new Intent(AndroidXMLParsingActivity.this, com.androidhive.xmlparsing.SubCate.class);
tech.putExtra(KEY_TITLE, "Books");
startActivity(tech);
break;
default:
break;
}
}
});
在第行下面添加onCreate函数之后:
Bundle bdl = getIntent().getExtras();
KEY_CATEGORY = bdl.getString(KEY_TITLE);
我还在第三个活动(catalog.java)中添加了一些代码
首先声明密钥_SUBCATE:
static final String KEY_SUBCATE = "subcategoryname";
必须在onCreate()函数后添加以下行:
Bundle bdl = getIntent().getExtras();
KEY_CATEGORY = bdl.getString(KEY_SUBCATE);
现在我必须运行应用程序,这意味着am没有获得任何产品。请帮助我。我如何才能获得正确类别的产品。只需在单击子类别之前对每个产品进行
最终
。我想你的问题会解决的。如果你不做出这些最终的决定,你每次都会处于最后的位置
我想您可以在这里发送产品表单:---
只需替换它:---
请详细解释。我必须在这里更改哪个文件和行。例如:-final int temp\u veriable=ur\u current\u value;然后放入temp_变量,它将根据您的位置取值。我只在每个产品上使用了最终值。请检查我的code@DeepankerChaudhary不,是的。现在我也只得到相同的输出
Bundle bdl = getIntent().getExtras();
KEY_CATEGORY = bdl.getString(KEY_TITLE);
static final String KEY_SUBCATE = "subcategoryname";
Bundle bdl = getIntent().getExtras();
KEY_CATEGORY = bdl.getString(KEY_SUBCATE);
map.put(KEY_TITLE, parser.getValue(e, KEY_TITLE));
map.put(KEY_DESCRIPTION, parser.getValue(e, KEY_DESCRIPTION));
map.put(KEY_COST, parser.getValue(e, KEY_COST));
final String key_title=parser.getValue(e, KEY_TITLE);
final String key_desc=parser.getValue(e, KEY_DESCRIPTION);
fiinal String key_cost=parser.getValue(e, KEY_COST);
map.put(KEY_TITLE, key_title);
map.put(KEY_DESCRIPTION, key_desc);
map.put(KEY_COST, key_cost);