Java 带有请求消息的Apache CXF ExceptionMapper

我想知道这样做是否可行，或者是否有更好的方法：

public class WebServiceExceptionMapper implements ExceptionMapper<Exception> {

  private static Logger logger = LoggerFactory.getLogger(WebServiceExceptionMapper.class);

  @Override
  public Response toResponse(Exception ex, Message requestMessage) {
    logger.error("request=" + httpMessage.etc..etc.., ex);
    return Response.status(Status.INTERNAL_SERVER_ERROR).build();
  }

}

公共类WebServiceExceptionMapper实现ExceptionMapper{
私有静态记录器Logger=LoggerFactory.getLogger（WebServiceExceptionMapper.class）；
@凌驾
对响应的公共响应（异常示例，消息请求消息）{
logger.error（“request=“+httpMessage.etc..etc..ex”）；
返回Response.status（status.INTERNAL_SERVER_ERROR）.build（）；
}
}

---

基本上，我希望不仅能够记录异常，而且能够记录触发错误的请求消息。更具体地说，如果请求包含JSON或XML，我想抓住它。

NVM。通过在我的ExceptionMapper中注入MessageContext并添加自定义RequestHandler（如下所述）解决了这个问题：

public class StringContentRequestHandler implements RequestHandler { 

private static final Logger logger = LoggerFactory.getLogger(RawContentRequestHandler.class); 

public Response handleRequest(Message m, ClassResourceInfo resourceClass) { 
    InputStream is = m.getContent(InputStream.class); 
    try { 
        CachedOutputStream bos = new CachedOutputStream(); 
        IOUtils.copy(is, bos); 

        bos.flush(); 
        is.close(); 

        m.setContent(InputStream.class, bos.getInputStream()); 
        StringBuilder builder = new StringBuilder(); 
        bos.writeCacheTo(builder, "utf-8"); 
        m.setContent(String.class, builder.toString()); 
        return null; 

    } catch (IOException ex) { 
        logger.error("IOException on getting raw content", ex); 
        return null; 
    } 
} 
}