Java JComboBox的输出被打印两次

Java JComboBox的输出被打印两次,java,user-interface,jframe,jcombobox,Java,User Interface,Jframe,Jcombobox,我试图从组合框中获取所选值以显示在提示窗口中,但提示窗口显示两次。我没有复制任何代码,但为什么会发生这种情况 代码片段:- package interfaceGUI; import javax.swing.JComboBox; import javax.swing.JLabel; import javax.swing.JOptionPane; import javax.swing.JPanel; import javax.swing.JPasswordField; import javax.sw

我试图从组合框中获取所选值以显示在提示窗口中,但提示窗口显示两次。我没有复制任何代码,但为什么会发生这种情况

代码片段:-

package interfaceGUI;
import javax.swing.JComboBox;
import javax.swing.JLabel;
import javax.swing.JOptionPane;
import javax.swing.JPanel;
import javax.swing.JPasswordField;
import javax.swing.JFrame;
import javax.swing.JTextArea;
import javax.swing.JTextField;
import javax.swing.JButton;

import java.awt.Button;
import java.awt.FlowLayout;
import java.awt.GridLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.event.ItemEvent;
import java.awt.event.ItemListener;

import java.sql.DriverManager;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.SQLException;
import java.sql.Statement;
import java.sql.ResultSet;

public class BirthdayForm extends JFrame{
private JLabel chooseItem;
private JLabel chooseQuantity;
private JComboBox items;
private JTextField quantity;
private JTextArea selection;
private JButton Rent;
private JButton Edit;
private JButton Cancel;

private JPanel choose;
private JPanel forButton;

private String list[] = {"Chair", "Napkin", "Garland", "Mirrored Ball", 
"Floral Vases", "Large Balloons", "Square Jars"};

public BirthdayForm()
{
    super("Birthday Party Supplies Rental Form");
    setLayout(new FlowLayout());

    chooseItem = new JLabel("Choose Item:");
    items = new JComboBox(list);

    chooseQuantity = new JLabel("Choose Quantity:");
    quantity = new JTextField(5);
    choose = new JPanel();
    choose.setLayout(new GridLayout(1,4));
    choose.add(chooseItem);
    choose.add(items);
    choose.add(chooseQuantity);
    choose.add(quantity);
    add(choose);

    selection = new JTextArea(15,30);
    add(selection);

    Rent = new JButton("Rent");
    Edit = new JButton("Edit List");
    Cancel = new JButton("Cancel");
    forButton = new JPanel();
    forButton.setLayout(new GridLayout(1,3));
    forButton.add(Rent);
    forButton.add(Edit);
    forButton.add(Cancel);
    add(forButton);

    comboHandler handler = new comboHandler();
    items.addItemListener(handler);
}

public class comboHandler implements ItemListener
{
    public void itemStateChanged(ItemEvent event)
    {
        if(event.getSource() == items)
        {
            String item = (String) items.getSelectedItem();
            if(item == "Chair")
            {
                JOptionPane.showMessageDialog(null, "Chair" , "Items", 
                                         JOptionPane.INFORMATION_MESSAGE);
            }
        }
        else
        {
        }
    }
}
}

我做错了什么?我找不到我的错误。请提供帮助。

这是您需要的更改,请检查项目是否已选中

public void itemStateChanged(ItemEvent event)
    {
        if(event.getSource() == items)
        {
            int state = event.getStateChange();
            if(state == ItemEvent.SELECTED)
            {
              String item = (String) items.getSelectedItem();
              JOptionPane.showMessageDialog(null, item , "Items", JOptionPane.INFORMATION_MESSAGE);
            }
        }
        else
        {
        }
    }

从事件中获取项目状态,并检查该状态是否为选中状态,int state=event.getStateChange();如果(state==ItemEvent.SELECTED),您能提供一个更完整的答案吗?当然,请参阅我的答案,itemStateChange会被触发两次,一次用于取消选择的项,一次用于选择的项更好的选择可能是使用ActionListener而不是Head。非常感谢。$Damini,我不清楚你的问题,你想知道下一个列表项目的声明,关于下一个列表项目,你想展示什么?这是一个愚蠢的问题,对不起,哈哈。我没有仔细看你的答案。你解决了我的问题,非常感谢。“如果(item==“Chair”)”-真的吗?@MadProgrammer,谢谢你的提醒,我刚刚修改了代码。我只是想通过修改代码来回答这个问题。但如果使用if语句,则消息对话框将仅在选择“chair”时显示。