Java 无法在@JoinColumn上进行连接，该列为@Id

我有一个@Entity类，它有多个ID列，所有这些都是外键。类代码如下所示：

@Entity
@Immutable
@Table(name = "AnyNews")
public class AnyNews implements Serializable {
    private static final long serialVersionUID = 43876852L;

    @Id
    @Column(name = "id")
    private int id;

    @Id
    @OneToOne
    @JoinColumn(name = "news_id")
    private News news;

    .....
}

Criteria criteria = sessionFactory.getCurrentSession()
        .createCriteria(AnyNews.class, "any")
        .createCriteria("news", "news");
        .add(Restrictions.eq("news.id", id))
        .add(Restrictions.ge("news.date", from.getTime()));

我想在

News

实体的

date

列中添加

对
标准的
限制。所以我制定了如下标准：

@Entity
@Immutable
@Table(name = "AnyNews")
public class AnyNews implements Serializable {
    private static final long serialVersionUID = 43876852L;

    @Id
    @Column(name = "id")
    private int id;

    @Id
    @OneToOne
    @JoinColumn(name = "news_id")
    private News news;

    .....
}

Criteria criteria = sessionFactory.getCurrentSession()
        .createCriteria(AnyNews.class, "any")
        .createCriteria("news", "news");
        .add(Restrictions.eq("news.id", id))
        .add(Restrictions.ge("news.date", from.getTime()));

代码看起来不错，但会出现如下错误：

org.hibernate.exception.SQLGrammarException: could not execute query
...

该问题是由于缺少Join语句造成的。查询中没有Join语句：

select
    this_.id as news4_5_0_,
    this_.news_id as keyword1_5_0_,
    this_.board_no as board2_5_0_,
    this_.seq as seq5_0_ 
from
    AnyNews this_ 
where
    this_.news_id=? 
    and news1_.date>=? 

为什么Hibernate会这样做。我不能在同一列上使用@Id和@JoinColumn注释吗？
您需要一个
@OneToOne（fetch=FetchType.EAGER）
注释才能进行连接

或者，可以执行
.setFetchMode（“news”，FetchMode.JOIN）