Java 如何在hibernate中选择具有其他字段的对象的新实例?
假设我有这些Calss:Java 如何在hibernate中选择具有其他字段的对象的新实例?,java,hibernate,hql,instance,Java,Hibernate,Hql,Instance,假设我有这些Calss: public class A { public Long id; public B b; public void setId(Long id) { this.id = id; } public Long getId() { return id; } public void setB(B b) { this.b = b; } public B g
public class A {
public Long id;
public B b;
public void setId(Long id) {
this.id = id;
}
public Long getId() {
return id;
}
public void setB(B b) {
this.b = b;
}
public B getB() {
return b;
}
}
public class B {
public Long id;
public String code;
public void setId(Long id) {
this.id = id;
}
public Long getId() {
return id;
}
public void setCode(String code) {
this.code = code;
}
public Long getCode() {
return code;
}
public B(Long id) {
this.id = id;
}
}
我想执行这个查询:
select new B(a.b.id) as b, a.b.code as bCode
from A a
但是is不起作用。试试这个
select new B(b1.id) as b, b1.code as bCode
from A a
inner join a.b as b1