PHP-将JAVA/JS对象转换为PHP数组

PHP-将JAVA/JS对象转换为PHP数组,java,php,android,Java,Php,Android,我正在通过android中的JAVA从Facebook请求一些数据,并将其发送到服务器: Address[addressLines=[0:"Königspl., 86150 Augsburg, Germany"],feature=Königsplatz,admin=Bayern,sub-admin=Schwaben,locality=Augsburg,thoroughfare=Königsplatz,postalCode=86150,countryCode=DE,countryName=Germ

我正在通过android中的JAVA从Facebook请求一些数据,并将其发送到服务器:

Address[addressLines=[0:"Königspl., 86150 Augsburg, Germany"],feature=Königsplatz,admin=Bayern,sub-admin=Schwaben,locality=Augsburg,thoroughfare=Königsplatz,postalCode=86150,countryCode=DE,countryName=Germany,hasLatitude=true,latitude=48.366384499999995,hasLongitude=true,longitude=10.8943626,phone=null,url=null,extras=null]
我不知道这到底是什么,JAVA对象还是我不知道

我已经试过了:
$array=json\u decode($data,true)
并返回
NULL

它是什么?如何将其转换为PHP数组

编辑:

这是我用来生成数据的JAVA(实际上是kotlin)代码:

val geocoder = Geocoder(this, Locale.ENGLISH)
try {
    val addresses = geocoder.getFromLocation(48.366512, 10.894446, 1)

    if (addresses != null)
    {
        val returnedAddress = addresses[0]
        val strReturnedAddress = StringBuilder("Address:\n")
        for (i in 0 until returnedAddress.maxAddressLineIndex) {
            strReturnedAddress.append(returnedAddress.getAddressLine(i)).append("\n")
        }

        geocoderStuff = returnedAddress.toString()

    } else
    {
        // NO ADDRESS
    }
} catch (e: IOException) {
    e.printStackTrace()
}
        val returnedAddress = addresses[0]
        val strReturnedAddress = StringBuilder("Address:\n")
        for (i in 0 until returnedAddress.maxAddressLineIndex) {
            strReturnedAddress.append(returnedAddress.getAddressLine(i)).append("\n")
        }

        val gson = Gson() // HERE
        val json = gson.toJson(returnedAddress) // HERE

        geocoderStuff = json
我是这样发送的:

                val params = RequestParams()
                params.put("geocoder", geocoderStuff)
                letsDoSomeNetworking(params)

private fun letsDoSomeNetworking(params: RequestParams) {

        // AsyncHttpClient belongs to the loopj dependency.
        val client = AsyncHttpClient()

        client.get("http://www.bla.com/android/fb_access.php", params, object : JsonHttpResponseHandler()
        {
            override fun onSuccess(statusCode: Int, headers: Array<Header>?, response: JSONObject?)
            {
                // success
            }

            override fun onFailure(statusCode: Int, headers: Array<Header>?, e: Throwable, response: JSONObject?)
            {
                // error
            }
        })
    }
val params=RequestParams()
参数put(“地理编码器”,地理编码器TUFF)
letsDoSomeNetworking(参数)
私人娱乐letsDoSomeNetworking(参数:RequestParams){
//AsyncHttpClient属于loopj依赖项。
val client=AsyncHttpClient()
client.get(“http://www.bla.com/android/fb_access.php,参数,对象:JsonHttpResponseHandler()
{
覆盖成功时的乐趣(状态代码:Int,标题:Array?,响应:JSONObject?)
{
//成功
}
覆盖失败(状态代码:Int,头:Array?,e:Throwable,响应:JSONObject?)
{
//错误
}
})
}

解决方案是在获取数据后使用JAVA/Kotlin端的gson库:

val geocoder = Geocoder(this, Locale.ENGLISH)
try {
    val addresses = geocoder.getFromLocation(48.366512, 10.894446, 1)

    if (addresses != null)
    {
        val returnedAddress = addresses[0]
        val strReturnedAddress = StringBuilder("Address:\n")
        for (i in 0 until returnedAddress.maxAddressLineIndex) {
            strReturnedAddress.append(returnedAddress.getAddressLine(i)).append("\n")
        }

        geocoderStuff = returnedAddress.toString()

    } else
    {
        // NO ADDRESS
    }
} catch (e: IOException) {
    e.printStackTrace()
}
        val returnedAddress = addresses[0]
        val strReturnedAddress = StringBuilder("Address:\n")
        for (i in 0 until returnedAddress.maxAddressLineIndex) {
            strReturnedAddress.append(returnedAddress.getAddressLine(i)).append("\n")
        }

        val gson = Gson() // HERE
        val json = gson.toJson(returnedAddress) // HERE

        geocoderStuff = json

你想用Java转换成PHP数组吗?我想我不能那么容易地把它发送到服务器上,我是android/Java的初学者:)你能发布用于向服务器发送数据的Java代码吗?好的,我编辑了这个问题,试着在
json\u decode
上使用
$\u GET['geocoder']
。看看它是否有效。