Java split()和parseInt

Java split()和parseInt,java,android,Java,Android,使用创建字符串后 String data = String.valueOf(seekBar1.getProgress()) + ":" + String.valueOf(seekBar2.getProgress()) + ":" + String.valueOf(seekBar3.getProgress()) + ":" + String.valueOf(seekBar4.getProgress()) + ":"

使用创建字符串后

String data = String.valueOf(seekBar1.getProgress()) + ":"
            + String.valueOf(seekBar2.getProgress()) + ":"
            + String.valueOf(seekBar3.getProgress()) + ":"
            + String.valueOf(seekBar4.getProgress()) + ":"
            + String.valueOf(seekBar5.getProgress());
通过蓝牙将此字符串发送到其他设备,然后使用

byte[] rBuf = (byte[]) msg.obj;
String rMessage = new String(rBuf);
String[] split = rMessage.split(":");
seekBar1.setProgress(Integer.parseInt(split[0]));
seekBar2.setProgress(Integer.parseInt(split[1]));
seekBar3.setProgress(Integer.parseInt(split[2]));
seekBar4.setProgress(Integer.parseInt(split[3]));
seekBar5.setProgress(Integer.parseInt(split[4]));
我明白了

java.lang.NumberFormatException: Invalid int: "0�������������"...
我知道异常是什么,但我不完全确定它被抛出的原因,我已将收到的数字打印为字符串,据我所知,只有整数出现在split[4]

你知道这是怎么回事吗?可能与InputStream/OutputStream有关

处理蓝牙连接I/O的线程

private class ConnectedThread extends Thread {
        private final BluetoothSocket mmSocket;
        private final InputStream mmInStream;
        private final OutputStream mmOutStream;

        public ConnectedThread(BluetoothSocket socket, String socketType) {
            Log.d(TAG, "create ConnectedThread: " + socketType);
            mmSocket = socket;
            InputStream tmpIn = null;
            OutputStream tmpOut = null;

            // Get the BluetoothSocket input and output streams
            try {
                tmpIn = socket.getInputStream();
                tmpOut = socket.getOutputStream();
            } catch (IOException e) {
                Log.e(TAG, "temp sockets not created", e);
            }

            mmInStream = tmpIn;
            mmOutStream = tmpOut;
        }

        public void run() {
            Log.i(TAG, "BEGIN mConnectedThread");
            byte[] buffer = new byte[1024];
            int bytes;

            // Keep listening to the InputStream while connected
            while (true) {
                try {
                    // Read from the InputStream
                    bytes = mmInStream.read(buffer);

                    // Send the obtained bytes to the UI Activity
                    mHandler.obtainMessage(ControlActivity.MESSAGE_READ, bytes, -1, buffer)
                            .sendToTarget();
                } catch (IOException e) {
                    Log.e(TAG, "disconnected", e);
                    connectionLost();
                    break;
                }
            }
        }

        /**
         * Write to the connected OutStream.
         * @param buffer  The bytes to write
         */
        public void write(byte[] buffer) {
            try {
                mmOutStream.write(buffer);

                // Share the sent message back to the UI Activity
                mHandler.obtainMessage(ControlActivity.MESSAGE_WRITE, -1, -1, buffer)
                        .sendToTarget();
            } catch (IOException e) {
                Log.e(TAG, "Exception during write", e);
            }
        }

        public void cancel() {
            try {
                mmSocket.close();
            } catch (IOException e) {
                Log.e(TAG, "close() of connect socket failed", e);
            }
        }
    }

可能rMessage的结尾有一些字符,比如EOL字符或其他字符

如果您不想花时间调试
,可以在“data”
的末尾添加“:”

String data = String.valueOf(seekBar1.getProgress()) + ":"
            + String.valueOf(seekBar2.getProgress()) + ":"
            + String.valueOf(seekBar3.getProgress()) + ":"
            + String.valueOf(seekBar4.getProgress()) + ":"
            + String.valueOf(seekBar5.getProgress()) + ":";

这样,您的
split[4]
仍然是正确的,只有
split[5]
无效,您无论如何都不会使用它。

正如您所提到的,它可能与输入/输出部分有关。你为什么不发布与该部件相关的代码?我相信您可以对发布的代码进行单元测试,并亲自查看问题的原因。rMessage是第一个代码段中的变量数据吗?编码/解码方面存在一些问题。使用
stringrmessage=新字符串(rBuf,字符集)并传递正确的字符集来解码消息。你能提供失败的消息值吗?消息是##:##:##:##:##:####,其中###是任何整数值0-100,唯一一个。setProgress不起作用的是在我解析split[4]的值以设置进度时。我这样做了,但它最终导致了另一个问题,哈哈