Java 从Air本机扩展(android)显示ImageView时出现问题

Java 从Air本机扩展(android)显示ImageView时出现问题,java,android,air,Java,Android,Air,首先我想说的是,我是java和android的初学者,我花了很多时间来尝试实现这一点,并寻找答案,但还是忍不住 我正在做一个Air本地扩展。如果现在我成功地创建了这封电子邮件,并且大部分呼叫都正常工作,那么当我从这封电子邮件中显示ImageView时,我就卡住了 似乎我需要了解一些东西才能正确显示ImageView,所以在启动时,我检索了一些信息,如活动、上下文和根视图 public class MyContext extends FREContext { @Override

首先我想说的是,我是java和android的初学者,我花了很多时间来尝试实现这一点,并寻找答案,但还是忍不住

我正在做一个Air本地扩展。如果现在我成功地创建了这封电子邮件,并且大部分呼叫都正常工作,那么当我从这封电子邮件中显示ImageView时,我就卡住了

似乎我需要了解一些东西才能正确显示ImageView,所以在启动时,我检索了一些信息,如活动、上下文和根视图

public class MyContext extends FREContext 
{

    @Override
    public void dispose() 
    {

    }


    @Override
    public Map<String, FREFunction> getFunctions()
    {
        Configs.activity    = this.getActivity();
        Configs.context     = Configs.activity.getApplicationContext();
        Configs.decorView   = Configs.activity.getWindow().getDecorView();

        Map<String, FREFunction> map = new HashMap<String, FREFunction>();

        map.put("init"                  , new InitFunction());
        map.put("oneFunction"           , new myFunction());

        return map;
    }

}
然后我调用这个类从web加载一个图像,加载后我想在屏幕上显示它

public class GraphicLoader extends AsyncTask<URL, String, String>
{
    public ImageView    view;

    private URL         url;
    private int         width;
    private int         height;


    // Constructor
    public GraphicLoader (String url, int width, int height)
    {
        this.width  = width;
        this.height = height;

        try 
        {
            this.url    = new URL (url);
        } 
        catch (MalformedURLException e) 
        {
            e.printStackTrace();
        }
    }


    @Override
    protected String doInBackground(URL... params) 
    {
        final BitmapFactory.Options options = new BitmapFactory.Options();
        options.inJustDecodeBounds = false;

        try 
        {
            this.view   = new ImageView (Configs.context);
            view.setImageBitmap(BitmapFactory.decodeStream(url.openConnection().getInputStream(), null, options));

            RelativeLayout relativeLayout = new RelativeLayout(Configs.context);

            RelativeLayout.LayoutParams rlp = new RelativeLayout.LayoutParams(
                    RelativeLayout.LayoutParams.MATCH_PARENT,
                    RelativeLayout.LayoutParams.MATCH_PARENT);

            RelativeLayout.LayoutParams lp = new RelativeLayout.LayoutParams(
                    RelativeLayout.LayoutParams.WRAP_CONTENT,
                    RelativeLayout.LayoutParams.WRAP_CONTENT);
            lp.addRule(RelativeLayout.CENTER_IN_PARENT);
            view.setLayoutParams(lp);

            relativeLayout.addView(view);
            Configs.activity.setContentView(relativeLayout, rlp);

        } 
        catch (IOException e) 
        {
            Configs.debug = Configs.debug + " GraphicLoaded error 2 " + e.getMessage();
            e.printStackTrace();
        }

        return null;
    }
}
然后,我的应用程序在进入doInBackground函数时崩溃,位于Configs.activity.setContentViewrelativeLayout,rlp;行。我可能没有以正确的方式使用它,我尝试了多种方法来实现它,这取决于我在web上找到的内容,但没有成功,总是导致崩溃

应该怎么做


感谢您的帮助?

因此我找到了解决方案,只需将这部分代码移出异步任务:

RelativeLayout relativeLayout = new RelativeLayout(Configs.context);

            RelativeLayout.LayoutParams rlp = new RelativeLayout.LayoutParams(
                    RelativeLayout.LayoutParams.MATCH_PARENT,
                    RelativeLayout.LayoutParams.MATCH_PARENT);

            RelativeLayout.LayoutParams lp = new RelativeLayout.LayoutParams(
                    RelativeLayout.LayoutParams.WRAP_CONTENT,
                    RelativeLayout.LayoutParams.WRAP_CONTENT);
            lp.addRule(RelativeLayout.CENTER_IN_PARENT);
            view.setLayoutParams(lp);

            relativeLayout.addView(view);
            Configs.activity.setContentView(relativeLayout, rlp);
应用程序不再崩溃,将正确显示ImageView