Java 如何防止TrayIcon弹出窗口占用整个dispatcher线程

Java 如何防止TrayIcon弹出窗口占用整个dispatcher线程,java,windows,swing,system-tray,Java,Windows,Swing,System Tray,我有一个使用JFrame和TrayIcon的java应用程序,我在TrayIcon中添加了一个PopupMenu 当我点击TrayIcon时,弹出菜单会出现,但只要PopupMenu可见,主框架就会冻结 我的第一个想法是事件调度线程被某个人占用。所以 我编写了一个使用swing worker和进度条的小示例应用程序 public class TrayIconTest { public static void main(String[] args) throws AWTException {

我有一个使用
JFrame
TrayIcon
的java应用程序,我在
TrayIcon
中添加了一个
PopupMenu

当我点击
TrayIcon
时,弹出菜单会出现,但只要
PopupMenu
可见,主框架就会冻结

我的第一个想法是事件调度线程被某个人占用。所以 我编写了一个使用swing worker和进度条的小示例应用程序

public class TrayIconTest {

  public static void main(String[] args) throws AWTException {
    JFrame frame = new JFrame("TrayIconTest");
    frame.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE);

    Container contentPane = frame.getContentPane();
    JProgressBar jProgressBar = new JProgressBar();
    BoundedRangeModel boundedRangeModel = jProgressBar.getModel();
    contentPane.add(jProgressBar);

    boundedRangeModel.setMinimum(0);
    boundedRangeModel.setMaximum(100);

    PopupMenu popup = new PopupMenu();
    TrayIcon trayIcon =
            new TrayIcon(new BufferedImage(64, 64, BufferedImage.TYPE_INT_RGB), "TEST");


    // Create a popup menu components
    MenuItem aboutItem = new MenuItem("About");
    popup.add(aboutItem);
    trayIcon.setPopupMenu(popup);
    SystemTray tray = SystemTray.getSystemTray();
    tray.add(trayIcon);

    IndeterminateSwingWorker indeterminateSwingWorker = new IndeterminateSwingWorker(boundedRangeModel);
    indeterminateSwingWorker.execute();


    frame.setSize(640, 80);
    frame.setLocationRelativeTo(null);
    frame.setVisible(true);

  }
}

class IndeterminateSwingWorker extends SwingWorker<Void, Integer> {

  private BoundedRangeModel boundedRangeModel;

  public IndeterminateSwingWorker(BoundedRangeModel boundedRangeModel) {
    this.boundedRangeModel = boundedRangeModel;
  }

  @Override
  protected Void doInBackground() throws Exception {
    int i = 0;
    long start = System.currentTimeMillis();
    long runtime = TimeUnit.MILLISECONDS.convert(5, TimeUnit.MINUTES);
    while (true) {
      i++;
      i %= boundedRangeModel.getMaximum();

      publish(i);
      Thread.sleep(20);

      long now = System.currentTimeMillis();
      if ((now - start) > runtime) {
        break;
      }

      System.out.println("i = " + i);
    }
    return null;
  }

  @Override
  protected void process(List<Integer> chunks) {
    for (Integer chunk : chunks) {
      boundedRangeModel.setValue(chunk);
    }
  }
}
公共课堂培训竞赛{
公共静态void main(字符串[]args)引发AWTException{
JFrame=新JFrame(“TrayIconTest”);
frame.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE);
容器contentPane=frame.getContentPane();
JProgressBar JProgressBar=新的JProgressBar();
BoundedRangeModel BoundedRangeModel=jProgressBar.getModel();
contentPane.add(jProgressBar);
boundedRangeModel.setMinimum(0);
boundedRangeModel.setMaximum(100);
PopupMenu popup=新建PopupMenu();
特拉伊孔特拉伊孔=
新TrayIcon(新BuffereImage(64,64,BuffereImage.TYPE_INT_RGB),“测试”);
//创建一个弹出菜单组件
MenuItem aboutItem=新MenuItem(“关于”);
弹出窗口。添加(大约个字符);
trayIcon.setPopupMenu(弹出菜单);
SystemTray=SystemTray.getSystemTray();
托盘。添加(trayIcon);
不确定WingWorker不确定WingWorker=新的不确定WingWorker(boundedRangeModel);
不确定WingWorker.execute();
帧。设置大小(640,80);
frame.setLocationRelativeTo(空);
frame.setVisible(true);
}
}
类不确定WingWorker扩展SwingWorker{
私有边界范围模型边界范围模型;
公共不确定WingWorker(BoundedRangeModel BoundedRangeModel){
this.boundedRangeModel=boundedRangeModel;
}
@凌驾
受保护的Void doInBackground()引发异常{
int i=0;
长启动=System.currentTimeMillis();
long runtime=TimeUnit.millizes.convert(5,TimeUnit.MINUTES);
while(true){
i++;
i%=boundedRangeModel.getMaximum();
出版(一);
睡眠(20);
long now=System.currentTimeMillis();
如果((现在-开始)>运行时){
打破
}
System.out.println(“i=“+i”);
}
返回null;
}
@凌驾
受保护的无效进程(列表块){
for(整型块:块){
boundedRangeModel.setValue(块);
}
}
}
如何复制

启动示例应用程序时,您将看到一个带有进度条的框架。
SwingWorker
模拟进度动作

SwingWorker
发布进度值,并将其打印到
System.out

当我点击托盘图标(“黑色的”)时,进度条冻结,弹出菜单出现。我可以看到SwingWorker仍然在后台运行,因为它将进度值输出到命令行

调查

因此,我使用
jvisualvm
查看了应用程序,它向我显示,只要弹出窗口可见,事件调度程序线程就非常繁忙

我可以通过方法
sun.awt.windows.WTrayIconPeer.showPopupMenu(int,int)
看到弹出窗口

此方法使用
EventQueue.invokeLater
向事件调度线程提交可运行的。在这个runnable中,调用方法
sun.awt.windows.WPopupMenuPeer.\u show
。此方法是
本机的
它似乎实现了一个繁忙的等待循环,因此事件调度线程被此方法完全占用。 因此,只要弹出菜单可见,就不会执行其他与ui相关的任务


是否有人知道一种变通方法,可以在显示
TrayIcon
弹出窗口时保持事件调度线程的响应?

我现在使用
jpopumenu
作为变通方法,但您不能将
jpopumenu
直接添加到
TrayIcon

诀窍是编写一个
MouseListener

public class JPopupMenuMouseAdapter extends MouseAdapter {

  private JPopupMenu popupMenu;

  public JPopupMenuMouseAdapter(JPopupMenu popupMenu) {
    this.popupMenu = popupMenu;
  }

  @Override
  public void mouseReleased(MouseEvent e) {
    maybeShowPopup(e);
  }

  @Override
  public void mousePressed(MouseEvent e) {
    maybeShowPopup(e);
  }

  private void maybeShowPopup(MouseEvent e) {
    if (e.isPopupTrigger()) {
      Dimension size = popupMenu.getPreferredSize();
      popupMenu.setLocation(e.getX() - size.width, e.getY() - size.height);
      popupMenu.setInvoker(popupMenu);
      popupMenu.setVisible(true);
    }
  }
并将其连接到
TrayIcon

TrayIcon trayIcon = ...;
JPopupMenu popupMenu = ...;

JPopupMenuMouseAdapter jPopupMenuMouseAdapter = new JPopupMenuMouseAdapter(popupMenu);
trayIcon.addMouseListener(jPopupMenuMouseAdapter);