Java 如何防止TrayIcon弹出窗口占用整个dispatcher线程
我有一个使用Java 如何防止TrayIcon弹出窗口占用整个dispatcher线程,java,windows,swing,system-tray,Java,Windows,Swing,System Tray,我有一个使用JFrame和TrayIcon的java应用程序,我在TrayIcon中添加了一个PopupMenu 当我点击TrayIcon时,弹出菜单会出现,但只要PopupMenu可见,主框架就会冻结 我的第一个想法是事件调度线程被某个人占用。所以 我编写了一个使用swing worker和进度条的小示例应用程序 public class TrayIconTest { public static void main(String[] args) throws AWTException {
JFrame
和TrayIcon
的java应用程序,我在TrayIcon
中添加了一个PopupMenu
当我点击TrayIcon
时,弹出菜单会出现,但只要PopupMenu
可见,主框架就会冻结
我的第一个想法是事件调度线程被某个人占用。所以
我编写了一个使用swing worker和进度条的小示例应用程序
public class TrayIconTest {
public static void main(String[] args) throws AWTException {
JFrame frame = new JFrame("TrayIconTest");
frame.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE);
Container contentPane = frame.getContentPane();
JProgressBar jProgressBar = new JProgressBar();
BoundedRangeModel boundedRangeModel = jProgressBar.getModel();
contentPane.add(jProgressBar);
boundedRangeModel.setMinimum(0);
boundedRangeModel.setMaximum(100);
PopupMenu popup = new PopupMenu();
TrayIcon trayIcon =
new TrayIcon(new BufferedImage(64, 64, BufferedImage.TYPE_INT_RGB), "TEST");
// Create a popup menu components
MenuItem aboutItem = new MenuItem("About");
popup.add(aboutItem);
trayIcon.setPopupMenu(popup);
SystemTray tray = SystemTray.getSystemTray();
tray.add(trayIcon);
IndeterminateSwingWorker indeterminateSwingWorker = new IndeterminateSwingWorker(boundedRangeModel);
indeterminateSwingWorker.execute();
frame.setSize(640, 80);
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
}
class IndeterminateSwingWorker extends SwingWorker<Void, Integer> {
private BoundedRangeModel boundedRangeModel;
public IndeterminateSwingWorker(BoundedRangeModel boundedRangeModel) {
this.boundedRangeModel = boundedRangeModel;
}
@Override
protected Void doInBackground() throws Exception {
int i = 0;
long start = System.currentTimeMillis();
long runtime = TimeUnit.MILLISECONDS.convert(5, TimeUnit.MINUTES);
while (true) {
i++;
i %= boundedRangeModel.getMaximum();
publish(i);
Thread.sleep(20);
long now = System.currentTimeMillis();
if ((now - start) > runtime) {
break;
}
System.out.println("i = " + i);
}
return null;
}
@Override
protected void process(List<Integer> chunks) {
for (Integer chunk : chunks) {
boundedRangeModel.setValue(chunk);
}
}
}
公共课堂培训竞赛{
公共静态void main(字符串[]args)引发AWTException{
JFrame=新JFrame(“TrayIconTest”);
frame.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE);
容器contentPane=frame.getContentPane();
JProgressBar JProgressBar=新的JProgressBar();
BoundedRangeModel BoundedRangeModel=jProgressBar.getModel();
contentPane.add(jProgressBar);
boundedRangeModel.setMinimum(0);
boundedRangeModel.setMaximum(100);
PopupMenu popup=新建PopupMenu();
特拉伊孔特拉伊孔=
新TrayIcon(新BuffereImage(64,64,BuffereImage.TYPE_INT_RGB),“测试”);
//创建一个弹出菜单组件
MenuItem aboutItem=新MenuItem(“关于”);
弹出窗口。添加(大约个字符);
trayIcon.setPopupMenu(弹出菜单);
SystemTray=SystemTray.getSystemTray();
托盘。添加(trayIcon);
不确定WingWorker不确定WingWorker=新的不确定WingWorker(boundedRangeModel);
不确定WingWorker.execute();
帧。设置大小(640,80);
frame.setLocationRelativeTo(空);
frame.setVisible(true);
}
}
类不确定WingWorker扩展SwingWorker{
私有边界范围模型边界范围模型;
公共不确定WingWorker(BoundedRangeModel BoundedRangeModel){
this.boundedRangeModel=boundedRangeModel;
}
@凌驾
受保护的Void doInBackground()引发异常{
int i=0;
长启动=System.currentTimeMillis();
long runtime=TimeUnit.millizes.convert(5,TimeUnit.MINUTES);
while(true){
i++;
i%=boundedRangeModel.getMaximum();
出版(一);
睡眠(20);
long now=System.currentTimeMillis();
如果((现在-开始)>运行时){
打破
}
System.out.println(“i=“+i”);
}
返回null;
}
@凌驾
受保护的无效进程(列表块){
for(整型块:块){
boundedRangeModel.setValue(块);
}
}
}
如何复制
启动示例应用程序时,您将看到一个带有进度条的框架。SwingWorker
模拟进度动作
SwingWorker
发布进度值,并将其打印到System.out
当我点击托盘图标(“黑色的”)时,进度条冻结,弹出菜单出现。我可以看到SwingWorker仍然在后台运行,因为它将进度值输出到命令行
调查
因此,我使用jvisualvm
查看了应用程序,它向我显示,只要弹出窗口可见,事件调度程序线程就非常繁忙
我可以通过方法sun.awt.windows.WTrayIconPeer.showPopupMenu(int,int)
看到弹出窗口
此方法使用EventQueue.invokeLater
向事件调度线程提交可运行的。在这个runnable中,调用方法sun.awt.windows.WPopupMenuPeer.\u show
。此方法是本机的
,它似乎实现了一个繁忙的等待循环,因此事件调度线程被此方法完全占用。
因此,只要弹出菜单可见,就不会执行其他与ui相关的任务
是否有人知道一种变通方法,可以在显示
TrayIcon
弹出窗口时保持事件调度线程的响应?我现在使用jpopumenu
作为变通方法,但您不能将jpopumenu
直接添加到TrayIcon
中
诀窍是编写一个MouseListener
public class JPopupMenuMouseAdapter extends MouseAdapter {
private JPopupMenu popupMenu;
public JPopupMenuMouseAdapter(JPopupMenu popupMenu) {
this.popupMenu = popupMenu;
}
@Override
public void mouseReleased(MouseEvent e) {
maybeShowPopup(e);
}
@Override
public void mousePressed(MouseEvent e) {
maybeShowPopup(e);
}
private void maybeShowPopup(MouseEvent e) {
if (e.isPopupTrigger()) {
Dimension size = popupMenu.getPreferredSize();
popupMenu.setLocation(e.getX() - size.width, e.getY() - size.height);
popupMenu.setInvoker(popupMenu);
popupMenu.setVisible(true);
}
}
并将其连接到TrayIcon
TrayIcon trayIcon = ...;
JPopupMenu popupMenu = ...;
JPopupMenuMouseAdapter jPopupMenuMouseAdapter = new JPopupMenuMouseAdapter(popupMenu);
trayIcon.addMouseListener(jPopupMenuMouseAdapter);