Java通用可序列化、可重用堆栈
以下是我的程序片段,用于序列化和反序列化通用堆栈Java通用可序列化、可重用堆栈,java,generics,serialization,stack,Java,Generics,Serialization,Stack,以下是我的程序片段,用于序列化和反序列化通用堆栈 反序列化方法 public Stack<?> readAll(Path aPath){ Stack<?> temp = new Stack<>(); try(ObjectInputStream readStream = new ObjectInputStream(new BufferedInputStream(Files.newInputStream(aPath)))) { te
反序列化方法
public Stack<?> readAll(Path aPath){
Stack<?> temp = new Stack<>();
try(ObjectInputStream readStream = new ObjectInputStream(new BufferedInputStream(Files.newInputStream(aPath)))) {
temp = (Stack<?>) readStream.readObject();
}catch(EOFException e) {
e.printStackTrace();
System.out.println("EOF");
}catch(IOException | ClassNotFoundException e) {
e.printStackTrace();
System.exit(1);
}
return temp;
}
public void writeAll(Path aPath) {
try(ObjectOutputStream writeStream = new ObjectOutputStream(new BufferedOutputStream(Files.newOutputStream(aPath)))) {
writeStream.writeObject(this);
}catch(IOException e) {
e.printStackTrace();
}
}
import java.nio.file.*;
public class StackTrial {
public static void main(String[] args) {
String[] names = {"A","B","C","D","E"};
Stack<String> stringStack = new Stack<>(); //Stack that will be Serialized
Stack<String> readStack = new Stack<>(); //Stack in which data will be read
Path aPath = Paths.get("C:/Documents and Settings/USER/Beginning Java 7/Stack.txt");//Path of file
for(String name : names) { //pushing data in
stringStack.push(name);
}
for(String a : stringStack) { //displaying content
System.out.println(a);
}
stringStack.writeAll(aPath); //Serialize
readStack = (Stack<String>) readStack.readAll(aPath);//Deserialize
for(String a : readStack) { //Display the data read
System.out.println(a);
}
}
}
数据如何序列化和反序列化
public Stack<?> readAll(Path aPath){
Stack<?> temp = new Stack<>();
try(ObjectInputStream readStream = new ObjectInputStream(new BufferedInputStream(Files.newInputStream(aPath)))) {
temp = (Stack<?>) readStream.readObject();
}catch(EOFException e) {
e.printStackTrace();
System.out.println("EOF");
}catch(IOException | ClassNotFoundException e) {
e.printStackTrace();
System.exit(1);
}
return temp;
}
public void writeAll(Path aPath) {
try(ObjectOutputStream writeStream = new ObjectOutputStream(new BufferedOutputStream(Files.newOutputStream(aPath)))) {
writeStream.writeObject(this);
}catch(IOException e) {
e.printStackTrace();
}
}
import java.nio.file.*;
public class StackTrial {
public static void main(String[] args) {
String[] names = {"A","B","C","D","E"};
Stack<String> stringStack = new Stack<>(); //Stack that will be Serialized
Stack<String> readStack = new Stack<>(); //Stack in which data will be read
Path aPath = Paths.get("C:/Documents and Settings/USER/Beginning Java 7/Stack.txt");//Path of file
for(String name : names) { //pushing data in
stringStack.push(name);
}
for(String a : stringStack) { //displaying content
System.out.println(a);
}
stringStack.writeAll(aPath); //Serialize
readStack = (Stack<String>) readStack.readAll(aPath);//Deserialize
for(String a : readStack) { //Display the data read
System.out.println(a);
}
}
}
导入java.nio.file.*;
公开审判{
公共静态void main(字符串[]args){
字符串[]名称={“A”、“B”、“C”、“D”、“E”};
Stack stringStack=新堆栈();//将被序列化的堆栈
Stack readStack=new Stack();//将在其中读取数据的堆栈
Path aPath=Path.get(“C:/Documents and Settings/USER/beging Java 7/Stack.txt”);//文件的路径
对于(字符串名称:名称){//将数据推入
stringStack.push(名称);
}
对于(字符串a:stringStack){//显示内容
系统输出打印项次(a);
}
stringStack.writeAll(aPath);//序列化
readStack=(Stack)readStack.readAll(aPath);//反序列化
对于(字符串a:readStack){//显示读取的数据
系统输出打印项次(a);
}
}
}
问题:readAll()方法的返回类型是否真的提供了灵活性,或者如果我将其更改为Stack
我的逻辑是,写入文件的数据可能是
堆栈的
,因此在回读时可能会导致问题,编译器无法检查您读取的是堆栈
,还是堆栈
。因此,最后,您必须知道堆栈中有什么,并且必须确定堆栈的类型。剩下的是糖
如果你这样离开它,并且你知道你正在读一个堆栈
,你就必须写
Stack<Integer> stack = (Stack<Integer>) readAll(path);
Stack Stack=(Stack)readAll(path);
如果你把它写成
public <T> Stack<T> readAll(Path aPath) {...}
public Stack readAll(Path aPath){…}
编译器可以从变量声明中推断类型,因此您可以编写
Stack<Integer> stack = readAll(path);
Stack-Stack=readAll(路径);
但最终,结果是一样的。当从堆栈中获取整数时,如果它不是一个真正的
堆栈
,您将得到一个异常:公共堆栈readAll(Path aPath){…}
下面的public不是必需的,是吗?是的,它是必需的。否则该方法将不是泛型方法,编译器将搜索一个名为t的具体类。对于我的方法公共堆栈readAll(Path aPath)
,我不需要
,因为它是通配符,对吗?只有当它是公共堆栈readAll(Path aPath)
时,我才需要
确定我将更改应用于所有构造函数和方法,并且现在将其标记为errorsOh。因此,您正在实现自己的堆栈类。我错过了。为什么不使用标准集合类?无论如何,我不知道你的堆栈是如何实现的,我也不知道错误是什么。。。但是我怀疑您的类已经是泛型的,所以您不需要参数化push方法。