Java:使用时间单位将秒转换为日、时、分和秒
我使用TimeStamp类将秒转换为天、小时、分钟、秒。我使用了以下代码Java:使用时间单位将秒转换为日、时、分和秒,java,datetime,time,Java,Datetime,Time,我使用TimeStamp类将秒转换为天、小时、分钟、秒。我使用了以下代码 public static void calculateTime(long seconds) { int day = (int)TimeUnit.SECONDS.toDays(seconds); long hours = TimeUnit.SECONDS.toHours(seconds) - TimeUnit.SECONDS.toHours(TimeUnit.SECONDS.
public static void calculateTime(long seconds) {
int day = (int)TimeUnit.SECONDS.toDays(seconds);
long hours = TimeUnit.SECONDS.toHours(seconds) - TimeUnit.SECONDS.toHours(TimeUnit.SECONDS.toDays(seconds));
long minute = TimeUnit.SECONDS.toMinutes(seconds) - TimeUnit.SECONDS.toMinutes(TimeUnit.SECONDS.toHours(seconds));
long second = TimeUnit.SECONDS.toSeconds(seconds) - TimeUnit.SECONDS.toSeconds(TimeUnit.SECONDS.toMinutes(seconds));
System.out.println("Day " + day + " Hour " + hours + " Minute " + minute + " Seconds " + second);
}
但我没有得到正确的结果。
例如,当我将此方法称为calculateTime(3600)
时,它将结果显示为day0hour 1minute60seconds3540
,而不是day0hour 1minute0seconds0
我的逻辑有什么问题?请帮帮我 应该是这样的
int day = (int)TimeUnit.SECONDS.toDays(seconds);
long hours = TimeUnit.SECONDS.toHours(seconds) - (day *24);
long minute = TimeUnit.SECONDS.toMinutes(seconds) - (TimeUnit.SECONDS.toHours(seconds)* 60);
long second = TimeUnit.SECONDS.toSeconds(seconds) - (TimeUnit.SECONDS.toMinutes(seconds) *60);
编辑
说明:
下面是我创建的代码:(3600秒显示“天:0小时:1分钟:0秒:0”)
公共类时间转换
{
公共静态void main(字符串[]args)
{
温度=0,i;
fsec=3600;
//好几天
如果(fsec>=86400)
{
温度=fsec/86400;
d=温度;
对于(i=1;i=3600)
{
温度=fsec/3600;
h=温度;
对于(i=1;i=60)
{
温度=fsec/60;
m=温度;
对于(i=1;i=1)
{
s=fsec;
}
其他的
{
s=0;
}
系统输出打印项次(“天:+d+”小时:+h+”分钟:+m+”秒:+s);
}
}
希望它能回答您的问题。试试这个
public static void calculateTime(long seconds) {
int day = (int)TimeUnit.SECONDS.toDays(seconds);
long hours = TimeUnit.SECONDS.toHours(seconds) ;
long tempSec = seconds - (TimeUnit.HOURS.toSeconds(hours) );
System.out.println("after hours calculation "+ tempSec);
long minute = TimeUnit.SECONDS.toMinutes(tempSec);
if(tempSec > TimeUnit.MINUTES.toSeconds(minute)){
tempSec = tempSec - (TimeUnit.MINUTES.toSeconds(minute) );
}else{
tempSec = TimeUnit.MINUTES.toSeconds(minute) - tempSec;
}
System.out.println("after min calculation "+ tempSec);
long second = TimeUnit.SECONDS.toSeconds(tempSec) ;
System.out.println("Day " + day + " Hour " + hours + " Minute " + minute + " Seconds " + second);
}
您可以这样做,只使用
时间单位
:
public static void calculateTime(long seconds) {
int day = (int) TimeUnit.SECONDS.toDays(seconds);
long hours = TimeUnit.SECONDS.toHours(seconds) -
TimeUnit.DAYS.toHours(day);
long minute = TimeUnit.SECONDS.toMinutes(seconds) -
TimeUnit.DAYS.toMinutes(day) -
TimeUnit.HOURS.toMinutes(hours);
long second = TimeUnit.SECONDS.toSeconds(seconds) -
TimeUnit.DAYS.toSeconds(day) -
TimeUnit.HOURS.toSeconds(hours) -
TimeUnit.MINUTES.toSeconds(minute);
System.out.println("Day " + day + " Hour " + hours + " Minute " + minute + " Seconds " + second);
}
或者稍微短一点,但可能不那么直观
public static void calculateTime(long seconds) {
int day = (int) TimeUnit.SECONDS.toDays(seconds);
long hours = TimeUnit.SECONDS.toHours(seconds) -
TimeUnit.DAYS.toHours(day);
long minute = TimeUnit.SECONDS.toMinutes(seconds) -
TimeUnit.HOURS.toMinutes(TimeUnit.SECONDS.toHours(seconds));
long second = TimeUnit.SECONDS.toSeconds(seconds) -
TimeUnit.MINUTES.toSeconds(TimeUnit.SECONDS.toMinutes(seconds));
System.out.println("Day " + day + " Hour " + hours + " Minute " + minute + " Seconds " + second);
}
简单方法:
public static void calculateTime(long seconds) {
long sec = seconds % 60;
long minutes = seconds % 3600 / 60;
long hours = seconds % 86400 / 3600;
long days = seconds / 86400;
System.out.println("Day " + days + " Hour " + hours + " Minute " + minutes + " Seconds " + sec);
}
晚了,但很有帮助 以00:00:00格式获取时间 这是我的代码:
public static String secondsToString(TimeUnit greatestUnit, long sourceDuration, TimeUnit sourceUnit) {
int ordinal = greatestUnit.ordinal();
if(ordinal<=sourceUnit.ordinal())
return String.format("%02d", sourceDuration);
final long greatestDuration = greatestUnit.convert(sourceDuration, sourceUnit);
final long rest = sourceDuration - sourceUnit.convert(greatestDuration, greatestUnit);
return String.format("%02d:", greatestDuration) + secondsToString(TimeUnit.values()[--ordinal], rest, sourceUnit);
}
函数返回:“00:00:16:40”(天:小时:分钟:秒)
返回:“00:16:40”(天:小时:分钟)
返回:“16:40”(分:秒)很好的尝试。但是我使用的是TimeUnit类,没有得到想要的答案。实际上这是一个很好的答案。一个很好的用例是计算当前和某个未来目标日期之间的剩余时间。只需使用上面的代码创建一个新方法。Calculate
long duration=endDate.getTime()-startDate.getTime();
和long diffinsionds=时间单位。毫秒。到秒(持续时间)
。然后将diffinsectonds
作为参数传递给此新方法。从整数变量列表中删除fsec
。然后删除行fsec=3600;
。或者将fsec
的所有实例替换为diffinsectonds
或者将输入参数命名为long fsec
。干杯。+1谢谢这是一个很好的答案。很抱歉,我有一个选择正确答案的选项。不客气!在有用的答案中添加+1,然后选择你最喜欢的答案作为正确答案似乎是完美的行为。所以基本上你有可变秒的时间戳?那么月和年呢?不鼓励只使用代码的答案。问题是关于使用时间单位。你根本不用。
public static void timeCalculator(){
Scanner input = new Scanner(System.in);
System.out.print("Enter length of time in seconds: ");
int n = input.nextInt();
int nDay = n/86400;
int nHours = (n%86400)/3600;
int nMin = ((n%86400)%3600) /60;
int nSec =(((n%86400)%3600)%60);
System.out.println();
System.out.print("That is "+ nDay+ " day(s),"+nHours+" hour(s), "+nMin+" minute(s), and "+nSec+" second(s). ");
}
/**
* The time in format.
*
* in The Format of 00:00:00
*/
public String getTimeInFormat(long _SECONDS)
{
if(TimeUnit.SECONDS.toHours(_SECONDS)>0)
{
return String.format("%02d:%02d:%02d",
TimeUnit.SECONDS.toHours(_SECONDS),
TimeUnit.SECONDS.toMinutes(_SECONDS) -
TimeUnit.HOURS.toMinutes(TimeUnit.SECONDS.toHours(_SECONDS)),
TimeUnit.SECONDS.toSeconds(_SECONDS) -
TimeUnit.MINUTES.toSeconds(TimeUnit.SECONDS.toMinutes(_SECONDS)));
}
else {
return String.format("%02d:%02d",
TimeUnit.SECONDS.toMinutes(_SECONDS) -
TimeUnit.HOURS.toMinutes(TimeUnit.SECONDS.toHours(_SECONDS)),
TimeUnit.SECONDS.toSeconds(_SECONDS) -
TimeUnit.MINUTES.toSeconds(TimeUnit.SECONDS.toMinutes(_SECONDS)));
}
}
public static String secondsToString(TimeUnit greatestUnit, long sourceDuration, TimeUnit sourceUnit) {
int ordinal = greatestUnit.ordinal();
if(ordinal<=sourceUnit.ordinal())
return String.format("%02d", sourceDuration);
final long greatestDuration = greatestUnit.convert(sourceDuration, sourceUnit);
final long rest = sourceDuration - sourceUnit.convert(greatestDuration, greatestUnit);
return String.format("%02d:", greatestDuration) + secondsToString(TimeUnit.values()[--ordinal], rest, sourceUnit);
}
public static String secondsToStringByLoop(TimeUnit greatestUnit, long sourceDuration, TimeUnit sourceUnit) {
final StringBuffer sb = new StringBuffer();
int ordinal = greatestUnit.ordinal();
while(true){
if(ordinal<=sourceUnit.ordinal()) {
sb.append(String.format("%02d", sourceDuration));
break;
}
final long greatestDuration = greatestUnit.convert(sourceDuration, sourceUnit);
// if(greatestDuration>0 || sb.length()>0)
sb.append(String.format("%02d:", greatestDuration));
sourceDuration -= sourceUnit.convert(greatestDuration, greatestUnit);
greatestUnit = TimeUnit.values()[--ordinal];
};
return sb.toString();
}
String str = secondsToString(TimeUnit.DAYS, 1000, TimeUnit.SECONDS);
str = UnitsConverter.secondsToString(TimeUnit.DAYS, 1000, TimeUnit.MINUTES);
str = UnitsConverter.secondsToString(TimeUnit.MINUTES, 1000, TimeUnit.SECONDS);