Java asyntask期间的Gson解析
我正在做一个请求,该请求给出了以下答案:Java asyntask期间的Gson解析,java,android,parsing,http,gson,Java,Android,Parsing,Http,Gson,我正在做一个请求,该请求给出了以下答案: { "SuL":[ {"IdS":"63","Nam":"Quiz1","Cat":"4097"}, {"IdS":"64","Nam":"6e","Cat":"4099"}, {"IdS":"65","Nam":"CP","Cat":"4100"}, {"IdS":"66","Nam":"CE1","Cat":"4098"} ], "CaL":[ {"Cod":"4097","Lab":"Ca
{
"SuL":[
{"IdS":"63","Nam":"Quiz1","Cat":"4097"},
{"IdS":"64","Nam":"6e","Cat":"4099"},
{"IdS":"65","Nam":"CP","Cat":"4100"},
{"IdS":"66","Nam":"CE1","Cat":"4098"}
],
"CaL":[
{"Cod":"4097","Lab":"Categorie1"},
{"Cod":"4098","Lab":"Math"},
{"Cod":"4099","Lab":"Anglais"},
{"Cod":"4100","Lab":"Géographie"}
]
}
我试图做的是将所有“Lab”值放在一个字符串列表中。
SuL表示服务器上可用对象的列表(我现在不感兴趣),CaL表示类别
这是我的分类课:
public class Categorie {
public String Cod;
public String Lab;
public String getCode() {
return Cod;
}
public void setCode(String code) {
this.Cod = code;
}
public String getName() {
return Lab;
}
public void setName(String name) {
this.Lab = name;
}
}
下面是我的AsyncTask,用于执行请求和Gson解析:
class DownloadQuizCategory extends AsyncTask<String, String, String> {
protected String doInBackground(String...uri) {
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response;
String responseString = null;
ByteArrayOutputStream out;
try {
response = httpclient.execute(new HttpGet(uri[0]));
StatusLine statusLine = response.getStatusLine();
if (statusLine.getStatusCode() == HttpStatus.SC_OK) {
out = new ByteArrayOutputStream();
response.getEntity().writeTo(out);
out.close();
responseString = out.toString();
} else {
// Closes the connection.
response.getEntity().getContent().close();
throw new IOException(statusLine.getReasonPhrase());
}
} catch (ClientProtocolException e) {
// TODO Handle problems..
} catch (IOException e) {
// TODO Handle problems..
}
Log.i("AsyncTask", "responseString : " + responseString);
return responseString;
}
@Override
protected void onPostExecute(String resultat) {
super.onPostExecute(resultat);
//PARSING HERE :(
}
}
你必须反序列化你的Json,试试上面这行。您的JSONArray实验室应该包含您的“实验室”列表
您只需在
分类
类之外创建另一个类。大概是这样的:
public class Response {
private List<Categorie> CaL;
//getter & setter
}
Gson将自动且无提示地将所有值跳过到“SuL”
,因为在响应中没有名为SuL
的属性
编辑:然后,如果您想将所有的“Lab”
vlaues放入列表中,只需执行以下操作(这是Java基础知识…):
List labs=new ArrayList();
for(类别c:response.getCaL()){
添加(c.getName());
}
您能否重新表述您的问题,告诉我们您使用此代码获得了什么输出以及您希望获得什么?我在这里回答另一个有关解析的问题,请查看。非常感谢,效果很好
@Override
protected void onPostExecute(String resultat)
{
super.onPostExecute(resultat);
JSONObject Response = new JSONObject(resultat);
JSONArray Lab= (JSONArray) Response.get("Lab");
System.out.print(Lab);
}
public class Response {
private List<Categorie> CaL;
//getter & setter
}
Gson gson = new Gson();
Response response = gson.fromJson(resultat, Response.class);
List<String> labs = new ArrayList<String>();
for (Categorie c : response.getCaL()) {
labs.add(c.getName());
}