Java 未定义类型为[service.NewsServiceImpl]的符合条件的bean

Java 未定义类型为[service.NewsServiceImpl]的符合条件的bean,java,spring,hibernate,spring-mvc,spring-boot,Java,Spring,Hibernate,Spring Mvc,Spring Boot,我在SpringMVC中有一个错误 Exception in thread "main" org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type [service.NewsServiceImpl] is defined at org.springframework.beans.factory.support.DefaultListableBeanFactory.getB

我在SpringMVC中有一个错误

Exception in thread "main" org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type [service.NewsServiceImpl] is defined
at org.springframework.beans.factory.support.DefaultListableBeanFactory.getBean(DefaultListableBeanFactory.java:373)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.getBean(DefaultListableBeanFactory.java:333)
at org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:1088)
at controller.Testing.main(Testing.java:24)
NewsDAImpl代码为:

@Repository 
public class NewsDAImpl implements NewsDA {

@PersistenceContext
private EntityManager context;  

@Override
public News ... Some Other Codes
我的NewsServiceImpl类:

@Service
@Transactional
public class NewsServiceImpl implements NewsService{

@Autowired
private NewsDAImpl newsDa;

@Override
public News ... Some Other Codes
我编写的控制器具有静态void main,只是为了测试。 在这篇文章中,我写道:

ApplicationContext context = new AnnotationConfigApplicationContext(ProjectConfig.class);
然后我用getBean方法获取新闻服务:

NewsServiceImpl service = context.getBean(NewsServiceImpl.class);
改变


您使用
@Transactional
注释了
NewServiceImpl
,因此默认情况下spring将创建一个代理,该代理当然实现
NewsService
,而不是
NewsServiceImpl

您的
ProjectConfig
如何?永远不要编码到实现-编码到接口,所以不要在impl上使用DI,而是使用接口。
NewsServiceImpl service = context.getBean(NewsServiceImpl.class);
NewsService service = context.getBean(NewsService.class);