JavaEEWebSocket：如何在不接收消息的情况下继续发送数据？

我想要什么？
我正在尝试编写一个应用程序，其中客户端发送一个查询，并基于查询服务器获取twitter流并推送到客户端

我有什么？
我有一个简单的结构，客户机可以连接到服务器，服务器会做出响应

TweetStreamServer

package com.self.tweetstream;

import javax.websocket.OnMessage;
import javax.websocket.server.ServerEndpoint;

@ServerEndpoint("/tweets")
public class TweetStreamServer {
    @OnMessage
    public String tweets(final String message) {
        return message;
    }
}

@ClientEndpoint
public class TweetStreamClient {
    public static CountDownLatch latch;
    public static String response;

    @OnOpen
    public void onOpen(Session session) {
        try{
            session.getBasicRemote().sendText("Hello World!");
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    @OnMessage
    public void printTweets(final String tweet) {
        System.out.println("Tweet:" + tweet);
        response = tweet;
        latch.countDown();
    }
}

@Test
    public void test() throws URISyntaxException, IOException, DeploymentException, InterruptedException {
        System.out.println("URI: " + getEndpointUrl());
        TweetStreamClient.latch = new CountDownLatch(1);
        Session session = connectToServer(TweetStreamClient.class, "tweets");
        assertNotNull(session);
        assertTrue(TweetStreamClient.latch.await(10, TimeUnit.SECONDS));
        assertEquals("Hello World!", TweetStreamClient.response);
    }

TweetStreamClient

package com.self.tweetstream;

import javax.websocket.OnMessage;
import javax.websocket.server.ServerEndpoint;

@ServerEndpoint("/tweets")
public class TweetStreamServer {
    @OnMessage
    public String tweets(final String message) {
        return message;
    }
}

@ClientEndpoint
public class TweetStreamClient {
    public static CountDownLatch latch;
    public static String response;

    @OnOpen
    public void onOpen(Session session) {
        try{
            session.getBasicRemote().sendText("Hello World!");
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    @OnMessage
    public void printTweets(final String tweet) {
        System.out.println("Tweet:" + tweet);
        response = tweet;
        latch.countDown();
    }
}

@Test
    public void test() throws URISyntaxException, IOException, DeploymentException, InterruptedException {
        System.out.println("URI: " + getEndpointUrl());
        TweetStreamClient.latch = new CountDownLatch(1);
        Session session = connectToServer(TweetStreamClient.class, "tweets");
        assertNotNull(session);
        assertTrue(TweetStreamClient.latch.await(10, TimeUnit.SECONDS));
        assertEquals("Hello World!", TweetStreamClient.response);
    }

TweetStreamTest

package com.self.tweetstream;

import javax.websocket.OnMessage;
import javax.websocket.server.ServerEndpoint;

@ServerEndpoint("/tweets")
public class TweetStreamServer {
    @OnMessage
    public String tweets(final String message) {
        return message;
    }
}

@ClientEndpoint
public class TweetStreamClient {
    public static CountDownLatch latch;
    public static String response;

    @OnOpen
    public void onOpen(Session session) {
        try{
            session.getBasicRemote().sendText("Hello World!");
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    @OnMessage
    public void printTweets(final String tweet) {
        System.out.println("Tweet:" + tweet);
        response = tweet;
        latch.countDown();
    }
}

@Test
    public void test() throws URISyntaxException, IOException, DeploymentException, InterruptedException {
        System.out.println("URI: " + getEndpointUrl());
        TweetStreamClient.latch = new CountDownLatch(1);
        Session session = connectToServer(TweetStreamClient.class, "tweets");
        assertNotNull(session);
        assertTrue(TweetStreamClient.latch.await(10, TimeUnit.SECONDS));
        assertEquals("Hello World!", TweetStreamClient.response);
    }

问题
我很困惑，我现在怎么能发送从Twitter收到的连续推文，因为我的服务器方法是API

       @OnMessage
        public String tweets(final String message) {
            return message;
        }  

这意味着它需要一条消息才能返回任何内容

如何将来自Twitter的未来数据发送到客户端？

这对我来说很有效

@OnMessage
public void tweets(final String message, Session client) throws IOException, InterruptedException {
    int i = 0;
    for (Session peer : client.getOpenSessions()) {
        while (i < 10) {
            System.out.println("sending ...");
            peer.getBasicRemote().sendText("Hello");
            Thread.sleep(2000);
            i++;
        }
    }
}

@OnMessage
公共void tweets（最终字符串消息，会话客户端）引发IOException、InterruptedException{
int i=0；
对于（会话对等方：client.getOpenSessions（））{
而（i<10）{
System.out.println（“发送…”）；
peer.getBasicRemote（）.sendText（“你好”）；
《睡眠》（2000年）；
i++；
}
}
}

---

感谢通过他的推文提供帮助：）

请确保将try-catch块放在循环中-当一个会话因某种原因中断时，您不想跳过其他连接的会话。