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Java 大摇大摆的人不';t显示OpenApi codegen正确生成的文档化API_Java_Swagger_Swagger Ui_Openapi_Openapi Generator - Fatal编程技术网

Java 大摇大摆的人不';t显示OpenApi codegen正确生成的文档化API

Java 大摇大摆的人不';t显示OpenApi codegen正确生成的文档化API,java,swagger,swagger-ui,openapi,openapi-generator,Java,Swagger,Swagger Ui,Openapi,Openapi Generator,我正在使用openapi生成器maven插件从YAML文档生成代码 openapi: 3.0.3 info: title: Example API Doc description: Those are example endpoints. termsOfService: https://localhost:8080/termsOfService license: name: No license url: https://localhost:8080/licens

我正在使用openapi生成器maven插件从YAML文档生成代码

openapi: 3.0.3
info:
  title: Example API Doc
  description: Those are example endpoints.
  termsOfService: https://localhost:8080/termsOfService
  license:
    name: No license
    url: https://localhost:8080/license
  version: 1.0-SNAPSHOT
servers:
- url: https://localhost:8080/
- url: http://localhost:8080/
tags:
- name: example
  description: Example Tag
paths:
  /example:
    get:
      tags:
      - example
      summary: Example GET request
      description: Send example GET request
      operationId: exampleGetRequest
      responses:
        200:
          description: Successful operation
          content: {}
        400:
          description: Example Bad Request
          content: {}
        404:
          description: Example Not Found
          content: {}
以下是我如何配置maven插件以生成接口:

<plugin>
  <groupId>org.openapitools</groupId>
  <artifactId>openapi-generator-maven-plugin</artifactId>
  <version>4.1.1</version>
  <configuration>
    <generatorName>spring</generatorName>
    <inputSpec>${project.basedir}/src/main/resources/exampleApi.yaml</inputSpec>
    <apiPackage>com.example.openapi.generated.api</apiPackage>
    <modelPackage>com.example.openapi.generated.models</modelPackage>
    <generateSupportingFiles>false</generateSupportingFiles>
    <output>${project.basedir}</output>
    <configOptions>
      <dateLibrary>java8</dateLibrary>
      <java8>true</java8>
      <interfaceOnly>true</interfaceOnly>
    </configOptions>
  </configuration>
</plugin>

org.openapitools

您好,我也有同样的问题。你找到解决办法了吗?嗨,我不确定它是否解决了问题,因为从那一刻起我改变了很多事情。尝试将实现类注释为
@Controller
,而不是
@RestController
。另外,我的接口现在没有默认方法,所有端点方法声明都是“抽象的”,正如您在接口中所说的那样。如果它对您有效,请在这里为其他人提供答案。您好,如果我将实现类注释为@Controller swagger ui显示“规范中未定义任何操作”。我将两个设置“interfaceOnly”和“skipDefaultInterface”都设置为“true”。嗨,我遇到了同样的问题。你找到解决办法了吗?嗨,我不确定它是否解决了问题,因为从那一刻起我改变了很多事情。尝试将实现类注释为
@Controller
,而不是
@RestController
。另外,我的接口现在没有默认方法,所有端点方法声明都是“抽象的”,正如您在接口中所说的那样。如果它对您有效,请在这里为其他人提供答案。您好,如果我将实现类注释为@Controller swagger ui显示“规范中未定义任何操作”。我将两个设置“interfaceOnly”和“skipDefaultInterface”都设置为“true”。
@Api(value = "example", description = "the example API")
public interface ExampleApi {

    default Optional<NativeWebRequest> getRequest() {
        return Optional.empty();
    }

    @ApiOperation(value = "Example GET request", nickname = "exampleGetRequest", notes = "Send example GET request", tags = {"example",})
    @ApiResponses(value = {
            @ApiResponse(code = 200, message = "Successful operation"),
            @ApiResponse(code = 400, message = "Example Bad Request"),
            @ApiResponse(code = 404, message = "Example Not Found")})
    @RequestMapping(value = "/example", method = RequestMethod.GET)
    default ResponseEntity<Void> exampleGetRequest() {
        return new ResponseEntity<>(HttpStatus.NOT_IMPLEMENTED);
    }
}
@RestController
public class ExampleApiImpl implements ExampleApi {

    @Override
    public ResponseEntity<Void> exampleGetRequest() {
        return ResponseEntity.ok().build();
    }
}