Java 如何使用EclipseKepler和Apache7创建和运行servlet
我正在制作这个新的servlet:Java 如何使用EclipseKepler和Apache7创建和运行servlet,java,eclipse,servlets,Java,Eclipse,Servlets,我正在制作这个新的servlet: package Servlets; import java.io.IOException; import java.io.PrintWriter; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpSe
package Servlets;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class Hello
*/
public class Hello extends HttpServlet
{
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public Hello()
{
super();
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("It works");
out.close();
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
doGet(request, response);
}
}
这是web-INF中的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>FirstServlet</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>Hello</servlet-name>
<servlet-class>Hello</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Hello</servlet-name>
<url-pattern>/hello</url-pattern>
</servlet-mapping>
</web-app>
第一个servlet
index.html
index.htm
index.jsp
default.html
default.htm
default.jsp
你好
你好
你好
/你好
显示名称和欢迎文件列表标记是在我创建动态web项目时自动生成的。servlet和servlet映射是由我编写的。当我使用Appache7运行项目时,它显示HTTP状态404-/FirstServlet/。我的错误在哪里?1)您可能缺少列出的所有欢迎文件。404是不存在时应该发生的情况
2) 您的servlet映射已损坏。servlet类元素需要一个完全限定的类名,它应该是
Servlets.Hello
,而不仅仅是Hello
。正确映射后,/FirstServlet/hello
将访问您的servlet,匹配映射的URI,然后按名称查找注册的servlet,最后找到应执行的完全限定类。您的servlet位于/FirstServlet/Helloyes下。您的servlet运行包是正确的,但仅当我在java文件上运行时,但是如果我运行整个项目,它会给出相同的错误。好的,我已经从web.xml中删除了display name和welcome file list,还用servlet更改了class元素。您好,现在如果我运行项目,它会显示“HTTP Status 404-/FirstServlet/”,如果我运行java文件,它会工作。我想在运行项目时运行它。@user3430773您是否尝试过我对@nitind的回答和第2点的评论?