Java 为什么会抛出IndexOutOfBoundsException？

为什么在下面的代码段中抛出IndexOutOfBoundsException？ 我似乎不明白它为什么会被扔出去

    import java.util.*;
    public class PrimeNumbers {

        //Printing all prime numbers less than 600 using 'Sieve Method'
        final static int SIZE = 600;
        static ArrayList<Integer> numbers = new ArrayList<Integer>(SIZE);


        public static void populateList(ArrayList<Integer> arraylist){
            for(int i=0; i<SIZE; i++){
                arraylist.add(i, i);
            }
        }

        public static void filterMultiples(ArrayList<Integer> arraylist){
            for(int i=0; i<SIZE; i++){
                if(arraylist.get(i)%2==0 || arraylist.get(i)%3==0 || arraylist.get(i)%5==0){
                    arraylist.remove(i);
                    }
                }
            }

        public static void main(String[] args){
            populateList(numbers);
            filterMultiples(numbers);
            System.out.println(numbers);

        }
    }

---

for（int i=0；i此块中存在错误：

       for(int i=0; i<SIZE; i++){
            if(arraylist.get(i)%2==0 || arraylist.get(i)%3==0 || arraylist.get(i)%5==0){
                arraylist.remove(i);
                }
            }
        }

for（int i=0；i
for(int i=0; i<SIZE; i++){
    if(arraylist.get(i)%2==0 || arraylist.get(i)%3==0 || arraylist.get(i)%5==0){
        arraylist.remove(i);
        }
    }
}

       for(int i=0; i<SIZE; i++){
            if(arraylist.get(i)%2==0 || arraylist.get(i)%3==0 || arraylist.get(i)%5==0){
                arraylist.remove(i);
                }
            }
        }

    for (Iterator<Integer> iterator = numbers.iterator(); iterator.hasNext();) {
        int number = iterator.next();
        if (number % 2 == 0 || number % 3 == 0
                || number % 5 == 0) {
            iterator.remove();
        }
    }