Java 昆德拉铸串“；1“；到查询中的整数1

我得到了下一个例外：

Caused by: com.impetus.kundera.KunderaException: com.datastax.driver.core.exceptions.InvalidQueryException: Invalid INTEGER constant (1) for promo_code_id of type ascii
    at com.impetus.kundera.client.cassandra.dsdriver.DSClient.execute(DSClient.java:510) [kundera-cassandra-ds-driver.jar:]
    at com.impetus.kundera.client.cassandra.dsdriver.DSClient.executeQuery(DSClient.java:415) [kundera-cassandra-ds-driver.jar:]
    at com.impetus.client.cassandra.query.CassQuery.recursivelyPopulateEntities(CassQuery.java:245) [kundera-cassandra.jar:]
    at com.impetus.kundera.query.QueryImpl.fetch(QueryImpl.java:1266) [kundera-core.jar:]
    at com.impetus.kundera.query.QueryImpl.getResultList(QueryImpl.java:187) [kundera-core.jar:]
    at com.impetus.kundera.query.KunderaTypedQuery.getResultList(KunderaTypedQuery.java:250) [kundera-core.jar:]

在执行下一个代码块期间：

public List<ActivatedPromoCode> findRegistrationPromoBetween(List<String> promoCodeIds, Date startDate, Date endDate)
            throws DAOException {
        try {
            if (promoCodeIds == null ) return null;

            TypedQuery<ActivatedPromoCode> query = getEM().createQuery(
                    "select apc from ActivatedPromoCode apc where apc.promoCodeId in ?1 " +
                            "and apc.isRegistrationPromo = true " +
                            "and apc.activationTimestamp > ?2 and apc.activationTimestamp < ?3",
                    ActivatedPromoCode.class);
            query.setParameter(1, promoCodeIds);
            query.setParameter(2, startDate);
            query.setParameter(3, endDate);

            try {
                return query.getResultList();
            } catch (NoResultException e) {
                return null;
            }
        } catch (Exception e) {
            throw new DAOException("Search activated promo codes activated during registration", e);
        }

类别声明：

@Entity
@Table(name = "activated_promo_code")
public class ActivatedPromoCode {

    @Id
    @GeneratedValue
    @Column(name = "id", nullable = false, unique = true)
    private String id;

    @Column(name = "promo_code_id")
    private String promoCodeId;

    @Column(name = "code")
    private String code;

    @Column(name = "target_id")
    private String targetId;

    @Column(name = "activation_timestamp")
    private Date activationTimestamp;

    @Column(name = "current_target_bonus")
    private Integer currentTargetBonus;

    @Column(name = "is_active")
    private Boolean isActive;

    @Column(name = "used_counts")
    private Integer usedCounts;

    @Column(name = "is_registration_promo")
    private Boolean isRegistrationPromo;

    // Getters and setters
}

有人能解释为什么昆德拉把字符串“1”转换成整数1吗？我怎样才能避免呢

---

谢谢

昆德拉不会将字符串转换为整数。表-实体的映射不正确（表中有复合键，但实体中未定义复合键）

为了使用昆德拉在Cassandra中使用复合键，您需要将其定义为

嵌入ID

可嵌入类：-

@Embeddable
public class Myid
{
    @Column(name = "id", nullable = false, unique = true)
    private String id;

    @Column(name = "promo_code_id")
    private String promoCodeId;

    //setters and getters
}

实体类：-

@Entity
@Table(name = "activated_promo_code")
public class ActivatedPromoCode {

@EmbeddedId
private Myid myid;           //EmbeddedId

@Column(name = "code")
private String code;

@Column(name = "target_id")
private String targetId;

@Column(name = "activation_timestamp")
private Date activationTimestamp;

@Column(name = "current_target_bonus")
private Integer currentTargetBonus;

@Column(name = "is_active")
private Boolean isActive;

@Column(name = "used_counts")
private Integer usedCounts;

@Column(name = "is_registration_promo")
private Boolean isRegistrationPromo;

// Getters and setters
}

并将

TypedQuery

中的

where apc.promoCodeId

替换为

where apc.myid.promoCodeId

---

您可以参考有关复合键的更多信息。

因此，问题不在昆德拉，而是在模型类定义中。类包含映射到一个数据库字段的2个字段。有时字段promo_code_id转换为字符串，我们得到了正确的工作，有时它转换为PromoCode，我们得到了错误的工作。 因此，解决方案是使用更合适的模式定义

与讨论人员聊天：

---

您的实体中

promoCodeId

字段的数据类型是什么？您能否共享您的实体（

ActivatedPromoCode

）定义？DB中的数据类型：class中的ascii数据类型：Strings在复合键中没有交易，当我使用由两个字段组成的复合键和使用简单的一个字段键时，会出现问题。如果您告诉昆德拉没有转换类型，为什么查询看起来像

SELECT*FROM“activated_promo_code”，其中（1）中的“promo_code_id”和“is_registration_promo”=true和“activation_timestamp”>'1427857200000'和“activation_timestamp”<'1428116400000'LIMIT 100允许在将字符串值插入IN运算符后进行筛选

？是的，您是对的，不应该发生这种情况。我也尝试过同样的方法，但效果很好。您使用的是哪个版本的昆德拉？最新版本为2.16，在对Cassandra的查询中，您在运算符中得到了字符串值“1”，如

in（'1'）

？您的实体是否包含任何关系？是的。当前类有

@ManyToOne（cascade=CascadeType.ALL，fetch=FetchType.EAGER）@JoinColumn（name=“promo\u code\u id”，referencedColumnName=“id”）私有PromoCode PromoCode
@Embeddable
public class Myid
{
    @Column(name = "id", nullable = false, unique = true)
    private String id;

    @Column(name = "promo_code_id")
    private String promoCodeId;

    //setters and getters
}

@Entity
@Table(name = "activated_promo_code")
public class ActivatedPromoCode {

@EmbeddedId
private Myid myid;           //EmbeddedId

@Column(name = "code")
private String code;

@Column(name = "target_id")
private String targetId;

@Column(name = "activation_timestamp")
private Date activationTimestamp;

@Column(name = "current_target_bonus")
private Integer currentTargetBonus;

@Column(name = "is_active")
private Boolean isActive;

@Column(name = "used_counts")
private Integer usedCounts;

@Column(name = "is_registration_promo")
private Boolean isRegistrationPromo;

// Getters and setters
}