Java 如何使用CloudFileClient从azure文件存储中获取文件内容(字节数组)?
我在azure上有文件存储,我正在成功连接和遍历这些目录。但我无法获取文件的内容。为了获取FileClientReference,我使用以下代码:Java 如何使用CloudFileClient从azure文件存储中获取文件内容(字节数组)?,java,azure,azure-files,Java,Azure,Azure Files,我在azure上有文件存储,我正在成功连接和遍历这些目录。但我无法获取文件的内容。为了获取FileClientReference,我使用以下代码: public CloudFileClient getFileClientReference() { log.info("Logging into azure file storage:"); CloudFileClient cloudFileClient = null; CloudStorageAccou
public CloudFileClient getFileClientReference() {
log.info("Logging into azure file storage:");
CloudFileClient cloudFileClient = null;
CloudStorageAccount storageAccount;
try {
storageAccount = CloudStorageAccount.parse(storageConnectionString);
cloudFileClient = storageAccount.createCloudFileClient();
} catch (IllegalArgumentException | URISyntaxException e) {
log.error("Connection string specifies an invalid URI.");
log.error("Please confirm the connection string is in the Azure connection string format.");
throw new AzureFileStorageNotAvailableException("Failed to login to azure file storage.");
} catch (InvalidKeyException e) {
log.error("Connection string specifies an invalid key.");
log.error("Please confirm the AccountName and AccountKey in the connection string are valid.");
throw new AzureFileStorageNotAvailableException("Failed to login to azure file storage.");
}
log.info("Logged into azure file storage.");
return cloudFileClient;
}
fileClientReference.getShareReference(document.getPath())
.getRootDirectoryReference().getFileReference(document.getFileName()).openRead();
我已经测试了这段代码,它运行良好。我用它来遍历所有目录。
我现在要做的是让给定的url获取文件内容。我用来获取url的代码是:
Iterable<ListFileItem> results = rootDir.listFilesAndDirectories();
for (ListFileItem item : results) {
boolean isDirectory = item.getClass() == CloudFileDirectory.class;
final String uri = item.getUri().toString();
if (isDirectory && uri.contains("myPath")) {
traverseDirectories((CloudFileDirectory) item, azureFiles);
} else if (!isDirectory) {
handleFile(item, uri, azureFiles);
}
}
其中document.getPath()
将指向上述路径,document.getFileName()
将给出文件名:somepdf.pdf
调用此方法时,我收到一个错误:
Method threw 'com.microsoft.azure.storage.StorageException' exception.
The specifed resource name contains invalid characters.
pdf是可以的,但我不知道如何访问pdf和获取内容。如果有人也在尝试如何做到这一点,这里有一个答案: 首先,在调用该方法时:
fileClientReference.getShareReference(document.getPath())
路径应采用以下格式:
/folder1/folder2/folder3/
没有来自azure的前缀:
没有我以前尝试过的文件名。我通过调用字符串上的replaceAll来解析它
在一种方法中,我有:
CloudFile cloudFile;
try {
String fileLocation = document.getPath().replaceAll(AZURE_FILE_STORAGE_URL_PREFIX + "|" + document.getFileName(), "");
final CloudFileShare fileShare = fileClientReference.getShareReference(fileLocation);
cloudFile = fileShare.getRootDirectoryReference().getFileReference(document.getFileName());
return new AzureFile(document.getFileName(), readFileContent(cloudFile));
} catch (URISyntaxException | StorageException e) {
log.error("Failed to retrieve file for document with id: {}", documentId, e);
throw new AzureFileStorageNotAvailableException("Failed to retrieve file");
}
readFileContent方法是:
private ByteArrayResource readFileContent(CloudFile cloudFile) {
try (final FileInputStream fileInputStream = cloudFile.openRead()) {
final byte[] content = fileInputStream.readAllBytes();
return new ByteArrayResource(content);
} catch (StorageException | IOException e) {
log.error("Failed to read file content", e);
throw new AzureFileStorageNotAvailableException("Failed to read file");
}
}
AzureFile是我自己创建的实体,因为我需要传递文件名和内容:
@Data
@AllArgsConstructor
public class AzureFile {
private String fileName;
private ByteArrayResource content;
}
当我们调用
getShareReference
方法时,我们只需要提供共享名:@JimXu这是文件名吗?