Java 如何使用Saxon XSLT转换每个xml节点？

如何使用Saxon xslt转换库将包含多个节点的xml文件转换为纯csv字符串？意思是，我希望Saxon将每个员工条目连接为csv，并将它们放在一起

这是saxon设置，但我不知道如何无法使用它转换输入xml文件：

    //false = does not required a feature from a licensed version of Saxon.
    Processor processor = new Processor(false);

    XsltCompiler compiler = processor.newXsltCompiler();
    compiler.compile(new StreamSource("transformation.xslt"));

    Serializer serializer = processor.newSerializer();
    serializer.setOutputProperty(Serializer.Property.OMIT_XML_DECLARATION, "yes");

    //TODO 
    //String result = serializer...serializeNodeToString();

我想转换以下xml：

<employees stage="test">
   <employee>
      <details>
         <name>Joe</name>
         <age>34</age>
      </details>
      <address>
         <street>test</street>
         <nr>12</nr>
      </address>
   </employee>
   <employee>
      <address>....</address>
      <details>
         <!-- note the changed order of elements! -->
         <age>24</age>
         <name>Sam</name>
      </details>
   </employee>
</employees>

Xslt可能类似于：

<xsl:transform version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="text"/>
  <xsl:template match="employee">
    <xsl:value-of select="name"/>
    <xsl:value-of select="age"/>
  </xsl:template>
</xsl:transform>

---

XSLT模板可以修改如下。可根据所需顺序选择元件

<xsl:template match="employee">
    <xsl:value-of select="ancestor::employees/@stage, details/name, details/age, address/street, address/nr" separator=", " />
    <xsl:text>&#xA;</xsl:text>
</xsl:template>

为了在Java中使用XSLT转换XML，我大部分时间使用以下代码片段。此方法将转换后的XML作为字符串返回。所需的库是saxon9he.jar。您可能必须升级库版本才能与XSLT 3.0一起使用

public static String transformXML(String xml, InputStream xslFile) {
    String outputXML = null;
    try {
        System.setProperty("javax.xml.transform.TransformerFactory", "net.sf.saxon.TransformerFactoryImpl");
        TransformerFactory factory = TransformerFactory.newInstance();
        Transformer transformer = factory.newTransformer(new StreamSource(xslFile));
        Source xmlStream = new StreamSource(new StringReader(xml));
        StringWriter writer = new StringWriter();
        Result result = new StreamResult(writer);
        transformer.transform(xmlStream, result);
        outputXML = writer.getBuffer().toString();
    } catch (TransformerConfigurationException tce) {
        tce.printStackTrace();
    } catch (TransformerException te) {
        te.printStackTrace();
    }
    return outputXML;
}

---

这里有两个问题吗？如何使用Saxon9和Java来执行XSLT转换，以及如何为特定任务编写XSLT样式表？至于XSLT任务，第二个address元素是否不包含任何子元素，而只包含文本。。。。？什么定义了CSV的顺序？两者都包含，不包含更多的子元素。顺序应该由属性的顺序来设置。是和。我只是懒得再复制地址详细信息。在使用现有xslt时，我最好需要帮助，了解如何正确地将xml转换为字符串java代码。

test, Joe, 34, test, 12
test, Sam, 24, test1, 123

public static String transformXML(String xml, InputStream xslFile) {
    String outputXML = null;
    try {
        System.setProperty("javax.xml.transform.TransformerFactory", "net.sf.saxon.TransformerFactoryImpl");
        TransformerFactory factory = TransformerFactory.newInstance();
        Transformer transformer = factory.newTransformer(new StreamSource(xslFile));
        Source xmlStream = new StreamSource(new StringReader(xml));
        StringWriter writer = new StringWriter();
        Result result = new StreamResult(writer);
        transformer.transform(xmlStream, result);
        outputXML = writer.getBuffer().toString();
    } catch (TransformerConfigurationException tce) {
        tce.printStackTrace();
    } catch (TransformerException te) {
        te.printStackTrace();
    }
    return outputXML;
}