Java ObjectInputStream返回ObjectStreamClass

我有点麻烦。以下行在第一次读取时在客户端上执行良好，但在第二次读取时失败

java:72

messagetask=（Message）in.readObject（）

中是一个私有ObjectInputStream。收到的异常如下所示

Exception in thread "main" java.lang.ClassCastException: java.io.ObjectStreamClass cannot be cast to parallelprogramming.Message
    at parallelprogramming.WorkerNode.receiveTask(WorkerNode.java:72)
    at parallelprogramming.WorkerNode.computeTillEndOfWork(WorkerNode.java:139)
    at parallelprogramming.Worker.main(Worker.java:24)
Nov 15, 2014 11:07:15 PM parallelprogramming.WorkerNode receiveTask
SEVERE: null
java.io.StreamCorruptedException: invalid type code: 00
    at java.io.ObjectInputStream.readObject0(ObjectInputStream.java:1379)
    at java.io.ObjectInputStream.readObject(ObjectInputStream.java:371)
    at parallelprogramming.WorkerNode.receiveTask(WorkerNode.java:72)
    at parallelprogramming.WorkerNode.lambda$startListeningForWork$0(WorkerNode.java:59)
    at parallelprogramming.WorkerNode$$Lambda$1/798154996.run(Unknown Source)
    at java.lang.Thread.run(Thread.java:745)

Exception in thread "WorkListener" java.lang.ClassCastException: parallelprogramming.MatMulTask cannot be cast to parallelprogramming.Message
    at parallelprogramming.WorkerNode.receiveTask(WorkerNode.java:72)
    at parallelprogramming.WorkerNode.lambda$startListeningForWork$0(WorkerNode.java:59)
    at parallelprogramming.WorkerNode$$Lambda$1/798154996.run(Unknown Source)
    at java.lang.Thread.run(Thread.java:745)
Java Result: 1

消息具有以下结构

public class Message implements IMessage{
    private final MessageType type;
    private final Object payload;

IMessage扩展了可序列化的功能。我在客户端和服务器端使用相同的ObjectInputStream和ObjectOutputStream。我试着四处寻找，但没有成功。还有人发现类似的东西吗

编辑2：
向工作者发送消息的代码：

private final Map<String, WorkerConn> nodes;
//nodes initialized in constructor
private void sendTaskToNode(ITask task, String node) {
        if(task == null){
            return;
        }        
        try{   
            Message msg = new Message(MessageType.task, task);
            nodes.get(node).sendObject(msg);

            nodes.get(node).incrementworkCount();

            System.out.println("Sent work to "+node);
        } catch (IOException ex) {
            Logger.getLogger(MasterNode.class.getName()).log(Level.SEVERE, null, ex);
        }
    }

接收有关Worker的消息的部分：

public void receiveTask() throws NotConnectedToMasterException {
        try {
            Message task = (Message) in.readObject();
            if(task.getMessageType() == MessageType.task){
                tasks.add((ITask) task.getPayload());
                System.out.println("Received Task");
            }else if(task.getMessageType() == MessageType.endOfWork){
                ITask t = new AbstractTask() {

                    @Override
                    public Object call() throws Exception {
                        throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
                    }
                };
                t.setDeathPill();
                tasks.add(t);
                System.out.println("added deathpill");
            }else{
                System.out.println("Received "+task.getMessageType());
            }
        } catch(EOFException ex) {
            return;
        } catch (IOException ex) {
            Logger.getLogger(WorkerNode.class.getName()).log(Level.SEVERE, null, ex);
            return;
        } catch (ClassNotFoundException ex) {
            Logger.getLogger(WorkerNode.class.getName()).log(Level.SEVERE, null, ex);
        }
    }

编辑：
我发现了我的问题。我创建了一个线程来监听传入的任务，读取输入流，并且在任务队列为空时从主线程读取相同的输入流。在工作节点中：

private void startListeningForWork(){
        workListener = new Thread(() -> {
            while(!master.isClosed()){
                try {
                    receiveTask();
                } catch (NotConnectedToMasterException ex) {
                    break;
                }
            }
        });
        workListener.setName("WorkListener");
        workListener.start();
    }

private void startListeningForWork(){
        workListener = new Thread(() -> {
            while(!master.isClosed()){
                try {
                    receiveTask();
                } catch (NotConnectedToMasterException ex) {
                    break;
                }
            }
        });
        workListener.setName("WorkListener");
        workListener.start();
    }

及

这导致一个线程在另一个线程之前读取对象，并将事情搞砸。
发现了我的问题。我创建了一个线程来监听传入的任务，读取输入流，并且在任务队列为空时从主线程读取相同的输入流。在工作节点中：

private void startListeningForWork(){
        workListener = new Thread(() -> {
            while(!master.isClosed()){
                try {
                    receiveTask();
                } catch (NotConnectedToMasterException ex) {
                    break;
                }
            }
        });
        workListener.setName("WorkListener");
        workListener.start();
    }

private void startListeningForWork(){
        workListener = new Thread(() -> {
            while(!master.isClosed()){
                try {
                    receiveTask();
                } catch (NotConnectedToMasterException ex) {
                    break;
                }
            }
        });
        workListener.setName("WorkListener");
        workListener.start();
    }

及

这导致其中一个线程在另一个线程之前读取对象，并将事情搞砸。
显示您在哪里发送数据，以及将整个代码上载到github。我很抱歉，但我不会在所有这些文件中查找与特定的
readObject
语句相关的
writeObject
语句（特别是因为我在打电话）。至少告诉我哪一类在哪一个包裹里对那件事感到担忧。这里发送的消息没有详细说明，但我很确定您有一些同步问题。WorkerNode以线程不安全的方式使用节点映射。我没有完全分析worker，但我猜测您没有正确地同步对流的访问。正如@jtahlborn预测的那样。是的：）在我找到它之前调试了每一行：（java需要更好地解释这类东西的异常：p或更好地处理竞争
while(!task.isDeathPill()){
            try {                
                results.addToResult(task.call());
                sendACKtoMaster();                
                task = tasks.remove();
            } catch (Exception ex) {
                try {
                    receiveTask();
                } catch (NotConnectedToMasterException ex1) {
                    Logger.getLogger(WorkerNode.class.getName()).log(Level.SEVERE, null, ex1);
                    break;
                }
            }   
        }